[Solved] a word should not start with a digit in Java [closed]
string.matches(“^([A-Za-z’\”][A-Za-z0-9_’\”]* *)+$”) Visualization 1 solved a word should not start with a digit in Java [closed]
string.matches(“^([A-Za-z’\”][A-Za-z0-9_’\”]* *)+$”) Visualization 1 solved a word should not start with a digit in Java [closed]
This is the do-while equivalent of your program. In do while the code inside the {} block executed at least once before checking the condition. And the condition is checked after execution of that block. For Complete Tutorial On do-while loop, refer this link Structure: do{ //do here }while(booleanExpression); This is your do-while equivalent: See … Read more
You can do this: public void greaterCounter(List<Integer> input){ for (Integer i : input){ Integer count = 0; for (Integer j : input){ if (i < j) count++; } System.out.print(i+”,”+count+” “); } } 2 solved How to get count of number elements which are greater than current element in an arraylist [closed]
For simple methods that do not have many checks on the Boolean conditions, it’s usually fine to simply return true or false. boolean methodName(..arguments) { return <checkCondition> } The above snippet is a reduction of your code’s intent (I say intent because yours will always return false). For more complex functions, a common rule of … Read more
There doesn’t appear to be a problem. Java understands hexadecimal notation: it’s okay to write eg = new CommandAPU(new byte[] {(byte)0x80, (byte)0xCA, (byte)0x9F, 0x7F, 0x00}); Your problem is probably the colon : Colons are used for “labeling” code, so that the JVM can go to that point and keep running. That is, because eg is … Read more
Parameters allows a method to have more flexibility. Sometimes it is necessary to run a method but with different arguments, this is where parameters become handy. For Example (Clarifying): public void calcTotal() { int firstNum= 1; int secondNum=2; System.out.println(firstNum+secondNum); //when we run calcTotal() //output= 3 } This method would correctly print the sum of the … Read more
Try this code. import java.security.MessageDigest; public class Test { String code = null; String encrypted = null; private String getString(byte[] bytes) { StringBuffer sb = new StringBuffer(); for (int i = 0; i < bytes.length; i++) { byte b = bytes[i]; sb.append(0xFF & b); } return sb.toString(); } public String encrypt(String source) { try { … Read more
encryText =+ text; can be interpreted as encryText = +text; // positive(text) assigned to encryText and encryText += text; can be interpreted as encryText = encryText + text; // encryText is added with text and assigned back to encryText positive(text) – means a positive integer. You’re just explicity specifying the sign here. Usually, the positive … Read more
Mastering Regular Expressions (Third Edition) gives a pattern that will validate an IPv4 address, having four dot-separated integers in the range 0-255: ^(?:[01]?\d\d?|2[0-4]\d|25[0-5])\. (?:[01]?\d\d?|2[0-4]\d|25[0-5])\. (?:[01]?\d\d?|2[0-4]\d|25[0-5])\. (?:[01]?\d\d?|2[0-4]\d|25[0-5])$ Modifying that to find (rather than validate) an IP, to exclude things that look like IPs turning up within longer strings of dotted digits, and escape backslashes for Java … Read more
I love this library for scraping the internets http://jsoup.org/. I had a parser up and running in about 30 mins and have only been writing java in my spare time for 3 months. solved Extracting images from a webpage under a specific tag
You know that your long that represents the change in time is in milliseconds (assuming both the original message created timestamp and the current timestamp were both created via System.currentTimeMillis()). You can then use simple math to convert milliseconds to minutes. 1,000 milliseconds = 1 second, so 60,000 = 1 minute. Where exactly were you … Read more
I assume your actual code looks like this: if (preconditionflag.equals(“skip”)){ System.out.println(“Skipping this testcase due to earlier testcase failed”); flag = “skip”; } else { flag = “pass”; } If not, the answer to your question is already no, because you can’t return from a method in one part and not return from a method in … Read more
Try with int probability = x / 1000; // 1/100 of the value to get an probability in percent (integer) or float probably = x / 100000F; //F for a `float` double probability = x / 100000.0; //a decimal without a F is a `double` Without that, this can’t work : float probably = x … Read more
How to print digits in ascending order from 1 to n using recursion ,where n is given in the parameter of that function [closed] solved How to print digits in ascending order from 1 to n using recursion ,where n is given in the parameter of that function [closed]
public static void main(String[] args) { int n = 8; //set anything here for (int even = 2, odd = 1;even<=n;even+=2,odd+=2){ System.out.print(even+” “+odd+” “); } } 2 solved How I print the following sequence of numbers using for loop in java [closed]