You have a member function: void func_A(int a, T initvalue = T()) {} that can be called like this: mc.func_A(1); Then you have an overloaded member function: void func_A(int a) {} that can also be called like this: mc.func_A(1); How…
At least part of the problem is that you are not understanding how operators work in C++. for(i=1;i<=n,completed==0;i++){ The expression i<=n,completed==0 has the effect of evaluating i <= n, discarding the result, then evaluating completed == 0, and giving the…
Now, the question states that at most 2 out of A, B, C are non-positive. So, it means that condition that includes the 3 numbers and returns true would be 1. !(A =< 0 && B =< 0 && C…
Solution in C++14, assuming I understood what you meant: template <class Container> constexpr auto byte_size(const Container& container) { using std::begin; using std::end; return (end(container) – begin(container)) * sizeof(container[0]); } Note that this will work even if the container is empty,…
As panta-rei correctly pointed out, it looks like you’re trying to contain a string of the form “string” + string form of (i) but you’re actually doing pointer arithmetic which is illogical in this case (you’re just passing a pointer…
Remove #include “ar.cpp” from main. You’re defining insert two times. There is no difference between the relevant rules in C++11 and C++14. You did something different between your test runs that has nothing to do with the language version. I…
Optimization was the wrong term, but the code can be rewritten to find a better (more reduced, or succinct to the business) logic. X < min(Y, Z) <=> X < Y and X < Z X < max(Y, Z) <=>…
For any array or pointer a and index i, the expression a[i] is exactly equal to *(a + i). From that we can draw the conclusion that a + i is a pointer which is equal to &a[i]. So when…
You have p as some pointer. Who is going to allocate the memory that pointer points to? In C it is almost always the responsibility of the caller to allocate any buffers before the call. If you don’t want to,…
The actual type is hidden as it’s local inside the function, so you can’t explicitly use it. You should however be able to use decltype as in decltype(create<int>()) v = create<int>(); I fail to see a reason to do like…
So how is the 10000th element stored here? The element isn’t stored in the vector. It’s ‘stored’ in a piece of memory that is unrelated to the vector. Isn’t the expected behavior here a “Segmentation fault”? No. The behaviour is…
The part in is_attaced in which you check the diagonals is not working. It has two basic problems, first you dont check all diagonals all rows – you just check the previous row. And, second, you are doing out of…
Depending on the file structure (does it contain line/column headers, single/multi-line?) you use QString::split() to get a QStringList per line. Then you assign the stringlist items to the variables according to your csv structure knowledge. 0 solved Qt separating csv…
The speed difference is largely due to the iostream I/O functions maintaining synchronization with the C I/O functions. We can turn this off with a call to std::ios::sync_with_stdio(false); By default standard C++ streams are synchronized to the standard C stream…
The issue is that n keeps growing, but your array does not. This code invokes undefined behavior, which thankfully caused a segfault for you: while(ch==’y’) { n++; cout<<“Enter 1 more element: “; cin>>arr[n]; cout<<“Want to enter more? “; cin>>ch; }…