I am trying to make login module in android studio but i got the error as following..(Column name doesn’t exist) [closed] solved I am trying to make login module in android studio but i got the error as following..(Column name doesn’t exist) [closed]
Actually figured it out – was very simple. NewDataFrame <- data.frame(colnames(Original)) solved R: create new dataframe rows are columns from another dataframe
EDIT: Sorry, misread your question. I thought you only wanted to keep these values. Changed my code accordingly. list1 = [“13:00″,”13:10″,”13:20″,”13:30″,”13:40”] range_start = “13:10” range_end = “13:30” You can use list comprehension with the range condition: list1 = [x for x in list1 if not(range_start<=x<=range_end)] print(list1) You could also use filter on your list: list1=list(filter(lambda … Read more
Nonlinear arbitrary-directional broadband piezoelectric vibration energy harvester using 3-DOF parallel mechanism by matlab [closed] solved Nonlinear arbitrary-directional broadband piezoelectric vibration energy harvester using 3-DOF parallel mechanism by matlab [closed]
Take a look at remove_if() #include <iostream> #include <algorithm> #include <string> using namespace std; int main() { string s; getline(std::cin,s); cout << s << endl; s.erase (std::remove_if(s.begin (), s.end (), ispunct), s.end ()); cout << s << endl; } 4 solved Removing punctuation from string of characters [closed]
How about using the basic base 10 to any base conversion, modified for custom digits: func numberToCustomRadix(_ number: Int, alphabet: String) -> String { let base = alphabet.count var number = number var result = “” repeat { let idx = alphabet.index(alphabet.startIndex, offsetBy: number % base) result = [alphabet[idx]] + result number /= base } … Read more
The problem you describe is actually a very difficult problem in general, since it is related to the knapsack problem. But it is only hard if you allow very large amounts of money on the card and very many different prices. For your real world problem with very few different prices you can solve this … Read more
Try it like, var ul = $(‘<ul>’).appendTo(‘body’); function createList() { ul.empty(); $(‘select option:selected’).each(function() { li = $(‘<li/>’).text($(this).text()).attr(‘value’, this.value); li.appendTo(ul); }); } $(‘select’).on(‘change’, function() { createList() }).trigger(‘change’); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js”></script> <select name=”is_format” id=”is_format”> <option value=”A4″>{l s=”A4″}</option> <option value=”A3″>{l s=”A3″}</option> </select> <select name=”is_color” id=”is_color”> <option value=”Couleur” selected>{l s=”Couleur”}</option> <option value=”Noir/Blanc”>{l s=”Noir et Blanc”}</option> </select> 3 solved Jquery Multiple … Read more
do this: import {Component} from ‘angular2/core’; import {CoursesComponent} from ‘./courses.component’ import {AuthorsComponent} from ‘./authors.component’ @Component({ selector: ‘my-app’, template: ‘<h1>My first Angular2 App</h1><courses></courses> <authors></authors>’, directives: [CoursesComponent, AuthorsComponent], }) export class AppComponent { } btw, update your code based-on latest Angular version as this tutorial https://angular.io/docs/ts/latest/guide/learning-angular.html include your directives, pipe and other components to declarations array. src/app/app.module.ts … Read more
span “Returns the longest prefix of the list whose elements all satisfy the given predicate, and the rest of the list.” the list here is the ls parameter and ls.head is the first item of the list The two lists are then assigned to packed (containing the longest prefix) and next which contains the rest. … Read more
You need to use $.ajax like $(function(){ function getdata(){ $.ajax({ url:’getdata.php’, success:function(response){ $(‘#dataTables-example tbody’).html(response); } }); } setInterval(function(){getdata()},5000); }); getdata.php <?php $req = mysqli_query($con, ‘select user_id, user_name from users’); while ($dnn = mysqli_fetch_array($req)) { echo “<tr> <td>” . $dnn[‘user_id’] . “</td> <td>” . $dnn[‘user_name’] . “</td> </tr>”; } ?> 6 solved Refresh table after seconds
If you are looking to search, you need to use the LIKE syntax, not WHERE $sql=”SELECT * FROM members WHERE FirstName LIKE ‘”. $fname .”%'”; The LIKE & % make it a wildcard. Now you said you want to search by first and last, but you only pass in your first variable and you only … Read more
Something like this should work: paid = Math.Min(total, payment+paid) 3 solved Can an algorithm for this be done in one line? [closed]
Your logic to print is fine, all you need to do is to wrap the code into a for loop and excute it from 1 to 100, e.g.: for(int zmienna = 0 ; zmienna <= 100 ; zmienna++){ if (zmienna % 5 == 0 && zmienna % 3 == 0) System.out.println(“FizzBizz”); else if (zmienna % … Read more
your instantiation must be inside a method check the following and under setContentView method TextView tvnum =null; Button btnMin=null; @Override protected void onCreate(Bundle savedInstanceState) //TODO solve runtime problem(E/AndroidRuntime: FATAL EXCEPTION: main) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); tvnum = (TextView) findViewById(R.id.TV_num);//creating object of TextView int id = 100;//id is first number of tv num btnMin = (Button) findViewById(R.id.btnMIN); … Read more