[Solved] searching sub string in string and check another string before that [closed]

Here ya go, use std::string::find: // Notice the double quotes std::string::size_type position = my_string.find(“34”); bool found = ((position != std::string::npos) && (position > 0) && (my_string[position – 1] == ‘6’)); The find method returns the position of substring, or std::string::npos if it is not found. The position must be greater than 0, because of the … Read more

[Solved] Me not understanding do while loops [closed]

If the number input isn’t one that you check (1 to 5) then you hit: else if (a == 1) { std::cout << “\n”; return 1; } which will enter the if (because a is 1), print a new line and return from main ending your run. solved Me not understanding do while loops [closed]

[Solved] How can the facet function in ggplot be used to create a histogram in order to visualize distributions for all variables in a dataset?

I’ve copied the data from your post above so you can skip the variable assignment library(“tidyverse”) df <- read.table(file = “clipboard”, header = T) %>% as_tibble() You need to modify your data structure slightly before you pass it to ggplot. Get each of your test names into a single variable with tidyr::gather. Then pipe to … Read more

[Solved] Double digit 30 seconds countdown

This is how you can proceed: <script type=”text/javascript”> var timeleft = 30; var downloadTimer = setInterval(function(){ timeleft–; document.getElementById(“countdowntimer”).textContent = “:” + ((timeleft >= 10) ? timeleft : (“0” + timeleft)); if(timeleft <= 0){ clearInterval(downloadTimer); window.location.replace(“next_slide.html”); } },1000); </script> 0 solved Double digit 30 seconds countdown

[Solved] How could a viable transformation look like that does convert a product-name into a valid HTML id-attribute value? [closed]

You can try this- const data = [ “2-inch leg extension”, “2′ x 8′ Overhead Garage Storage Rack”, “4 Drawer Base Cabinet 16-1/2\”W x 35\”H x 22-1/2\”D”, “24\” Long Tool Bar w/ Hooks Accessory” ]; const res = data.map(str => str.replace(/[^a-z\d\-_]/ig, ”)); console.log(res); If you need any prefix with the ID then add it like- … Read more

[Solved] Summarize data in array of objects by common date [closed]

Try this function function mapData(data) { let result = []; data.forEach(element => { let t = element.time + 9200; let substr = t.toString().substr(0, 8); if(!result[substr]) result[substr] = 0; result[substr] += element.count; }); let returnResult = []; result.forEach((element, index) => returnResult.push({ time: index, count: element }) ); return returnResult; } 2 solved Summarize data in array … Read more