Modify your function and use it like in example below. using System; public class Program { public static double Decode(string a) { return double.Parse(a); } public static void Main() { var decoded = Decode(“2.1”); Console.WriteLine(decoded); } } OUTPUT: 2.1 If you want improve this function read about Double.TryParse. solved Error CS0030: Cannot convert type ‘void’ … Read more
You answered your own question by reading the documentation. What if the item is not in the tree, or has already been removed, will this method raise an exception? And then the documentation: Returns true if this set contained the element So it will return false if the set does not contain the element (“not … Read more
Your first if is the problem if((a>b)&&(a>c)) { if(a>d) return a; // what about else? } If your outer condition is true, but the inner condition is false, it will not have any return case. By the way, your method is a very convoluted way to solve this, or at least difficult to read. I … Read more
You got a bad example. Short answer: never(!) return a pointer from a binary function (operator). Return by value or a std::unique_ptr or std::shared_ptr. Note: The accepted answer in the link of the question changed afterward. 2 solved When should I return pointer to object (not an object) from the operator function?
The void keyword is not an object or a variable, all it does is specify that a method does not return anything. So the following line means that the function will return void (i.e. nothing): public void doSomething() {} Therefore, using the method Log.i() to print nothing is not possible. This method expects two String … Read more
static IEnumerable<int> Number(int number1, int number2){ for(int i=number1; i<=number2; i++) { if(i%2==1) { yield return i; } } } or static int[] Number(int number1, int number2){ var x = new int[number2]; int y = 0; for(int i=number1; i<=number2; i++) { if(i%2==1) { x[y] = i; y++; } } return x; } This is what you … Read more