[Solved] Ruby code doesn’t work [closed]

I checked your codes and found some problems: num_array.reverse.each_with_index { |value , index| if index % 3 == 0 && num_array[index] != 0 num_string = num_string << ones_place[value-1] elsif index % 3 == 0 && value > 0 && num_array[index] != 0 num_string = num_string << other_place[index/3] << ones_place[value-1] elsif index % 3 == 1 … Read more

[Solved] Swift Nested If statements do not compile

It should be like this: func getWeight() -> String { if weightLabel.text == “Weight (lbs)” { if pickerView == heightPicker { let titleRow = height[row] return titleRow } else if pickerView == weightPicker { let titleRow = weight[row] return titleRow } return “” } else if weightLabel.text == “Weight (kgs)” { if pickerView == heightPicker … Read more

[Solved] For/if/else loop has unexpected identifier [closed]

Just about every angle-bracket language I know follows the following conventions: The condition of an if statement normally goes in parenthesis You shouldn’t have a curly brace at the end of turnCard(‘hit5′}; You shouldn’t have a ; at the end of your if-statements(or your for statement) Some languages allow you to use single-quotes like that … Read more

[Solved] Java if statements without brackets creates unexpected behaviour

Because this: if(name.equals(“email_stub”)) if(emailStub == “”) emailStub = results.getString(“text”); else if(name.equals(“fax”)) if(fax == “”) fax = results.getString(“text”); Is actually this: if(name.equals(“email_stub”)) if(emailStub == “”) emailStub = results.getString(“text”); else if(name.equals(“fax”)) if(fax == “”) fax = results.getString(“text”); Without the curly brackets, the else will reference the first if before it. And as @Hovercraft commented: Avoid if(emailStub == … Read more

[Solved] What is the equivalence in scheme for ‘if’? [closed]

It depends. You really should try to narrow you question further with an actual problem in scheme since the answer will depend on what you are trying to do. In idiomatic Scheme most should be done without side effects so you have (if predicate-expression consequent-expression alternative-expression) ;; alternative is optional but should be used anyway. … Read more

[Solved] ELSE IF + do nothing c# [closed]

Since you used pseudo code, I’m going to guess at variable names: if(yCoord <= 300 && yCoord >= -130) { vGauge.YCoord = yCoord; } only set your variable if the yCoord falls within a valid range. solved ELSE IF + do nothing c# [closed]

[Solved] How are variables involved in a for loop’s body if they are not defined? [closed]

In your for loop, the variable result Is created outside of the for loops scope. Essentially, you are just changing the result variable that has already been created. If you attempted to create a new variable within the for loop such as “newResult = base * result”, it would fail if you attempted to use … Read more

[Solved] if-statement gives another result than expected

The if-statements you use are quite straightforward, the only possibility is that $_SESSION[“Member_type”] always is the value “S”. This means that the ‘problem’ is something else. You can easily verify this yourself. Right before you do the if-statement, you place print_r($_SESSION). If you do that, you’ll see the values in the session array. It could … Read more