You can put the array through Array.protoype.map, which replaces each value in the array with whatever the callback function returns. In the callback function you can return an array version of the object. For example: var result = yourArray.map(function (item) { return [item.text, item.count]; }); More array methods can be found on the MDN docs … Read more
You want to create an array with a size of zero which is not allowed. You also can´t declare an array with a variable size so you have to use malloc or something else. #include <stdio.h> #include <stdlib.h> int main() { printf(“HOW MANY NUMBERS DO YOU WANT TO INPUT\n”); int array_size; scanf(“%d”, &array_size); int* Array … Read more
Looking at the error messages is sufficient to debug the code and make it work. It’s very basic error messages that can be resolved just by reading the code once. 1) extern.c:14:7:conflicting types for ‘array’ char *array[5][0]; ^~~~~ extern.c:6:6: note: previous declaration of ‘array’ was here char array[5][10]; Error: There is declaration of same variable … Read more
Can you try something like following? I haven’t tested the following but it should work on most part. // Elvis’s hip and happening ABC-printing code #include <stdio.h> #include <string.h> #define NUM_ABC_LET 26 void makeABC(char abc[NUM_ABC_LET]); int main() { char abcString[NUM_ABC_LET + 1]; makeABC(abcString); puts(abcString); return 0; } void makeABC(char abc[NUM_ABC_LET + 1]) { char letter; … Read more
You can check every element in the array and break if only the element is smaller than 100. And outside the loop print the message based on whether i – The loop counter- is equal to the size or not. If equal than all elements are greater otherwise one of them is smaller: int array[] … Read more
Looks like you’re using the php script to construct a sql statement. I do this all the time. Try something like: $galleryIds = implode(“,”,$galleries); $sql = “SELECT * FROM galleries WHERE id IN ($galleryIds)”; Cheers and please vote me up!! OK, Here’s an edit because it seems that the Stack thinks you’re going to use … Read more
The fundamental issue is that you’re creating multiple JSON strings (json_data = (json.dumps(response, indent=2))) and then adding them to an array (json_arr.append(json_data)), and then converting that array to JSON (json.dump(json_arr,outline)). So the result is a JSON array of strings (containing JSON). You don’t want to create a string before adding to the array, just include … Read more
You can’t capture elements from an array like you want. Either do it the traditional way: var arr = calcualteMyAge(myDob); var age = arr[0]; var rang = arr[1]; Or with ES6 you can use destructuring: const [ age, rang ] = calcualteMyAge(myDob); 4 solved Multiple value returned in JS/How to access an array of returned … Read more
While you can achieve this with a bash script, probably the easier way is to use the xargs utility. xargs -L 1 ./myscript.py <inputfile The bash way would be: while read line do ./myscript $line done <inputfile solved text file each line to command in bash [closed]
Use DispatchQueue.main.asyncAfter(deadline: .now() + 3) { test.append(number) } 1 solved Create the tail of the Snake in a Snake Game – swift [duplicate]
void is not a complete type. It is only used either in a function definition to state that it either takes no parameters or returns no value, or as a generic pointer i.e. void *ptr. As such, a variable of type void cannot exist. solved C: error: array has incomplete element type ‘void’ [closed]
Simplest solution if all arrays have same length: string rowFormat = “{0,15}|{1,3} {2,3}”; Console.WriteLine(rowFormat, “History”, “B”, “W”); Console.WriteLine(new String(‘=’, 25)); for(int i = 0; i < array1.Length; i++) Console.WriteLine(rowFormat, array1[i], array2[i], array3[i]); But I would suggest to use custom type for your data instead of keeping data in three arrays. E.g. (names according to your … Read more
How about this solution #include<stdio.h> int main() { int i; int arr[]={ 2, 1 ,4 ,3 ,6 ,5 ,8 ,7 ,9}; int arr_size = sizeof(arr)/sizeof(arr[0]); int sorted[arr_size]; int sp = 0; for(i=0;i<arr_size;i++){ if(arr[i]&1){ sorted[sp++]=arr[i]; } } for(i=0;i<arr_size;i++){ if(!(arr[i]&1)){ sorted[sp++]=arr[i]; } } for(i=0;i< arr_size ;i++) printf(“%d “, sorted[i]); return 0; } the output is 1 3 … Read more
You get the error : Warning: array_push() expects parameter 1 to be array, null given because your $_SESSION[‘messages’] variable is never set. When this part of your code gets executed, session_start(); if (session_status() == PHP_SESSION_NONE) { $_SESSION[‘messages’] = array(); } The first line starts a new session. So session_status() == PHP_SESSION_NONE will never be true … Read more
Consider this: var date = “11252017”; var arrDate = date.ToArray(); var strDate = arrDate[0] + arrDate[1] + “https://stackoverflow.com/” + arrDate[2] + arrDate[3] + “https://stackoverflow.com/” + arrDate[4] + arrDate[5] + arrDate[6] + arrDate[7]; // 98/25/2017 Notice that: ‘1’ + ‘1’ = 98* ⇒ char + char = int 98 + “https://stackoverflow.com/” = “98/” ⇒ int + … Read more