I figure out what the error is for those in future who might be banging their head wondering what went wrong. It’s actually really simple. A small typo actually. Too bad M$ have horrible error message that don’t really tell you where the error might have happened: Simply replace this line: public void GetObjectData(SerializationInfo info, … Read more
I recommend for you the SharedPreferences. This is an in Android simple class, that stores you data in Key-Value sets. Here is the code: SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(getApplicationContext()); This initialize your SharedPreferences. If you want to write/change a value, do this: SharedPreferences.Editor editor = sharedPref.edit(); editor.putInt(“KEY_TO_VALUE”, 123); editor.commit(); You also can put in there other … Read more
Impossible to answer because you haven’t given us anywhere near enough information. But your code does give one potential clue. use CGI qw/:standard/; use DBI; print “Content-type:text/html\n\n”; print first(); print myform(); print second(); sub myform { return <<B; <form action=” method=’post’> <img src=”https://stackoverflow.com/questions/26614013/images/img0001.gif” id=”Shape1″ align=”top” alt=”” title=”” border=”0″ width=”1344″ height=”126″> … </form> B } You … Read more
You can use either “0|5” or “[05]”. The first is an alternative, the second is a character class. They will behave identically. See the documentation for Pattern for more information on the building blocks for regular expressions. solved Java – Regex only 0 or 5 [closed]
Use sets! static int NumberOfDigits(int a) { return new HashSet<char>(Math.Abs(a).ToString()).Count; } We make a into a string and then turn the string into a set of characters. Since sets cannot contain duplicate values, the count of the set is the number of distinct digits. solved How to count the number of different digits in a … Read more
You could fill the Pits with Box Collidiers wich are marked as Triggers. Then you write a Script with void OnTriggerEnter(Collider other){ if(other.gameobject.tag == “Player”) //do something } Doku OnTrigger Enter That should do the Job 1 solved Unity3d how can i program my game?
.div { position: relative; overflow: hidden; padding: 50px 0; } .div-inner { position: relative; background: black; height: 120px; } .div-inner:before, .div-inner:after { box-shadow: 0 0 0 80px #000; border-radius: 100%; position: absolute; height: 150px; /* You can change it */ content: ”; right: -20%; left: -20%; top: 100%; } <div class=”div”> <div class=”div-inner”></div> </div> 0 … Read more
None of those two cases are right. Case 1 only worked because you got lucky, probably by giving a short string as input. Try something like “bfjabfabjkbfjkasjkvasjkvjksbkjafbskjbfakbsjfbjasbfjasbfkjabsjfkbaksbfjasbfkja” and you’ll suffer a seg fault, most likely. You should have a block of memory associated with str, either on the stack by declaring an array for it … Read more
try this: class CreatePages < ActiveRecord::Migration[5.0] def change create_table :pages do |t| t.string :name t.text :description t.text :address t.text :contact t.string :profile_image t.string :cover_image t.string :look_book t.integer :seller_id t.timestamps end end end solved Error undefined methode ‘interger’ when make migrate [closed]
Try this System.out.println(“originaltext”.replaceAll(“.{1}”,”$0ry”)); The above is using the String replaceAll(String regex, String replacement) method – “Replaces each substring of this string that matches the given regular expression with the given replacement.” “.{1}” – The regular expression used to find exactly one occurrence({1}) of any character(.) “$0ry” – The replacement string with “$0” for the matched … Read more
Lists don’t take name-value pairs. You probably want dictionaries here instead: definitions = { ‘title_label’: { ‘text’: (236, 218, 51), ‘background’: (125, 142, 246) }, ‘start_button’: { ‘text’: (32, 40, 145), ‘background’: (236, 235, 136), ‘pressed’: (44, 51, 112) }, ‘quit_button’: { ‘text’: (166, 21, 13), ‘background’: (48, 61, 188), ‘pressed’: (31, 40, 129) } … Read more
That’s because BufferedReader.readLine() reads only a line not the whole file. I assume that the line break characters \r and \n are not part of the normal content you interested in. Maybe that helps. // … StringBuilder sb = new StringBuilder(); String line; while ((line = inputStream.readLine()) != null) { sb.append(line); // if enough content … Read more
There are many possible solutions to this problem. Here’s a reusable solution that simply decrements from 4 to 1 and adds the expected number of 1’s and 0’s. Loops used : 1 def sequence(n): string = “” for i in range(n): string+=’1’*(n-i) string+=’0’*(n-i) return string print sequence(4) There’s another single-line elegant and more pythonic way … Read more
Think of it as a greedy algorithm, it will take as many characters as possible, if they make sense. Example: i+ // good, keep going i++ // good, keep going i+++ // not good, start new token + // good, keep going +- // not valid, start new token – // good — // good … Read more
In your example you can have TWO different causes for the NullReferenceException: – Value `user` is null; – `user.FirstName` is null. I assume you’ve checked already if user is not null, so lets skip that one. Now lets assume that user.FirstName is null, what happens then? The first condition string.IsNullOrWhiteSpace(user.FirstName) will result to true. Is … Read more