First, indicate to User the products available and their respective price: int productChoice = 0; int quantity = 0; double totalSum = 0.0; System.out.println(“Welcome To The Mail_Order House.”); System.out.println(“Please select Product Number (1 to 5) you want to buy:\n”); System.out.println(“1) Product Name 1: RM2.98”); System.out.println(“2) Product Name 2: RM4.50”); System.out.println(“3) Product Name 3: RM9.98”); System.out.println(“4) … Read more
The problem was that you initialized some values that caused errors during the first iteration when you check for the smallest number. I added the following condition that will set the smallest number to the current number, but only during the first iteration. if (count2 == 1 || num < smalled ) { smalled = … Read more
int main() { string calculateagain = “yes”; do { //… Your Code cout << “Do you want to calculate again? (yes/no) ” cin >> calculateagain; } while(calculateagain != “no”); return 0; } Important things to note: This is not checked, so user input may be invalid, but the loop will run again. You need to … Read more
Then add this code on your so called something.php 1)Link 1 <a href=”https://stackoverflow.com/questions/16559631/xxx.php?link=1>Link 1 </a> 2) Link 2 <a href=”xxx.php?link=2>Link 2 </a> Then on xxx.php do this <?php if ($_GET[‘link’] == “1”) { echo “hello”; } if ($_GET[‘link’] == “2”) { echo “hi”; } ?> 2 solved Get Session ID of a link and produce … Read more
The first statement compares the variable ‘a’ to ‘1’, and if the variable ‘a’ is equal to ‘1’, then you will execute the block of code enclosed in brackets. Likewise, the first statement also compares the variable ‘b’ to ‘1’ and if equal will execute a block of code. The second expression evaluates two conditions, … Read more
Try using this: if ( “Both”.equals ( s2 ) ) { //Do something } s2 == “Both” will not compare the text in Java. You can also use this to ignore casing: if ( “Both”.equalsIgnoreCase ( s2 ) ) { //Do something } 0 solved Starting an Activity on Condition
Your first if is the problem if((a>b)&&(a>c)) { if(a>d) return a; // what about else? } If your outer condition is true, but the inner condition is false, it will not have any return case. By the way, your method is a very convoluted way to solve this, or at least difficult to read. I … Read more
while True: choice = input (“Do you want to play?”) if choice == “yes” print(“Great!”) break # Go to the game elif choice == “no” print(“Goodbye.”) break # nothing else: print(“Please answer yes or no.”) solved How to end a python program without it going to the next line of code [duplicate]
You can simply invert the condition. Try the snippet below. if ( !((null == riskClass) || (riskClass.equals(“”)) || (riskClass.equals(“repay”))) ){ //do something } 1 solved opposite of if condition [closed]
const unsigned char sample2[] PROGMEM = { 100,96,84,72,60,58,46,34,20,18,4,12,20,38,46,54,62, }; int inPin = 7; void setup() { pinMode(inPin, INPUT_PULLUP); } int lastPin = HIGH; // HIGH means not pressed for Pullup Inputs void loop() { int pin = digitalRead(inPin); if (pin == lastPin) return; if (pin == HIGH) { startPlayback(sample1, sizeof(sample1)); } else { startPlayback(sample2, sizeof(sample2)); … Read more
You can string multiple conditions together in one, such that: If (thing = 1 OrElse thing = 2 OrElse thing = 3 OrElse thing = 4 OrElse thing = 5) End IF However, you could add these values to a whitelist, and do an Any or Contains check. You could of course to a lower … Read more
No, that would be a compilation error since it is parsing as if ((clickedButton == button0) || (button1) || (button2) … and buttons are not booleans. You must do: if (clickedButton == button0 || clickedButton == button1 … But an array would be much cleaner, instead of having nine separate button variables. Then you could … Read more
Trying to work out the requirements, I reckon that what you want is: If the target is Limited(), then fail if either we are larger than the capacity, or if there is not enough space in the target to add our amount So, that would make the condition: if (link.target.Limited() && (link.target.capacity < link.amount || … Read more
You didn’t get the error before, because your error_reporting and/or display_error settings were set too forgiving. Your first snippet is attempting to access a value in an array that might not exist. If it doesn’t PHP always issues a notice. It’s only after the notice has been issued that it can be hushed up (by … Read more
The problem occurs on the price Method not the number, if the user enters 50 , you are checking the matrix seatsArray[][] for available seats : Solution: you need to add a boolean when seat gets reserved so you can set it true and escape the loop which is on the for not the the … Read more