Here is a method that will do just that. public double[] AverageReverse(double targetAverage, double range) { var r = new Random(); // TODO: Cache it between calls to avoid “why does ny Random class only produce the same numbers?” var n1 = targetAverage – r.NextDouble() * range; var n2 = targetAverage + r.NextDouble() * range; … Read more
The problem is that you’re using new. When you write: variable = new <something>; it means to call the function <something> as an object constructor, e.g. var myObj = new Array; calls Array() as a constructor, and the returned object is assigned to myObj. While this is normally done using named functions, it works exactly … Read more
No code after login.go() will be executed until the GUI is closed – calling login.go() starts the GUI’s event loop, this is where tktiner is checking for events. I would define the function at the top of your code, and then put the line that calls GetNews(usr) on the line before login.go() If the GetNews(usr) … Read more
Correcting compile time errors is not a hard task. Follow error messages and try to find out the problem. I will show you some examples in your code to solve errors. Your code has many error which shows you need practice more in C++. The declaration of showMenu is void showMenu(int &) but you are … Read more
You have two different ints which both happen to have the same name: The global rezultat declared at the top of the file, and the function parameter rezultat in the parameter list for function pop(). You pass the value of the global rezultat into pop(), then you assign a new value to the function parameter … Read more
Try adding the following lines after all your defs. if __name__==’__main__’: start() Also, everytime you call a function it needs to be followed by parenthesis, example: sign = Button(rootE, text=”register”, command=Signup) login = Button(rootE, text=”log in”, command=Login) Should be: sign = Button(rootE, text=”register”, command=Signup()) login = Button(rootE, text=”log in”, command=Login()) solved code is ignoring def … Read more
if you but braces end of a list (x.favourite_channels is list), then you get such error. if you want i’th element of list x.favourite_channels you should write x.favourite_channels[i-1] instead. solved python object oriented programming type:list object is not callable
I don’t think it’s so awful a question. Lot of folks responded negatively to the “best” aspect of the question. A simple rephrase might be “what circumstances are best suited for each kind of inter-object communication”. In summary the common ones are as follows: Direct invocation (google Objective-C language methods) – Most common, most direct, … Read more
Try to not use goto, as much as you can. By using goto you will be lost in your own code, because you have to search each time where your goto is pointing. Here you can do what you want by writing : if (mysql_num_rows(mysql_query(“SELECT `id` FROM `players` WHERE `hash`=’$hash’ LIMIT 1”))!=0) { $hash=generateHash(32); } … Read more
You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”) 1 solved Break out of Python for loop
You are trying to call an unbound function; zxLolBoT is a class, not an instance. As such, the self parameter is not being passed in for you, and the method only received 2 arguments instead of 3 (with self being that 3rd argument). self is already that instance, access the method on that to get … Read more
<?php function setFont($text, $name, $size){ return “<div style=”font-family: $name ;font-size: $size”>”.$text.”</div>”; } echo setFont(“Hello”, “tahoma”, “19”); echo setFont(“Welcome”, “tahoma”, “19”); ?> 2 solved Trouble With PHP Function, passing arguments [duplicate]
Besides from that your function definition for SearchForCapitals has a typo, by which I mean that the line def SerachForCapitals(): should be def SearchForCapitals(): (note the spelling of Search), your code works perfectly fine for me. If this does not fix your problem, you should provide the output you get when running the code. 1 … Read more
I suppose you intended this: function run{ Structure[0]() // <— notice the parentheses. } Without the parentheses, the function run does not do anything. It just references the function, without invoking it. solved Java Script function does not work [closed]
That is a recursive method that just calls itself. It creates an infinite loop. 3 solved What does “def loop: Boolean = loop” do in Scala