Kirat I asked the same question at Vue.js forum and got the correct answer. Please refer to https://forum.vuejs.org/t/cannot-get-data-from-axios-request/18977 solved Vue.js cannot set data returned from external axios response
valueArray is a multidimensional array of objects, according to your parameter definition. switch does not support that. You can’t and wouldn’t perform a switch on an array of values; switch operates on a single value. You can use foreach to flatten the array, iterate over each value, and apply the switch, however… As the error … Read more
In .NET you could do use the AddMonths method: DateTime date = new DateTime(2013, 5, 19); DateTime newDate = date.AddMonths(14); As far as parsing a date from a string using a specified format you could use the TryParseExact method: string dateStr = “19/05/2013”; DateTime date; if (DateTime.TryParseExact(dateStr, “dd/MM/yyyy”, CultureInfo.InvariantCulture, DateTimeStyles.None, out date)) { // successfully … Read more
I’m not sure what you are going for exactly but this is your problem in your loop t == 5 it should be something like for(int t = 1; t <= 5; t = t+1) { t is never 5 here so it will never iterate. Also, you can simplify the last part so it … Read more
Solution simple as always: void RemoveDuplicates (std::string& input) { std::string::iterator it = std::unique(input.begin(), input.end()); input.erase(it, input.end()); std::cout << “New input = “<< input << std::endl; } Another solution to return a new string: std::string RemoveDuplicates (const std::string& input) { std::string newT(input); std::string::iterator it = std::unique(newT.begin(), newT.end()); newT.erase(it, newT.end()); return newT; } If desired result is … Read more
You can use Pattern and Matcher: String input = “Java: split text [duplicate],[description blablablablablabla]”; Pattern pattern = Pattern.compile(“\\[(.*?)\\]”); Matcher matcher = pattern.matcher(input); ArrayList<String> stringList = new ArrayList<String>(); while(matcher.find()) { stringList.add(matcher.group(1)); } //If you just need the results to be stored in an array of Strings anyway. String[] stringArray = stringList.toArray(new String[stringList.size()]); 1 solved Java: split … Read more
You can use this code for getting mouse position and posting request: $(“#target”).mousemove(function(event) { $.post(“test.php”, {x: event.pageX, y: event.pageY}); }); If you need help with doing something with position in PHP, you can ask me. solved Mouse position with Ajax in PHP [closed]
Try using std::max_element from <algorithm>: #include <algorithm> int i[] = { 1, 84, 11, 31 }; // for C++11 and later: int max = *std::max_element(std::begin(i), std::end(i)); // for C++03 or earlier: int max2 = *std::max_element(i, i + (sizeof(i) / sizeof(*i))); or if your array is static, you can just use an C++11 initializer list: auto … Read more
You try to add this listener to the onCreate event: myCustomView.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() { @Override public void onGlobalLayout() { myCustomView.getViewTreeObserver().removeOnGlobalLayoutListener(this); do_your_logic_to_save_bitmap_from_view; } }); addOnGlobalLayoutListener will register a callback to be invoked when the global layout state or the visibility of views within the view tree changes. For example when the view is rendered completely. 3 solved … Read more
Depth First Search or DFS as it is more generally called is a graph/tree traversing algorithm. How It Works Consider a graph such as given below Now let’s dig deep into how these numbers are coming up. We start with the starting node and mark it as visited then we add it to the top … Read more
I would do this for the links <%= ([1,2,3]- [params[:x]]).each do |link_number| %> <%= link_to “Version #{link_number}”, “/page?x=#{link_number}” %> <% end %> This way everytime the page is loaded the link to the other 2 versions will exist. You could handle the partials through the controller (which seems better) or use something like: <%= render … Read more
a==1. And then, i==2 It would be a==2 if you did a=++i solved a = i++; does `a` equal `i`?
Instead of overwriting the same variable, cb, try using an iterable type such as dictionary. You should also need to be attaching the value of Checkbutton to a tkinter variable class, such as BooleanVar, in order to easily track its status & value. The code below produces a GUI that re-writes Text each time a … Read more
I would use Highcharts.SVGRenderer to draw rect elements, based on the ticks from the second xAxis and translate the labels. Please check the example below: chart: { events: { render: function() { var ticks = this.xAxis[1].ticks, x = this.plotLeft, y = 378, width, color=”blue”, textColor=”yellow”, height = 28; if (!this.customTicks) { this.customTicks = []; } … Read more
I’m going to demonstrate required steps to cook a regex for word help but the requirements are not clear, rules are not strict hence some drawbacks are usual. \bh+[a-z&&[^e]]*e+[a-z&&[^le]]*l+[a-z&&[^ p l e ]]*p+\b ^ ^^ ^ ^ ^ | || | |–|-> [#2] | || |-> [#1] | ||-> Previous char(s) [#2] | |-> [#1] … Read more