When you call a function recursively, they add the new function to a stack until have a final result (return). When it occurs, you go back return by return in the stack. An Execution example: First Round wacky(4, 6): 4 <= 1? No, so call wacky(4 – 1, 6 – 1) Second Round wacky(3, 5): … Read more
You can turn a string into code by using pythons eval function, but this is dangerous and generally considered bad style, See this: https://stackoverflow.com/a/661128/3838691. If user can input the string, they could input something like import subprocess; subprocess.check_call([‘rm’, ‘-rf’, ‘*’], shell=True). So be sure that you build in reasonable security into this. You can define … Read more
Hi!This is your code without errors! So, I changed somethings, I’ll list them to get clearer. To use “Name” and “Id” in more than one method, it is easier if they are global variables. When calling the “test” method you need to pass the values, so in the “entry” method the values are passed. The … Read more
AppleScript is not the right tool for this job, so while the following solution works, it is sloooow. (For better performance, you’d need full hash-table functionality, which AppleScript doesn’t provide – AppleScript’s record class is severely handicapped by the inability to specify keys dynamically, at runtime, via variables – third-party solutions exist, though (e.g., http://www.latenightsw.com/freeware/list-record-tools/)). … Read more
a and b are the solutions of: X^2 – nX + x = 0 d = n*n – 4*x a = (- b – d**0.5)/2 b = (- b + d**0.5)/2 1 solved Solve a simultaneous equation with product of the 2 variables in Python?
Use == not = if (num == 1) { system(“start C:\\test\\vw”); Sleep(2000); } else if (num == 2) { system(“start C:\\test\\vw2”); Sleep(2300); } else if (num == 3) { system(“start C:\\test\\vw3”); Sleep(1800); } == is for comparison, = is for assignment The reason why it always chooses the first option is because C++ (and C) … Read more
As I said in my answer to your previous question, you can fix this easily by using single quotes on the inside. PHP Code <?php $eff=40; $pos=34; $i = ‘hello’; $line=exec(“tail $i.dssp -n $eff | awk -F’ ‘ -v var=$pos ‘{if ($2==var) print FNR}'”); print “$line\n”; ?> Sample Input (hello.dssp): foobar 34 Sample Output: 1 … Read more
You have to use commas between the css selectors. And as the other people say, important was spelled wrongly. Furthermore, as radiation said, no <tbody> tag is present in your page or table, therefore nothing is selected by the css. Additionally remove the Khmer part from the font-family, as it might not be recognized. #content-area-job-details, … Read more
The modulo operator, more or less, just gives you the remainder of the division. So: 12 % 4 = 0 since 12 / 4 = 3 remainder 0 Whereas, since 12 doesn’t divide 4: 4 % 12 = 4 since 4 / 12 = 0 remainder 4 For more information, see the Wikipedia article, or … Read more
You can simply do it as Task.Delay(delay).Wait() 1 solved Delay in a task
There’s nothing wrong with having a while loop inside a for loop. To demonstrate: i = 0 kebab = [“chicken”,”garlic”,”cheese”,”tomato”,”lettuce”,”chilli”] print “Kebabs are so good, this is what mine has:” excitement_over_kebab = 1 for ingredients in kebab: while excitement_over_kebab == 1: print kebab[i] i+=1 if i == 6: print “Enough talk, my lunch break is … Read more
The service has been shut down since April 2011. You can use Yahoo! Search BOSS instead, but you’ve to pay for it. You may consider switching to Google Custom Search which is free up to 100 queries per day, afaik. solved Searching in yahoo using java [closed]
change for (int i = 0; i <= resultArray.size(); i++) { into: for (int i = 0; i < resultArray.size(); i++) { you can use for(String s: resultArray){…} as well, if you don’t care about the index so much… 1 solved ArrayIndexOutOfBounds in android [duplicate]
I’m guessing you want to call two functions on onchange. Try this: newcell.childNodes[0].setAttribute(“onchange”,function(){ showUser(this.value,”+xx+”); secondFunction(); }); or since you tagged this jQuery, do it the jQuery way: $(newcell.childNodes[0]).change(function(){ showUser(this.value,”+xx+”); secondFunction(); }); 1 solved join 2 same almost same function into 1 [closed]
just upload the new APK and remember to change the Version in the manifest 4 solved How to “UPDATE” Application in the google play developer console? [closed]