[ad_1] You could use a function like this, where n is the number and d is the digit you want to count: int count_dig(int n, int d) { int result = 0; while (n > 0) { if (n % 10 == d) { result++; } n/=10; } return result; } Using this, you could … Read more
[ad_1] Is there a simpler approach to reuse code in C++ as we do with packages in java? Making a header file is comparatively complicated? [ad_2] solved Is there a simpler approach to reuse code in C++ as we do with packages in java? Making a header file is comparatively complicated?
[ad_1] Convert.ToDateTime uses DateTime.Parse internally, with the current culture of server. And, the problem is your new server’s current culture’s DateTime format is different from your string. You can use DateTime.ParseExact() instead of this. Converts the specified string representation of a date and time to its DateTime equivalent using the specified format and culture-specific format … Read more
[ad_1] “Is there any difference between these 2 ways of storing an integer?” Yes, there is a significant difference. int X = 100; Initializes a variable X on the stack with the value 100, while int *pX = new int(100); allocates memory for an int on the heap, kept in pointer pX, and initializes the … Read more
[ad_1] You can try this: for (int i=6; i>1; i–) { for (int j=0; j<i; j++) cout<<“*”; cout<<endl; } Output: ****** ***** **** *** ** 2 [ad_2] solved Print 6,5,4,3,2 characters separated by a new line in C++?
[ad_1] There will be no difference in the compiler generated code. The else is unnecessary but may be written for clarity. [ad_2] solved Which one of the following codes is faster in excecution? [closed]
[ad_1] Your first code fragment is badly indented, it should read: if (i1) if (i2) s1; else s2; Which is equivalent to your second fragment, but obviously very different from the third fragment: if (i1) { if (i2) s1; } else { s2; } This issue is called the dangling else problem. You can avoid … Read more
[ad_1] Signed ints use Two’s complement in order to represent negative numbers. 1 represented in int32: 0000 0000 0000 0000 0000 0000 0000 0001 -1 represented in int32, using Two’s complement: 1111 1111 1111 1111 1111 1111 1111 1111 XORing the two results in: 1111 1111 1111 1111 1111 1111 1111 1110 which, for signed … Read more
[ad_1] In C, in the result of the binary &, each bit depends on the two corresponding bits in the operands. If the bit in the same position is set (1) in both operands, it is set in the result. If it is clear (0) in either operand, it is clear in the result. For … Read more
[ad_1] These are just dummy files (implemented by the IDE) that serve documentation & autocomplete purposes for the builtin functions / classes. If you want to see how PHP works under the hood, take a look at its source code: https://github.com/php/php-src. If you want to extend PHP with custom functions, you can write an extension … Read more
[ad_1] I fixed it for you: static void Main() { Class1 c1 = new Class1(); int a=1; c1.test(out a); } When calling a function that has an out or ref parameter, you need to pay some respect to that, by marking your parameter as out or ref as well. MSDN Reference Page To use an … Read more
[ad_1] SaveAs doesn’t return a string, or anything else. If you want the path in its own variable, string filepath = Server.MapPath(“~/UploadImages/”) + filename; ((FileUpload)row.FindControl(“FileUpload1”)).PostedFile.SaveAs(filepath); 1 [ad_2] solved Error cannot implicitly convert type ‘void’ to ‘string’ on string filepath [closed]
[ad_1] You need to use logical operators each time. IF you want to chack all strings to inequality to empty string then use String.IsNullOrEmpty() method instead of != operator. Also there is no reason to use () in your expression. You need to use brackets to prioritize operations but in your code there is no … Read more
[ad_1] Your vector has zero length at start vector<int> binV; //zero length In this line of code for (int i = 0; i < binV.size(); i++){//some code} Will not run because binV is empty This expression is not correct if (input == 1 && input == 0) //not valid This && is logical and operator, … Read more
[ad_1] As asker has said, the issue was that the file name was “DATA.DOCX” and needed to be changed to “DATA.TXT”. //PROGRAM TO COUNT NO OF OCCURENCES OF A STRING IN A DATA FILE #include<fstream.h> #include<conio.h> #include<string.h> void main() { ifstream ifs; ifs.open(“DATA.TXT”,ios::in|ios::nocreate); if (!ifs) { cout<<“SORRY! FILE DOES NOT EXIST”; } else { int … Read more