Use an object and sort it using a sort function const results = { ‘UserA’: { points: 490 }, ‘UserB’: { points: 26 }, ‘UserC’: { points: 175 }, ‘UserD’: { points: 67 } } const rank = Object.entries(results) .sort(([, a], [, b]) => b.points – a.points) .map((item, i) => { results[item[0]].rank = (i + … Read more
Fixed number for all index var array = [0, 1, 2, 3]; array.map( function(n){ return (n* number to be multiplied); } ); Different number for each index var array = [0, 1, 2, 3], numberToBeMultiplied = [1,3,5,7]; array.map( function(n, i){ return n * numberToBeMultiplied[i]; }); You can also push the returning elements in an array. … Read more
I think you need something like bellow. You have a JSON like bellow. var data = {“dTableRowData”: [ { “id”: “1”, “rowData”: [ “tt”, “Sep13, 2010” ], “action”: [ { “hrefvar”: “aaa”, “label”: “fff” }, { “hrefvar”: “bbb”, “label”: “Details” }, { “hrefvar”: “ccc”, “label”: “View” } ] } ]} You want to get an … Read more
You can use array_map(“array_unique”, $array); For more information on array_map() you can visit PHP’s Docs. 1 solved Remove Duplicates in array php
The following code snippet is a very basic example of how something like this could be designed – it should give you a basic idea of how it could be expanded, to add more details to the cases or maybe add some other methods such as only viewing a specific case carrying a certain name … Read more
For a start, here is the original ArregloBinario class with the spacing fixed up: package laboratorio9; import java.util.Random; import java.util.Arrays; public class ArregloBinario { private int[] datos; private static Random generador = new Random(); public ArregloBinario (int tamanio) { datos = new int[tamanio]; for (int i=0; i<tamanio; i++) datos[i] = 10 + generador.nextInt(90); Arrays.sort(datos); } … Read more
Here in above image of structure of your JSON you should better use http://jsonviewer.stack.hu/ and paste your json here to view and understand its structure and then can use GSON or any other library to parse it and get what you want out of it 2 solved How to parse this? [closed]
The Basic Idea So with this solution, it’s quite simple, you have your dictionary, then you make a slight change to each object within the dictionary, you basically add some string to it so that if a word is ‘card’, it’ll swap the order of the letters in such a way that when you search … Read more
function Case(values){ console.log(“values: ” + values); var A = []; var B = []; var C = []; var i = 0; while(i < values.length) { A.push(values[i++]); B.push(values[i++]); C.push(values[i++]); } console.log(“A: ” + A); console.log(“B: ” + B); console.log(“C: ” + C); } var values = [5, 4, 3, 6, 7 , 8]; Case(values); values … Read more
Check the exit condition of your for loop: for (int i= 0; i> num_proyect_act; i++) { // … } 2 solved arrayindexoutofbounds exception processing [closed]
<?php $sum1 = 0; $sum2 = 0; foreach($array[‘a’] AS $smallArray){ $sum1 += $smallArray[‘x’]; } foreach($array AS $smallArray){ $sum2 += $smallArray[‘h’][‘n’]; } solved find the sum of array value [closed]
data_tab.sort(function(a,b){return a[0]-b[0];}); solved Array sort in javascript [closed]
Since you can use C++, the default option for storing an array of integers is std::vector: std::vector<int> wave; for (int i = 0; i <= 4000; i += 100) wave.push_back(i); If you want to have a C array as the result (e.g. for compatibility with other code that uses such arrays), because you know the … Read more
There are a few issues with your code. Firstly, using single quotes (‘) instructs PHP to NOT interpolate values. Secondly, I suspect that your data value will never actually update as the values in $active change. Also, you should be using class=”active” not simply adding the word ‘active’ into your li element. A more effective … Read more
You haven’t mentioned what error you are getting. But I see these problems: The declaration char name = “Elham”; is incorrect. It should be char *name = “Elham”; The if condition in your code is missing parentheses. if s[h] == ‘\0’ return -1; should be: if (s[h] == ‘\0’) return -1; Hope this helps! 2 … Read more