There are two ways you can do this, recursively or iteratively. The recursive approach is the simplest to code. You write a “free node” function that checks if the node has any descendants or siblings and calls the “free node” on each of them, then it frees the node it was called on. Performing this … Read more
So, if this is just a thought-experiment, then the answer is “You can’t do that”. If you actually want a hierarchy where your derived classes have different types, you could do something like this: class Base { public: virtual void bar() = 0; }; class A: public Base { public: void bar() { … do … Read more
To list out just the items associated with the key: String.Join(“, “, items[key]); To list out all products and all items: foreach (var key in items.Keys) { System.Console.WriteLine(“{0}: {1}”, key, String.Join(“, “, items[key])); } 1 solved How to display values in a dictionary?
The 3 functions are the same. The difference is the argument you pass to them. &p: get the reference (memory adress) of the variable p. *p: assumes that p is a memory address and get the value that is stored in that position. In this case, you will get a sigsev because you are trying … Read more
You problem is with floating point precision. float i = 4.2; i *= 100; printf(“%f\n”, i); Print: 419.999969 and not 4.2 as it should, in this case 419 is the value used in the coin problem resulting in 22 coins used 16 of 25, 1 of 10, 1 of 5 and 4 of 1 = … Read more
So it looks like you have this: struct Obj { int x_; }; template <typename T> struct Struct { std::vector<T> items_; }; So to access an element (assuming you added it to the vector): int main() { Struct s; s.items_.resize(10); s.items_[0].x_ = 5; // Access the object memeber of element 0 in the vector. } … Read more
1: No because it is only the starting value. This part will be visited only once at the start of the loop 2: Yes because the linq expression has to be evaluated to get the result value. If you want to avoid it execute the linq expression once before the loop and save it into … Read more
HttpWebRequest req = null; HttpWebResponse resp = null; string baseaddress = “http://deveqtradedb.lazard.com/API.aspx?action=export&entity=global”; req = (HttpWebRequest)WebRequest.Create(baseaddress); req.Method = “POST”; req.ContentType = “text/xml; encoding = UTF-8”; resp = req.GetResponse() as HttpWebResponse; Check Here https://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.getresponse(v=vs.110).aspx solved How to call a service from console Application in c#
In your main you define gh(5) which allocates the vector of size 5 then you use your addEdge method with parameter (5,6) which tries to access list[5] but the five list entries are list[0],list[1],list[2],list[3], and list[4]. So I guess gh.addEdge(5,6) gives the Segmentation fault as it is out of range of your vector. 0 solved … Read more
x1 = (-e + sqrt(e*e – 4 * d*f)) / (2 * d); x2 = (-e – sqrt(e*e – 4 * d*f)) / (2 * d); solved why the output of C program is wrong?i have checked for a long time [closed]
The question is a bit more interesting than downvoting peple think. Sure, that conditional logic is really perfect. Visual studio generates a warning: Unreachable code detected, so the else branch will never ever be executed. Even in case of hardware fault, computer / operating system / program itself is more likely to crash than the … Read more
concentrate on this piece of code for (i = 0; i <= 5 ;i++) { –> for (space = 5 – i; space <= 4; space++) { printf(” “); } in first iteration of inner for loop space value is space: 5-0 = 5 as the i:0 and for we have condition space <= 4 … Read more
First name.Replace(“‘”, “\'”) does nothing because “‘” == “\'”. So name.Replace(“‘”, “\'”) returns “he’s here” (you can try it in https://dotnetfiddle.net/). What you want is: name.Replace(“‘”, “\\'”) Second if you inspect name in the debugger (in watch window or immediate window) you will get “he\\’s here” because that is how you should write a string … Read more
try dic.Values.OrderBy(i=>i.CreatedDateTime) 0 solved How to sort dictionary by DateTime attribute of the value
There are a few errors in your program. Firstly, you declare your function parameter without setting the data type of the parameter. Generally, declaring a function has the following format: return_type function_name(input_type input_parameter, …) { // Do whatever you want } In the above, the input type refers to the data type of the variable … Read more