[ad_1] As a general rule, it’s more flexible to leave it to the user. For example, consider a map-type container. Suppose the application needs to atomically move something from one map to another map. In this case, the user needs to lock both maps before the insert-erase sequence. Having such a scenario be automatically taken … Read more
[ad_1] You need to allocate memory for n before using it, something like: node n = new Node; 2 [ad_2] solved program compiles and runs but after sometime it stops working in cpp ,using typedef keyword [duplicate]
[ad_1] If you use e.g. MATLAB to design your filter (using e.g. the ellip function), you can take the resulting filter coefficients and very easily implement the filter in software (it’s just a matter of multiplying the float values by the coefficients and following the rational filter equation). 1 [ad_2] solved Elliptic Filter Code [closed]
[ad_1] You cannot do what you want with a switch, but you can simplify it to: if (intDaysOverdue <= 30) decInterestRate = 0m; else if (intDaysOverdue <= 59) decInterestRate = .5m; else if (intDaysOverdue <= 89) decInterestRate = .10m; else decInterestRate = .15m; Your >= 30 and >= 60 conditions are not needed, as they … Read more
[ad_1] Passing an instance of a class by value invokes the copy constructor. The compiler implements the copy constructor by default (essentially a memberwise copy after invoking copy constructors of any base classes) if the class definition does not explicitly supply one. This compiler-generated copy constructor will not call one of the other constructors you … Read more
[ad_1] The year does automatically change with adding and subtracting months. See This Example. 0 [ad_2] solved +/- 1 month to the datetime
[ad_1] Well, there are two different types: Array of array (jagged array): float[][] sample = new float[][] { new float[] {1, 2, 3}, new float[] {4, 5}, // notice that lines are not necessary of the same length }; 2d array: float[,] sample2 = new float[,] { {1, 2, 3}, {4, 5, 6}, }; Edit: … Read more
[ad_1] You can simple use ToString with parameter: private string getResult(int x) { return x.ToString(“0000”); } from @Dmitry Bychenko : You can also use “D4” as parameter instead of “0000” with same results. This solution also works with negative numbers instead of PadLeft method. 1 [ad_2] solved how to create a string like regex
[ad_1] Use std::vector, which is designed for exactly this use case. The (rough) translation of the Perl code you have given to C++ using std::vector would be something like this: #include <iostream> #include <vector> int main() { // Declare a vector that can only contain int values. std::vector<int> numbers; // Put the numbers [1,10] into … Read more
[ad_1] try this: string todayDate = DateTime.Today.ToString(“yyyyMMdd”) 0 [ad_2] solved How to retrieve date without time in the yyyymmdd format in C# [closed]
[ad_1] You need a char for the final \0, I have used a loop to get the 2 char #include <string.h> #include <stdio.h> int main(void) { static char pvtsWsMthDayTab[25]=”312831303130313130313031″; char sDaysInMth[12][3] ; memset(sDaysInMth, 0, sizeof(sDaysInMth)); for(int i = 0; i < 12; i++) { for (int j = 0; j < 2; j++ ) { … Read more
[ad_1] This might solve your problem discountedAmount = amountDue * discount / 100; For eg. amountDue = Rs. 700 discount = 10% discountedAmount = Rs. 70 Amount to be paid = Rs. 700 – 70 = Rs. 630 3 [ad_2] solved How to get a percentage in a given decimal value [closed]
[ad_1] The answer was a simple Regex: bool regexmatch(string s){ regex e (“[-+]?([0-9]*\.[0-9]+|[0-9]+)”); if (regex_match (s,e)) return true; return false; } It will return true on integers (i.e. 56, -34) and floating point numbers (i.e. 6.78, -34.23, 0.6) as expected. 3 [ad_2] solved c++ Check if string is valid Integer or decimal (both negative and … Read more
[ad_1] One advice, if you don’t learn for yourself, then nobody can teach you. So, please try researching a bit on the internet, or reading a good book before you post a question. Assuming this is your first mistake, and you wont repeat this without working a little on your own, i’ll provide the code … Read more
[ad_1] Add this code to Form1’s button click, private void button1_Click(object sender, EventArgs e) { Form2 from2 = new Form2(); Control[] button = from2.Controls.Find(“button1”, true); button[0].Click += new EventHandler(ShowLabel); from2.ShowDialog(); } Add this Form1 too (Set the WORK label’s visible property to false under properties) private void ShowLabel(object sender, EventArgs e) { label1.Visible = true; … Read more