Use Json library: To save dict into file with open(“your_file”) as f: f.write(json.dumps(your_dict)) To load dict from file with open(“your_file”) as f: d = json.load(f) 0 solved I can not transform a file to a dictionary in python [duplicate]
You have a map of string to the value of TeamRow so when you get the val out of the map it returns the value of the team, not a pointer to the team. If you make the map a string to the pointer of TeamRow then when you get the val out it will … Read more
You can do as var ph = [String]() var newjson = [[String:String]]() for dict in json { if ph.contains(dict[“Phone”]!) { print(“duplicate phone \(dict[“Phone”]!)”) } else { ph.append(dict[“Phone”]!) newjson.append(dict) } } print(newjson) Hare newjson is the new array of dictionary that do not have duplicate phone solved How to parse JSON data and eliminate duplicates in … Read more
C++ How to distinguish Multimap with duplicate keys with value and and Unique keys with values in different map containers with O(n) traversal solved C++ How to distinguish Multimap with duplicate keys with value and and Unique keys with values in different map containers with O(n) traversal
One of the shortest way would be to prepare a list/set of all the keys from all the dictionaries and call that key on all the dictionary in the list. list_of_dict = [{‘a’: 1, ‘b’: 2, ‘c’: 3}, {‘a’: 3, ‘b’: 5}, {‘k’: 5, ‘j’: 5}, {‘a’: 3, ‘k’: 5, ‘d’: 4}, {‘a’: 3}] # … Read more
There is the working code quiz_scores = { ‘Corbin’: [92, 66, 88, 91, 100, 95, 94], ‘Kevin’: [100, 99, 100, 98, 95, 98, 99], ‘Hannah’: [79, 67, 78, 81, 70, 55, 74], ‘Ben’: [94, 88, 85, 100, 91, 79, 88], ‘Yasaswini’: [99, 90, 88, 91, 89, 95, 94], ‘Veda’: [79, 97, 88, 82, 70, 95, … Read more
Your code is duplicating every corresponding list (values) in example1 as many times as the values in example2. Your code is similar to: >>>>two_items = [“A”,”B”] >>>>number = [3] >>>>result = two_items*number[0] [‘A’, ‘B’, ‘A’, ‘B’, ‘A’, ‘B’] To make this clear, it works like string multiplication: >>>>my_string=”Hello ” >>>>print(my_string * number[0]) Hello Hello Hello … Read more
As you have a dictionary of dictionaries, accessing each dictionary value will give you another dictionary. You can then access the values from that dictionary in the same way. For your particular example, you can do the following: >>> master_dict[“Item”][“last_data”][“S”][“question”] ‘question question question?’ If instead, you want to access all occurrences of a certain key … Read more
Trick The trick is to find out in advance whether a target_key is among the next children (= this_dict[key] = the values of the current dict iteration) before you reach the child level recursively. Only then you can still delete a key:value pair of the child level while iterating over a dictionary. Once you have … Read more
In here: for entry in my_dict_1.keys(): my_dict_1[entry] = metric You are assigning the value of metric to all your dict (my_dict_1) items. Reason why ‘it just adds the last arg passed’. Without cleaning up your code, here’s the patch to fix your issue: for i, metric in enumerate(my_metrics): … my_dict_1[i] = metric 4 solved Python … Read more
First make from your string a list. list_name = string_name.split(‘ ‘) Then switch the keys and the values from your dict (if using python 3.x use iter instead of iteritems) my_dict = {y:x for x,y in my_dict.iteritems()} Then you can iter tro your code for numbers in list_name: print(my_dict[int(numbers)]) 6 solved Python – Swap a … Read more
If you want [{‘name’: ‘None’, ‘age’:20, ‘dead’:’NO’}] then try: data_dict = {‘name’: ‘None’, ‘age’:20, ‘dead’:’NO’} data_list =[data_dict] 7 solved How to insert a dictionary inside list [closed]
I believe you want is: Multiply each key with 2. Not the square of it. d = {2: (1,2), 8: (2,4), 30: (10,3)} d = {k*2: v for (k, v) in d.items()} print(d) OUTPUT: {4: (1, 2), 16: (2, 4), 60: (10, 3)} solved How to multiply dictionary keys? [duplicate]
I think you are looking for something along the lines of this: # run with python dynamictopo.py z n # e.g.: python dynamictopo.py 3 2 import sys z = int(sys.argv[1]) # number of nodes n = int(sys.argv[2]) # number of hosts nodes = [] for i in range(0, z): nodes.append(“s” + str(i + 1)) print(nodes) … Read more
solution.highest_count_words_across_lines is an array of strings. When you do this: solution.highest_count_words_across_lines.map(&:highest_wf_words) you are calling highest_wf_words on each of the array items, and that method is not defined for a String (that is what the error message says). I guess that in fact you want something like this instead: words_found = solution.highest_count_words_across_lines.map( |x| highest_wf_words(x)).flatten UPDATE if … Read more