Kirat[ad_1] Because of this: $i=($num_dates-1) You need to check the condition ==, not use an assignment =. Although in this case it appears you want to do something like this: $i <= ($num_dates-1). You may have just forgot to type <. 1 [ad_2] solved Formatting php for-loop
[ad_1] int main(int argc, const char* argv[]) { for(int i = 0; i < argc; ++i) { // argv[i] contains your argument(s) } } Some more details: Accepting arguments passed to your program can be done by adding two arguments to main: One int, which is assigned the number of arguments you give to your … Read more
[ad_1] If your data actually looks like this: var data = new { Desc = “Marketcap”, Val = @”1,270.10 BTC 706,709.04 USD 508,040.00 EUR 4,381,184.55 CNY 425,238.14 GBP 627,638.19 CHF 785,601.09 CAD 72,442,058.40 JPY 787,357.97 AUD 7,732,676.06 ZAR”, }; (Because what you have in your question is unclear.) Then you could do this: var query … Read more
[ad_1] You are reading a RTF Document. If you want to read the text only you can try reading it into a byte array and parsing out the text using swings rtfeditorkit. Path path = Paths.get(“path/to/file”); byte[] data = Files.readAllBytes(path); RTFEditorKit rtfParser = new RTFEditorKit(); Document document = rtfParser.createDefaultDocument(); rtfParser.read(new ByteArrayInputStream(data), document, 0); String text … Read more
[ad_1] The steps shown in the question will actually create and install a real package. It won’t create any importable files, but it will create metadata in a site-packages directory. Exactly where it has installed depends on your USER_SITE configuration, which you can check with python3.6 -m site, but it’s probably going to be at … Read more
[ad_1] Trim the string and then check for space var hasMultipleWords = input.trim().indexOf( ” ” ) != -1; //returns true if there is a space 1 [ad_2] solved To know if a string is composed of a word or two words [duplicate]
[ad_1] The simplest solution is the below one. str = “0x00000000 7B 22 69 64 22 3A 36 35 33 30 36 36 33 7D {“”id””:2133221}” arr = Split(str, “:”) strID = Left(arr(1), len(arr(1)) – 1) msgbox strId However, If you still need a more robust one, try regex 3 [ad_2] solved Extract Text from … Read more
[ad_1] As there´s no type that is neither a class nor a struct, applying both constraints to your member is redundant. Thus you can simply omit it completely, making your method work on any T. public static int MyMethod<T>(this List<T> list) { int result = //do something return result; } Apart from this you can … Read more
[ad_1] The old traineddata files can be found at https://sourceforge.net/projects/tesseract-ocr-alt/files/. [ad_2] solved Matlab – OCR Languages Support Package Installation [closed]
[ad_1] I go about it by providing different states for your page (eg. loading, loaded, and error). And passing in a status parameter, then using css to add a display: none class to it. (the hide class is display: none) function setStatus(status) { document.getElementById(“loading”).classList.add(“hide”); document.getElementById(“contents”).classList.add(“hide”); if (status == “loaded”) { document.getElementById(“contents”).classList.remove(“hide”); } if (status == … Read more
[ad_1] This worked for me: Select * from Addresses Where Addresses.Longitude between -80.33313094482423 and -79.5290690551758 And Addresses.Latitude between 32.6420709033305 and 32.91052662576775 1 [ad_2] solved Returning results within Latitude / Longitude rectagle
[ad_1] If you want Vanilla JavaScript solution you can try this: function startCalc() { var root = document.documentElement || document.body; root.addEventListener(‘blur’, function(e) { var node = e.target; if (node.nodeName == ‘input’ && node.getAttribute(‘type’) == ‘text’) { var imekontrolebase = node.getAttribute(‘id’); var ime = imekontrolebase.substr(12, imekontrolebase.length); var n = ime.indexOf(“_”); var red = ime.substr(n+1); var imekol1 … Read more
[ad_1] Morty, Jethro, Fido etc. are not different “yoctos”, but different releases given the timeline of the project. Generally, pick the most current that is available, as it is the most actively maintained one. (At the current moment in time, Rocko is the stable release) [ad_2] solved Which yocto is best for me
[ad_1] Try this after renaming the referenced worksheet. Sub expandMonths() ‘https://stackoverflow.com/questions/52304181 Dim i As Long, j As Long, m As Long, a As Variant With Worksheets(“sheet1”) i = .Cells(.Rows.Count, “A”).End(xlUp).Row Do While i > 1 a = Array(.Cells(i, “A”).Value2, .Cells(i, “B”).Value2, 0, 0, 0, 0) m = .Cells(i, “C”).Value2 j = Application.Match(.Cells(i, “A”).Value2, .Columns(“A”), 0) … Read more
[ad_1] // Thanks for the help #include <stdio.h> int repeat(int num) { scanf(“%d”,&num) ; if(num!=42) { printf(“%d”,num) ; repeat(num) ; } else { return num ; } getch() ; } int main() { int num ; scanf(“%d”,&num) ; repeat(num) ; return 0; } [ad_2] solved Why doesn’t control enter the repeat() function? [closed]