[ad_1] You could try the below pattern to match XXXX.XXXX.XXXX, \b[a-z0-9]{4}(?:\.[a-z0-9]{4}){2}\b I assumed that the Hardware address must contains lowercase letters and numbers. 0 [ad_2] solved Regex pattern for parsing this test file?
[ad_1] Ahhh, At last I found solution to it. instead of declaring properties private they should be public:- private string ProductName { get; set; } private string ProductPrice { get; set; } private string ProductUnit { get; set; } private string ProductStock { get; set; } Correction:- public string ProductName { get; set; } public … Read more
[ad_1] Did you see inside the executenonquery method of the connection class this line? cmd = new SqlCommand(qry, conn); This creates a new command, one without any parameters defined. Of course it fails. The fastest way to fix your code is to change the method executenonquery to receive a already built command or create an … Read more
[ad_1] C doesn’t allow multiple assignment like that, set each variable to 30 in a different statement. 1 [ad_2] solved Can anyone explain what is the error in the following program?
[ad_1] The “environment” parameter, traditionally named envp, is a zero-terminated array of char*. You can display it like this: int main(int argc, char* argv[], char* envp[]) { while (*envp) { std::cout << *envp << std::endl; envp++; } } It’s not part of POSIX (or any other standard) but supported by many compilers. [ad_2] solved What … Read more
[ad_1] here is the solution i have done . and its working . foreach(var dir in Input_Folders) { string f = dir; for (int i = 0; i <= n; i++) { string path = sub_dir(f); f = path; } } n is the nth child and the method sub_dir(string) is public string sub_dir(string path) … Read more
[ad_1] EDIT – just changed it so that it’s just an int, now it gets a value of -82938723047 or some such number. why on earth is this happening? It’s ruining my program! You are almost certainly barking up the wrong tree. The code: for (int i = 0; …initializes i to 0, period. If … Read more
[ad_1] Try this. Tested working. using System; namespace ConsoleApplication { internal class Program { private static void Main(string[] args) { char[] letter = new char[26] { ‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, ‘G’, ‘H’, ‘I’, ‘J’, ‘K’, ‘L’, ‘M’, ‘N’, ‘O’, ‘P’, ‘Q’, ‘R’, ‘S’, ‘T’, ‘U’, ‘V’, ‘W’, ‘X’, ‘Y’, ‘Z’ }; int letter_number … Read more
[ad_1] Yes, you need to provide an argument in your macro definition: #define RequiredDamage(x) ( (x+1)*500 ) 3 [ad_2] solved C++ define function [closed]
[ad_1] You have p as some pointer. Who is going to allocate the memory that pointer points to? In C it is almost always the responsibility of the caller to allocate any buffers before the call. If you don’t want to, then use a std::string instead. [ad_2] solved file handling I/O c++ error
[ad_1] You need to print : for each strength point and fill the remaining with spaces (capacity). There are several methods. Method 1: The loop cout << ‘{‘; for (unsigned int i = 0; i < capacity; ++i) { if (i < strength) { cout << ‘:’; } else { cout << ‘ ‘; } … Read more
[ad_1] You copied the statement wrong. In the program you cited in your comment there’s only one for statement which approximates what you posted above: for(time=0,count=0;remain!=0;) In this case the “initialization” portion of the for statement is time=0,count=0 Note that the character between the initialization of time and count is a comma, not a semicolon. … Read more
[ad_1] you can use the following Regex To extract no from your string string input =”Example123456.csv”; input = Regex.Replace(input, “[^0-9]+”, string.Empty); the output will be 123456 [ad_2] solved C# Split String before the first number
[ad_1] Why isn’t std::set just called std::binary_tree? Because Tree doesn’t describe how the interface is used. Set does. std::set does not provide sufficient operations to be used as a general purpose search tree. It only provides an interface to a particular application of a search tree: The representation of a set. Technically the standard doesn’t … Read more
[ad_1] void A_output(struct msg message) { struct pkt packet; […] packets[counter++] = (pkt*)&packet; This last line assigns the address of a variable with automatic storage duration (a local variable) to an object with static storage duration (a global). Once your function exits, the variable with automatic storage duration doesn’t exist anymore, therefore the pointer doesn’t … Read more