[Solved] using for loop in repeating number of day [closed]
for (int i = 0; i < userInput; i++) { System.out.print(” ” +(i%7)+1); } Assuming it is java code that you are talking about. 2 solved using for loop in repeating number of day [closed]
for (int i = 0; i < userInput; i++) { System.out.print(” ” +(i%7)+1); } Assuming it is java code that you are talking about. 2 solved using for loop in repeating number of day [closed]
To answer your second part of the question, with the assumption that every round the health will decrease till 1 player hits 0. (Because the way you are implementing it now, is that every time the inner For-loop is done, you reset the health of both wizard and sorceress, therefore making this requirement useless) Declare … Read more
A simple test proves the loop indeed works as intended: public static void main(String[] args) { int enemysno = 5; for (int i = 0; i < enemysno; i++) { System.out.println(“lalala ” + i); } } this works fine producing lalala 0 lalala 1 lalala 2 lalala 3 lalala 4 It was kind of obvious, … Read more
You don’t have an array with the whole elements or even a list which you’re creating items using console, so it’s impossible to compare item by item with the same input of data… 3 solved C# “if” and “for” [closed]
Introduction The “if” and “for” statements are two of the most commonly used control flow statements in C# programming. The “if” statement is used to execute a certain block of code if a certain condition is met, while the “for” statement is used to execute a certain block of code a certain number of times. … Read more
Condition to iterate your loop for(int j=0; j<=99 & a[j] > 1; j++) is j<=99 & a[j]. You initialized j to 0, so j<=99 part is true, but problem lies in second part of this condition. For j=0 condition a[j]>1 becomes a[0]>1, but a[0] is -2, which leaves us with -2>1 which is false. So … Read more
NSInteger index = 0; for(NSMutableDictionary *dict in arr_thisWeek){ NSLog(“%d”,[arr_thisWeek objectATIndex:index); index++; } But you already have the item at that index so you shouldn’t need it for array iteration. 0 solved Get the index value each for loop [closed]
Hope you understand it with the simple trace table I draw. solved Please explain the following C code? [closed]
try for (int i = 0; i < a.Length; i++) // or i < n if you want { print i; int z = a[i]; // this line will get value from a one by one, 0, 1, 2, 3 and so on… } Edit 1 – After seeing the comments on the other answer, … Read more
the condition here is implicit. C considers as true every integer not null. the ++i syntax is applied before the condition is evaluated Therefore the program run as follows: start: i=5 first loop condition (++i) => i=6 second loop iteration operation (i-=3) => i=3 condition (++i) => i=4 i is evaluated to true third loop … Read more
Since this is homework, it would be a bad idea to write the code for you. So ideally, what you need to do, is get the words that fit into the criteria (that you mentioned) and store them in a list. Then take the length of the list. After that, you can divide the length … Read more
You do not need to do anything in the XML file. This can all be done in a class. for(int i=0; i < x; i++) // where x is the size of the list containing your alphabet. { Button button = new Button(this); button.setId(i); yourView.add(button); } 1 solved ANDROID: How can I set up buttons … Read more
It can be done without recursion. var s = “A,B,C|1,2|a|u,v,w”; var u = s.Split(‘|’).Select(v => v.Split(‘,’)).ToList(); var buffer = new List<string>(); buffer.Add(“COMMAND “); while (u.Count > 0) { var t = from a in buffer from b in u.First() select a + ‘ ‘ + b; buffer = t.ToList(); u.RemoveAt(0); } The buffer list will … Read more
As defined in JLS, the first “part” of the for loop declaration, ForInit, is a list of statement expressions or a local variable declaration; j isn’t a statement expression (an assignment; a pre/post increment/decrement; a method invocation; a new class initialization) or a local variable declaration, so it’s invalid syntax. Depending upon what you are … Read more
I think so is easy int [] tabMaxMin = {1, 4, 8, -4, 11, 0}; int max = tabMaxMin[0]; int min = tabMaxMin[0]; for (int i=1; i < tabMaxMin.length; i++) { if(min >= tabMaxMin[i]) min = tabMaxMin[i]; if(max <= tabMaxMin[i]) max = tabMaxMin[i]; } System.out.println(“MAX=” + max); System.out.println(“MIN=” + min); } 0 solved I want … Read more