Without looking at the way values are computed, the main issue is that, in your output functions, you are doing integer arithmetic to compute a value that is smaller than 1. For example, in OutputQuizz, (Q1 + Q2 ) / 20 will usually be less than 1. To force the compiler to use floating point, … Read more
property_object_parse is a real JavaScript object, so you can just use the member access syntax to access the value you are interested in directly: console.log(property_object_parse.p1.TextElement[0].size); Note that you cannot use a dynamic property path string like ‘p1.TextElement[0].size’, you would have to compile that in a way. For example, you could instead have an array of … Read more
a_row is containing all the rows of the two dimensional array and you are accessing a_row[i] where i value of the row and you have no a_row[3] in your code change like following for(int[] a_row: a){ for(int index=0; index < a_row.length; index++){ a_row[index]+=1; } } for(int[] a_row: a){ for(int i: a_row){ System.out.print(i+”\t”); } System.out.println(“\n”); } … Read more
Ok, you basically have it right, but you are not yet multiplying the argument value. So your function should be double functionXYZ (double data) { return data * 10; } The type before the function name determines its ‘return type’ (what type of variables can be expected to be returned by this function). In this … Read more
How do I create a C++ code that will allow a user to enter several percentage grades and then display the corresponding letter grade? solved How do I create a C++ code that will allow a user to enter several percentage grades and then display the corresponding letter grade?
I’m pretty sure Toddler Lock just uses a BroadcastReciever and listens for Intent.ACTION_MAIN and the category Intent.CATEGORY_HOME – that’s why when you first launch it, it tells you to check the “use this application as default” box, and makes you select toddler lock. So, it’s not really blocking the Home button at all, it’s just setting itself up as … Read more
There are a lot of issues with your code. I altered the function isPrime. There is among other no need for count here and if you want to increment test by 1 every loop use test +=1: def isPrime(value): test = 2 while(test < value): if( value % test != 0): test +=1 else: return … Read more
Why doesn’t the code print out “prime” when i use ‘C =1;’ but when i dont give any values to ‘C ‘ initially it works perfectly fine? [closed] solved Why doesn’t the code print out “prime” when i use ‘C =1;’ but when i dont give any values to ‘C ‘ initially it works perfectly … Read more
The simple answer: (?!^)\b[A-Z]\w* It matches any capitalized word that isn’t at the beginning of the line (checked using a negative look-ahead and a word boundary). See it here at regex101. But your requirements are sketchy… John and I are good friends. would return I. Is that really what you want? And it’ll only work … Read more
Test it in a console app. Remove things such as it being in run on the UI thread, and being run inside UI controls’ event handlers. Also, the act of displaying the message is huge overhead, so leave it out as it’s done in each method. All you really want to test is the performance … Read more
I’m not sure if there is a way to short-circuit the Regex engine that way. You can use the control verbs (*FAIL) to immediately fail a match or (*LIMIT_MATCH=x) to limit the number of matches you receive to a specific quantity, but I don’t believe there’s a way to dynamically tell the engine to just … Read more
All information available to your client (the app) is possible to extract, though some can be more difficult. As such, you should consider any such information public, and structure your security measures accordingly. In your specific example, the complex password doesn’t help much, since you will have to include the password in the code (or … Read more
The second one is always the better choice for readability, and the performance benefit (if one even exists) would be marginal using a switch statement. The < / > operators are probably an instruction or two of native code, and I can’t imagine that any switch statement would compile down to something so small. I … Read more
In an if else-if statement you put multiple conditions to evaluate the result. The following is how the statements will work in your case: if(row==1||row==n||row==2*n-1) cout<<“*”; //if true then put * or if false then move down else if (col==1&&row<n||col==n&&row>n) cout<<“*”; // if the first is false and the 2nd one is true then put … Read more
I don’t have the exact sensor as you, but this code is a snippet that I’ve been working on. You can look at it… Maybe it could help. If it did, then good 🙂 /* Project goal: Arduino built quadcopter. Motor diagram: Legend: num : motor number -> : clockwise <- : counter-clockwise 2 -> … Read more