[ad_1] I tried to understand your question but it is hard to visualize exactly what you want. So I’ll just clean and update your code (i.e. bring it into the 21st Century). Please don’t use the <font> tag or the align attribute anymore. It’s 2016. If this is a heading, use <h1>, not <p>. Tags … Read more
[ad_1] This is quite easy to o actually. Requirement #1 and #3 are the easiest. To test for whether a string contains two words and are separated by exactly one space, just use the split method. For requirement #2, test if the strings have a length that is larger than 2. Let’s say your string … Read more
[ad_1] Then create a hashmap and whenever updation takes place save the data in hashmap. Inherit getItem(int index) method in adapter with HashMap as return type & and return the data in that method for corresponding index. HashMap<String, Object> hashMap = new HashMap<String, Object>(); @Override public HashMap getItem(int i) { return hashMap.get(i); } Like if … Read more
[ad_1] Though, the question is not very clear, but here is my attempt to give you initials, as per my understanding. var sentence = $(‘div#content’).text(); var words = sentence.split(‘ ‘); var spanWords = []; $(words).each(function(i,word){ if($.trim(word).length) { var span = $(‘<span>’); span.text(word); spanWords.push(span) spanWords.push(‘ ’) } }); $(‘div#content’).html(spanWords) var start = function(element){ if(element.next().length){ setTimeout(function(){ element.css({color: “#000”}); … Read more
[ad_1] Use below method public static void openFragment(FragmentManager manager, Fragment targetFragment) { try { String fragmentName = targetFragment.getClass().getName(); manager.popBackStack(); manager.beginTransaction() .replace(R.id.frameLayout, targetFragment, fragmentName) .addToBackStack(fragmentName) .commit(); } catch (Exception e) { e.printStackTrace(); } } call this method each time when you are opening your fragment. You have to pass two params to this method. targetFragment is … Read more
[ad_1] As you now accepted to use RegEx, I adapted the solution based on this post https://stackoverflow.com/a/16707675/4339170: function validate() { var p = document.getElementById(‘pass’).value var errors = [] //if (p.length < 8) { // errors.push(“Your password must be at least 8 characters”) //} if (p.search(/[a-z]/) < 0) { errors.push(“Your password must contain at least one … Read more
[ad_1] getPosition is non-const in the interface class, but const in your derived class. These are two different functions and cause your problem. Adding the override keyword in the implementation class (if your compiler supports it) will flag this sort of problem. 0 [ad_2] solved C++ cannot instantiate abstract class
[ad_1] You can get CustomerMapping by cardId using JPQL. A more optimal solution will be to use projections. public String getCustomerMappingCustomerId(String cardId) { getEntityManager(); CustomerMapping result = first(em.createQuery( “select c from CustomerMapping c where c.cardId = :cardId”) .setParameter(“cardId”, cardId).getResultList()); return result == null ? null : result.getCustomerId(); } private static <T> T first(List<T> items) { … Read more
[ad_1] You’re accessing outside the vector. When you get to the last iteration of the for loop in bubbleSort(), numbers[i] is the last element of the vector, and numbers[i+1] is outside. This results in undefined behavior, and in your case it happens to access the -1 that you initially put in the vector and then … Read more
[ad_1] Try with following code: <script> $(document).ready(function(){ $(“[id^=tolevel_]”).click(function(){ var currentID = $(this).attr(“id”); var number = currentID.replace(“tolevel_”,””);//get the number in string format number = parseInt(number); var i = number -1; $(“#level_” + i).hide(500,’swing’, function(){ $(“#level_” +(i+1)).show(500, ‘swing’, function(){ }); }); }); $(“[id^=backtolevel_]”).click(function(){ var currentID = $(this).attr(“id”); var number = currentID.replace(“backtolevel_”,””);//get the number in string format number … Read more
[ad_1] I’ll go over your points one by one: Declare long presult; right before the try statement. This makes the compiler mad because it wrongly thinks there’s a possibility of returning an unintialized variable. Actually, the compiler correctly determines that there is the possibility of returning an uninitialized variable. Since the variable is only set … Read more
[ad_1] a VM is a virtual machine. In simple words, it is virtual hardware(emulator) to run your virtual devices. from Wikipedia: In computing, a virtual machine (VM) is an emulation of a particular computer system. Virtual machines operate based on the computer architecture and functions of a real or hypothetical computer, and their implementations may … Read more
[ad_1] C++ error: Reference to non-static member function must be called, Please help, don’t know whats literally wrong [closed] [ad_2] solved C++ error: Reference to non-static member function must be called, Please help, don’t know whats literally wrong [closed]
[ad_1] I don’t know Node.js but in javascript it can be done using split() var content = “Hello \n bob \n ben je op deze \n world \n bobert”, content_array = content.split(“\n”); content_array.forEach(function(entry) { document.write(“<content>’+entry+'</content><br />”); }); 1 [ad_2] solved javascript finding a string in a string
[ad_1] The Comparable interface is used to compare two objects and their order. As per the Javadocs, the compareTo method should return 0 if the two objects are equal, any negative number if this object is “smaller” than the specified other, and any positive number if this object is “larger” than the specified other. What … Read more