The only tricky thing here is a comparison with tolerance, since because of round up errors you can well never meet answer == value condition. The implementation could be double answer = 300.0; double tolerance = 1e-10; while (true) { // based on previous answer we compute next one double value = 0.5 * (answer … Read more
Your Question is Simple.. If and else are used, When you make a true or false statements. Example: If ( 3>2) { printf (“3”);} else { printf ( “2”);} But in case of if and else if Example: if(3>2) {printf (“3”);} else if (2>3) {printf (“false”);} IN THIS WAY .. In else if. you should … Read more
Given that 98% of the time is spent in that function, I rewrote your “get a number” function: int Ten_To_One_Million_Ten(void) { unsigned Number = (((unsigned)rand() << 5) + (unsigned)rand()%32) % 1000000 + 10; assert(Number >= 10 && Number <= 1000010); return Number; } Now, on my machine, using clang++ (Version 3.7 from about 4 weeks … Read more
Let’s consider two ways to solve it that are two slow, and then merge them into one solution, that will be guaranteed to finish in milliseconds. Approach 1 (slow) Allocate an array v of size 2^16. Every time you add an element, do the following: void add(int s) { for (int i = 0; i … Read more
Not Possible Two problems: Where does the array end? In C, arrays are simply blocks of memory and do not have a length property. It is possible to read unpredictable numbers off the end of the array, from other portions of memory. In the posted code, sizeof(*arr) apparently is being used to get the length … Read more
Change your code from $query = “SELECT COUNT( id ) FROM scores WHERE id = $id;”; $result = mysql_query($query) or die(‘Query failed: ‘ . mysql_error()); to $query = “SELECT COUNT( id ) as `total_ids` FROM scores WHERE id = $id”; $result = mysql_query($query) or die(‘Query failed: ‘ . mysql_error()); after that you need $count = … Read more
Is there another solution for this situation without using braces? That is the wrong question. The real question is: is there ever a reason to NOT use braces? NO. Just use braces. Your colleagues, and future-you, will thank you later. 1 solved Is this the most elegant/safe/recommended solution for this situation?
The solution you look for is rand() % 7 + 4 which will give you results from range [4, 10]. More general, for given min and max to obtain random value from [min, max] you go for rand() % (max – min + 1) + min 1 solved Error in using rand function [closed]
Let’s suppose we have a function like this: int change_char( char *str, const char a, const char b) { int n = 0; if ( str ) { while ( *str ) { if ( *str == a ) { *str = b; // Can I modify the value pointed by the pointer? ++n; } … Read more
They check completely different things. is compares types. == compares values. var isString = “Abc” is String; // => true var equalToString = “Abc” == String; // Error: `string’ is a `type’ but a `variable’ was expected There is one domain where these can both apply, and have different meanings, and that’s in type checking: … Read more
How can I remove every digit at the beginning? Linq SkipWhile would be one way string result = string.Concat(“1234ABC123”.SkipWhile(char.IsDigit)); // “ABC123” solved Check if the first chars are digits
First, let’s use a typedef for the function: typedef int agechanger(int); this makes a new type, agechanger, which will be used in code for passing the function instances around. Now, you should give your person class a proper constructor, and properly incapsulate the age field providing a public getter. Then add a method that accepts … Read more
Use output.put(i); since it takes one character at a time. But you really want to skip the for-loop and just write the whole vector in one write: output.write(f.data(), f.size()); 2 solved Save an unsigned char vector one by one
This will always return 0, because the last fac will always be 0 and it multiplies all the other results. Change that to if(a<1) fac=1; Also indent your code properly. solved what is wrong with my factorial program ??? [closed]
I think you need something like this: // Make sure x is smaller than y if(x>y) { swap(&x, &y); } // Make sure x is smaller than z if(x>z) { swap(&x, &z); } // Now x is smaller than both y and z // Make sure y is smaller than z if(y>z) { swap(&y, &z); … Read more