[Solved] Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index (mentioned code) [duplicate]

[ad_1] Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index (mentioned code) [duplicate] [ad_2] solved Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index (mentioned code) [duplicate]

[Solved] class object initialization in c++

[ad_1] For case 1 the A object instance is created on the heap, while the location of the variable c depends on if it’s a global, member or local variable. [Note: Question edited, case 2 totally different]For case 2 no object is created, as it is a function declaration. For case 2, the location of … Read more

[Solved] Converting c# to VB [closed]

[ad_1] You should try with this free online tool: http://www.developerfusion.com/tools/convert/csharp-to-vb/ It converts C# to VB.net (and vice versa) and has served me well in the past, apart from some rare unhandled cases it has always done a correct conversion for me. As for analyzing your code: if you don’t include the original C# to make … Read more

[Solved] What’s the difference between ‘==’ and ‘in’ in if conditional statements?

[ad_1] The first statement if keyword.lower() in normalized: is checking if keyword.lower() string is one of the elements inside the list normalized. This is True. The other statement if keyword.lower() == normalized: is checking if keyword.lower() string has same value as normalized list. This is False. 1 [ad_2] solved What’s the difference between ‘==’ and … Read more

[Solved] How to split int in a 5 random numbers? [closed]

[ad_1] I hope you will still edit your question with some more criteria and what you have tried so far, however, following implementation follows: No 0 numbers ; The resulting array should be exactly the requested numbers long ; It doesn’t check if the division is possible, theoretically, the targetNumber – totalSumNumbers >= 0 has … Read more

[Solved] Extracting objects from a list by quantity [closed]

[ad_1] If you are using java-8 or later then List<Drink> list = new ArrayList<>(); list.add(new Drink(“coke”, 30)); list.add(new Drink(“fanta”, 10)); list.add(new Drink(“coke”, 5)); list.add(new Drink(“sprite”, 1)); list.add(new Drink(“coke”, 10)); Map<String, Integer> map = list.stream() .collect(Collectors.groupingBy(Drink::getName, Collectors.summingInt(Drink::getAmount))); System.out.println(map); output {sprite=1, coke=45, fanta=10} Collection<Drink> c = list.stream().collect(Collectors.groupingBy(Drink::getName, Collectors.collectingAndThen( Collectors.reducing((Drink a, Drink b) -> { a.setAmount(a.getAmount() + b.getAmount()); … Read more

[Solved] MS Access 2007 : the code vba not running

[ad_1] Option Access –> Centre de gestion de la confidentialité –> paramètres du Centre de gestion de la confidentialité –> paramètres des marcos –> (coché le dernier choix) activer toutes les macros … et OK voilà la réponse [ad_2] solved MS Access 2007 : the code vba not running

[Solved] Can’t call a function in viewDidLoad [closed]

[ad_1] Your addMarker has an extra bracket. func addMarker(place:EClass) { guard let coordinates = place.location else { return } self.destination = coordinates // clear current marker marker.map = nil marker.position = coordinates marker.title = place.name marker.map = mapView mapView.selectedMarker = marker } 7 [ad_2] solved Can’t call a function in viewDidLoad [closed]

[Solved] How to extract string using RE in python?

[ad_1] seems like a crazy question but why not >>> myval=”ObjectId(“5a60a394ac73c233ba1acc55″)” >>> myval.split(“(“)[1] ‘”5a60a394ac73c233ba1acc55”)’ >>> myval.split(“(“)[1].split(“)”)[0] ‘”5a60a394ac73c233ba1acc55″‘ >>> import re >>> re.findall(‘[a-zA-z0-9]’, myval.split(“(“)[1].split(“)”)[0]) [‘5’, ‘a’, ‘6’, ‘0’, ‘a’, ‘3’, ‘9’, ‘4’, ‘a’, ‘c’, ‘7’, ‘3’, ‘c’, ‘2’, ‘3’, ‘3’, ‘b’, ‘a’, ‘1’, ‘a’, ‘c’, ‘c’, ‘5’, ‘5’] >>> “”.join(re.findall(‘[a-zA-z0-9]’, myval.split(“(“)[1].split(“)”)[0])) ‘5a60a394ac73c233ba1acc55’ [ad_2] solved How to … Read more