The storing of data from a JSP scriptlet should be pretty straight forward just like you have it. var id=<%=ctx.getAttribute(“id”)%> Although I would recommend you to be careful with the returning data, if it isn’t a number for sure, then you must put it between quotes just to be sure the JS doesn’t break. For … Read more
You used to have str.split(“,”); and split() is a void method. It doesn’t alter str. you could fix it by replacing str.split(“,”) with: str = str.split(“,”), or you could put it all on one line like: while ((str = br1.readLine()) != null) userstr.add(str.split(“,”)[0]); 2 solved How can I separate a single String into two parts? … Read more
You basically need to compare a with both b and c (using Math.abs(a-b) and using Math.abs(a-c)) and then check if the other values differ by at least 2. Something like this: public static boolean closeFar(int a, int b, int c) { return ( (Math.abs(a-b) == 1 && (Math.abs(a-c) >= 2 && Math.abs(b-c) >= 2) || … Read more
The difference between the two elements in a column is 9: a[i][j] = a[i-1][j] + 9, thus the code may be modified as: public static void main(String args[]) { int array[][] = new int[6][5]; // initialize the first row array[0] = new int[] {1, 2, 3, 5, 7}; // print the first row System.out.println(Arrays.toString(array[0])); for … Read more
If you want to update your JVM, uninstall the current one and install the latest version. (Actually you don’t have to uninstall the previous version, you can use as many versions as you like side by side if you know how to use just the specific version). Depending of what you need JDK or just … Read more
Exception in thread “main” java.lang.ClassCastException: A cannot be cast to java.lang.Comparable This means the version of A you are running is not Comparable. Most likely you have two versions of A or you didn’t build the class correctly. I suggest using an IDE to build you classes and doing a clean build should fix this. … Read more
There’s a pretty simple way to check if an item already exists in the list: Override the equals method. You will have to override the equals method inside your ExampleItem class. I don’t know the contents, ie. code, of your ExampleItem but this is just my guess so I suggest you to change your code … Read more
24 hours in a day, 60 minutes in an hour, 60 seconds in a minute, 1000 milliseconds in a second scheduleAtFixedRate(yourTask, initialDelay, 24 * 60 * 60 * 1000); solved how to use the schedule method
Date d = (new SimpleDateFormat(“yyyy-MM-dd”).parse(“2012-04-30”)); String result = (new SimpleDateFormat(“dd-MMM-yyyy”, Locale.ENGLISH).format(d)); System.out.println(result); 0 solved how to convert “2012-04-30” date into “04-Apr-2012” format [duplicate]
System.exit(int) takes an integer argument, but otherwise you can call it to terminate your program. Why do you want to call your main() method again? It is normally the static entry point to your program. If there’s some code you wish to repeat, I’d suggest putting this in its own method and calling that (from … Read more
It will enter the for loop first when i = 0. Immediately after it will enter the while loop and continue running indefinitely as i will always be 0 and therefore < 3. You perhaps need to deal with j in the break condition of inner loop for avoiding an infinite loop. solved How does … Read more
Since you’re working with arrays and not ArrayList objects, things get a little tedious. The following code runs through the first array, checks if the current String is not the one you don’t want, and increases the counter by one if it has found one you do want. It then creates a new array as … Read more
I think you can go for an approach like this. int clicks = 0; Button checkButton = (Button) findViewById(R.id.check_Button); checkButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { EditText editBox = (EditText) findViewById(R.id.edit_Text); String items = editBox.getText().toString(); if (i == 0) { Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show(); i++; editBox.setText(“”); } else if (i == 1) { Toast.makeText(getApplicationContext(), … Read more
if you want to check the difference between two numbers, you need to subtract them. The result may be negative if the first number is smaller than the second, so you may want to use Math.abs() which will make it positive again. Then you have a positive number that you can check for being between … Read more
List<List<Citizen>> mainList= new ArrayList<>(); You can go with List of List. Also need to consider below points. I recommend using “List” instead of “ArrayList” on the left side when creating list objects. It’s better to pass around the interface “List” because then if later you need to change to using something like Vector (e.g. you … Read more