found the answer myself.. note that there is a difference between sinx and sin(x) function [sinx, error] = sinx_approx(x) % approximates the value of sin(x), the approximation is more accurate as % the number of terms selected is increased. n= input(‘Up to how many terms would you like to evaluate?’); sinx=0; for i=1:1:n sinx=(-1)^(i+1) * … Read more
You can represent the matrix as a vector<vector<int> >. Try something like this: #include <vector> using namespace std; void myFunction(const vector<vector<int> >& matrix) { // do something w/ matrix passed in… } int main() { // create a 3×4 matrix initialized to all zero const size_t rowCount = 3; const size_t colCount = 4; vector<vector<int> … Read more
There’s several problems with your code. First, the swap function doesn’t work. You’re swapping the values of the pointers that are local variables inside the function, you’re not swapping the array elements they point to. You need to indirect through pointers to get the values. int temp1 = *a; *a = *b; *b = temp1; … Read more
Try this formula =MATCH(G5,{“Prica Plus”,”Miks S”,”Miks M”,”Miks L”,”Miks XL”,”Miks XL Plus”,”Miks XXL”,”Super”},0)-MATCH(F5,{“Prica Plus”,”Miks S”,”Miks M”,”Miks L”,”Miks XL”,”Miks XL Plus”,”Miks XXL”,”Super”},0) Above formula can be broken down in two parts. Firstly, matching Cell G5 to your values =MATCH(G5,{“Prica Plus”,”Miks S”,”Miks M”,”Miks L”,”Miks XL”,”Miks XL Plus”,”Miks XXL”,”Super”},0) Secondly, matching Cell H5 to your values =MATCH(F5,{“Prica Plus”,”Miks S”,”Miks … Read more
s is a local variable that only exists within the function. Once the function exits, s no longer exists, and its memory will be re-allocated to other parts of your program. Therefore, your function is returning a pointer to a random meaningless block of memory. 2 solved Why should a function not return a local … Read more
For starters you could just run the code… but otherwise we can try and predict the output. For starters the function f has two parameters, i and j. The & Infront of the j means that the value of the function input is passed by reference (the value of the variable will be edited). So … Read more
To communicate between javascript (which runs on the client machine’s browser) and PHP (which runs on your server) you need to use ajax. Since you are already using jQuery, I suggest using their abstraction method $.ajax(). It would look something like this: // post value of #progressbar id to my php page $.ajax({ url: myPHPPage.php, … Read more
You could use std::string::compare() which provides the same functionality as strcmp(). std::string name1 = “John”; std::string name2 = “Micheal”; int result = name1.compare(name2); Would roughly be the same as: const char* name1 = “John”; const char* name2 = “Micheal”; int result = std::strcmp(name1, name2); solved Built in function to compare strings in C++?
You are never defining the function you’re trying to call. You’re printing from the function but never returning a value, thus your variable “a” will never get a value. Take a look at this, hopefully you’ll see where you went wrong: def odd(x): if int(x) % 2 == 0: return(“this number is even”) else: return(“this … Read more
Try this corrected and verified JavaScript Code – var rock = rock; var paper= paper; var snip = snip; var playerOneName= prompt(“what is your name”); playerOne = choice(); var playerTwoName = prompt(“what is your name”); playerTwo=choice(); alert(‘Player 1 Chose – ‘+ playerOne + ‘Player 2 Chose – ‘+playerTwo); function choice(pick){ return(prompt(“rock paper or snip”)); //return … Read more
So it turns out I just misunderstood what was being asked. I’ve had it clarified by the course leader now. As I am now fully aware, a function definition needs to be told when a string is being entered, hence the quote marks being required. I admit full ignorance over my depth of understanding of … Read more
You can do that easily by passing label as reference ( I’m expecting label to be a double and not a string ) . Here is how void setToValue(double &label , double value ) { label = value; } Note that you don’t need to make the function as type double as it is not … Read more
You aren’t assigning a function and an object to the same variable you are redefining the what the symbol foo is bound to. Everytime you set foo = you are binding what is on the right hand side to that symbol. You can’t use this to access the function because it is a different object. … Read more
When you call round() with double agrument you actually call: double round(double x); from <cmath> not your version hence the error. If you rename your function error would be gone without cast. Yet another reason to avoid using namespace std. 1 solved C++ function returning wrong data type
You really should clarify the issue you’re having; feel free to read How to Ask. Basic Loop As far as your question states (from my understanding), you would like to repeatidly call a method and have that method return the index of a string that corresponds to the current call. I would look into the … Read more