[ad_1] B will not have any effect. inline only suppresses the one-definition rule; it does not force the compiler to inline the function. C is unlikely to have any impact; if the compiler determines that the function is a good candidate to be inlined, it will do so. Manually inlining it could make performance worse. … Read more
[ad_1] You need A separate index for writing to szBuffer Code that adds a zero termination to szBuffer Like: int j = 0; // Index for storing in szBuffer for (int i = 0; i < StrLenght – 1; i++) { if (szPattern[i] == ‘%’) { // DO stuff…. } else { szBuffer[j] = szPattern[i]; … Read more
[ad_1] Well the message is clear and it is easy to spot in your program: double gallons,miles; while (miles>=0||gallons>=0) { miles is declared in a function and so is an automatic variable. Automatic variables are not initialized (so they have garbage values). Now in the first executable statement you compare miles. But miles is still … Read more
[ad_1] To pass literal string to a function, it must have a parameter of type char const *, not char *. So your constructor should have this prototype: Etudiant(char const * c, unsigned int, Date &); Saying the above, you also do not allocate enough memory to copy a string in your constructor. This line: … Read more
[ad_1] You can use boost lexical-cast which is exactly for this purpose. It will throw an exception the conversion fails. Boost is well tested and you can safly use it to do the conversion for you. This could look like this: #include <boost/lexical_cast.hpp> #include <iostream> int cube(int x) { return x*x*x; } int main() { … Read more
[ad_1] Missprint. Should be: sql = sql + ” ORDER BY MemberID DESC Limit 1″; 0 [ad_2] solved I received error when I used this SQL Syntax
[ad_1] Although you believe your code is similar to this: #include <iostream> double f() { double x = 3; return x * -1; } int main() { std::cout << f() << std::endl; } The code you have actually takes the type of x from the result of a vector’s size() – this returns a std::size_t: … Read more
[ad_1] There are lots of mistakes in your code. Many of them look like typos, but the serious errors are Not using the template parameter T in your function signature. This is the reason half(tb) did not compile since your version of half always expected an int. Not understanding that in your constructor student = … Read more
[ad_1] Something like this should work: string.Join(“|”, myString.Split(‘|’).Select(x => x.PadLeft(4,’0′))); I made a fiddle: https://dotnetfiddle.net/uK1kyr [ad_2] solved Format a sting in based on Divider symbol [closed]
[ad_1] You can use if( atom[k][0] == ‘\”‘ ) Exception handled version (.at() throws an error if index is out of bounds): if( atom[k].at(0) == ‘\”‘ ) 2 [ad_2] solved How to check if the first element of an vector is a quote in C++
[ad_1] Standard C++11 or C++14 does not have any graphics library. But you should consider using Qt, a free software cross-platform GUI library for C++. I guess that you’ll be happy in using Qt graphics view framework. You could also consider some other, perhaps OS specific, widget toolkit. Or just output a 2D graphics using … Read more
[ad_1] To answer your first question. By doing an if statement in one line you are limited to one operation, so to speak. if(ret != 0) return false; Whilst using the curly brackets you are declaring a block with code operations. if(ret != 0) { /* do other stuff here */ return false; } There … Read more
[ad_1] Literally i can use a[i] or p1[i]? Yes, dereferencing works the same way for a raw array symbol or a pointer. The a symbol in your example will decay to a int* pointer whenever used as such (p1=a;). Using code like p1[i] is just syntactic sugar for *(p1 +i). 2 [ad_2] solved Pointers with … Read more
[ad_1] This example assigns a struct using a pointer and one statement. int main(void) { struct Foo { char a; int b; double c; } *foo, *bar; foo->b = 10; bar = foo; /* now bar->b=10 as well */ } [ad_2] solved Is it possible to assign a entire struct using a pointer and one … Read more
[ad_1] this is already a pointer to that object. So you should make something like this: Area *p = this; The this pointer is an implicit parameter to all member functions (non-static members). Therefore, inside a member function, this may be used to refer to the invoking object. 16 [ad_2] solved unexpected error on using … Read more