EDIT: You’re actually not having a python issue but a bash one. You’re running your python script as if it were bash (hence the ‘from: can’t read from’), did you put #!/usr/bin/env python at the beginning of the file you’re running (not print_text.py, the other one)? You could alternatively call it that way: python myfile.py … Read more
Here’s my best guess at the code you meant: #include <iostream> using namespace std; char *mystring = “thestring”; // extremely dangerous type mismatch, don’t do this int msize = 200; int myfunc(int x) { int y = 20; x = x + y; return x * y; } int main(void) { int *px = new … Read more
public class Main { int x=25; int y =25; //Go to next class second aMethod(){ Second s = new Second(); s.manipulateValues(x,y); } } public class Second { //inherit values of x and y //manipulate values //Go to next class third public void manipulateValues(int x, int y){ //manipulate here Third t = new Third (); s.manipulateHereToo(x,y); … Read more
Yes, a B can access protected members of an A. But it’s the fact that you’re going through v3 that makes it essentially irrelevant that this attempt is made from within a member function of B. It’s v3 trying to make the access, not B::calculate, and v3 is not a B&. [C++11: 11.4/1]: [..] All … Read more
As you can image, what you are reading in the log is the override version of Object#toString() in View: V stays for View.VISIBLE E stays for ENABLED final int id = getId(); if (id != NO_ID) { out.append(” #”); out.append(Integer.toHexString(id)); it is the View’s id toHex. You can read the complete method here 13 solved … Read more
That’s because you never set an initial value for x and y in either ArcherDown or Archer. You can solve this problem by adding a method such as def __init__(self, x, y): self.x = x self.y = y to each class. 3 solved Why does it say that my instance has no attribute x?
You are declaring the variables as local to the function. That is why they are being reset every time you call the function. To preserve the values between function calls, you have to move the variables into members of the class instead. Your Die class is also not well designed, either. You should be seeding … Read more
On your class DVDPlayer you chose to say that a regular DVDPlayer cannot record. So you set it to false. If you want it to record you either change the variable directly, like you did on the class DVDPlayerTestDrive. The boolean canRecord = false is only meant to show you that it is possible to … Read more
The identifier private restricts access to class methods and class friends. The static identifier indicates there is only 1 instance of the variable to be shared among all children. So, private static means a data member that has only one instance, regardless of the number of instances, and only class methods and class friends can … Read more
the only problem I see is the way youre accessing your method: $myLogIn = new Hos_LoginStatus(); $signedInName->getUserSignedIn(); $signedInName is not defined anywhere, it should be: $myLogIn = new Hos_LoginStatus(); $signedInName = $myLogIn->getUserSignedIn(); You should probably turn error_reporting on in order to see encountered errors. 1 solved How to debug this my Class in php
I have learned that extending JFrame and JPanel is bad But if you need to draw in the GUI, you often need to extend JPanel, and that’s exactly what you should do here. For example the code where you draw with a Graphics object should be inside of the JPanel’s protected void paintComponent(Graphics g) method. … Read more
If you want more than one economy, then you need a property that keeps track of which economy each worker belongs to. Then you can just use that reference to subtract the wage from the correct economy: public class Worker { public Economy InEconomy { get; private set; } public int Wage { get; private … Read more
This syntax in invalid. You cannot simply write code inside a class definition. Instead, you can write a function and your code will work inside it: class Foo { public: void bar() { int * p = new int; *p = 5; } }; int main(int argc, char ** argv) { Foo f; f.bar(); } … Read more
Yes, you are correct. By calling new you are creating a reference to an object, you are doing a similar operation when you declare a new String. 5 solved What is the error in each Java Statement?
Change public Circle(radius,x, y){ this(5, 3, 6); } To public Circle(int radius,int x, int y){ //need to add types to parameters this.radius=radius; this.x=x; this.y=y; } Or if you plan to use 5,3,6 as constant values add public Circle(){ this.radius=5; this.x=3; this.y=6; } 1 solved I’m not understanding what the error comment is trying to tell … Read more