[ad_1] The answer variable is defined as character so you should change the format string of the scanf function: scanf(“%c”,&answer); 9 [ad_2] solved C – for loop only execute ones after scanf [closed]
[ad_1] You were almost there: for (i = 1; i <= 7; ++i) { for (j = 1; j <= 7; j++) { if (j <= i) document.write(j); else document.write(“*”); } document.write(“ ”); } Your code with comments: for (i = 1; i <= 7; ++i) { // This for should loop over your blocks document.write(i); … Read more
[ad_1] This should work for your purposes: name = input(“Please enter your name: “) name = name.lower() luckynumb = 0 firstnamenumb = 0 surnamenumb = 0 number = [1, 2, 3, 4, 5, 6, 7, 8, 9] row1 = [“a”, “b”, “c”, “d”, “e”, “f”, “g”, “h”, “i”] row2 = [“j”, “k”, “l”, “m”, “n”, … Read more
[ad_1] You can replace the condition in a loop with a delegate. Something like this works: int i = 0; Func<bool> predicate = () => i < 5; for (; predicate(); ++i) Console.WriteLine(i); Just assign a different delegate to predicate if you want a different condition. EDIT: This might be a clearer example: Func<int, bool> … Read more
[ad_1] Create an array, type int, length 10. Initialize it with the multiple of 2. In your code snippet you are not Initializing the array but simply printing the values to the console. You’ll have to initialize it using either the loop or as follows: int[] values = {2, 4, 6, 8, 10, 12, 14, … Read more
[ad_1] Yes it is :-). You count from 0 to your value, right? So read your int before the loop and use the variable as the loop end condition: Scanner input = new Scanner(System.in); int num = input.nextInt(); for(int i =0; i<num; i++) { System.out.print(“*”); } [ad_2] solved Output row of Asterisks using a for-loop
[ad_1] def look_up(to_search,target): for (index , item) in enumerate(to_search): if item == target: break # break statement here will break flow of for loop else: return(-1) # when you write return statement in function function will not execute any line after it return(index) print(“This line never be printed”) # this line is below return statement … Read more
[ad_1] You have a couple of problems with your code. First, you should stop the loop before i has the value list.size(). (Actually, since the index of the element is not used, you can use an enhanced for loop, which is what I show below.) Second, you need to test for the condition you want, … Read more
[ad_1] To keep it simple, in case A, your program has to initialize i only once. Assign values to i only array.Length times. Increase i values only array.Length times. do the line execution and comparison 2*array.Length times. In case B, initialize i twice. Assign values to i 2*array.Length times. Increase i values 2*array.Length times. do … Read more
[ad_1] This is the way break works. If you want to iterate over the whole list, simply remove the break (or if you want to do something with the value, use pass as a placeholder). values = [1, 2, 3, 4, 5] for value in values: if value == 3: pass print(value) Output: 1 2 … Read more
[ad_1] it’s ok now for (int i = 4; i > 0; i–) { for (int j = 1; j <= i; j++) Console.Write(“*”); Console.WriteLine(); } [ad_2] solved How to reverse for loop in c# for string type ? i need to remove one character each iteration
[ad_1] Based on provided results, you need updated first loop and second. Fist loop should start from 9 as you already printed mid line in previous part. And second loop should iterate to counter of fist loop to achieve what you except: public static void main(String[] args) { for (int i = 10; i >= … Read more
[ad_1] Maybe use zip: for a,b,c in zip(scores,boxes,class_list): if a >= 0.98: data[k+1] = {“score”:a,”box”:b, “class”: c } ; k=k+1; print(“Final_result”,data) Output: Final_result {2: {‘score’: 0.98, ‘box’: [0.1, 0.2, 0.3, 0.4], ‘class’: 1}} Edit: for a,b,c in zip(scores,boxes,class_list): if a >= 0.98: data[k+1] = {“score”:a,”box”:b, “class”: int(c) } ; k=k+1; print(“Final_result”,data) 9 [ad_2] solved Appeding … Read more
[ad_1] Json comes from J ava S cript O bject N otation. It’s a javascript-compatible format, so you can loop through it, and access it as you need. In other words, you do can get array[0][1][1]. If what you’re asking for is how can you receive a JSON in a string and convert it to … Read more
[ad_1] What if string is 0 length or count is 0? In your second case, you don’t return a value. This should be giving a compiler warning and will probably cause a crash as it returns whatever it wants. Edit Ok, the problem is deeper – you are never getting to the part of the … Read more