Try to do this library(‘stringr’) apply(data, 1, function(x) str_c(x$columnnane,collapse=”,”)) where, data is you dataframe and columnname is the column containing list. edited answer out = do.call(rbind, lapply(data, function(x) str_c(x,collapse=”, “))) where data is your list object if the list is stored inside a dataframe then pass the column in place of the data above like … Read more
Well, for this example, you could use list comprehension with slicing. a = [[1, 2], [1, 2, 3], [1, 2, 3, 4]] b = [x[1:] for x in a] 0 solved Remove the first items in a list of lists – make a copy instead of modifying in-place
Driver info: driver.version: unknown at org.openqa.selenium.support.ui.Select.(Select.java:46) at com.myfirst.Main5.main(Main5.java:24) solved Driver info: driver.version: unknown at org.openqa.selenium.support.ui.Select.(Select.java:46) at com.myfirst.Main5.main(Main5.java:24)
You can simlpy cycle through the second array, split at :, check the first part and, in case of a match, return the second function findX(value, arr) { for (var i = 0; i < arr.length; i++) { var toSplit = arr[i].split(‘:’); if (toSplit[0] === value) { return toSplit[1]; } } } console.log(findX(“User1-2”, [“User1-2:280”, “User2-2:280”, … Read more
what have you tried so far? Try implementing a custom ListCellRenderer. More information here. 1 solved How to get multiline for a Jlist text? [closed]
The html, head and body elements are always going to be there. You can’t actually have an HTML page without them, even if you leave out the tags. The following two valid HTML documents are equivalent (whitespace notwithstanding): <!DOCTYPE html> <title>Image</title> <img src=”https://stackoverflow.com/questions/48771175/lightbulb.jpg” alt=””> <!DOCTYPE html> <html> <head><title>Image</title></head> <body><img src=”https://stackoverflow.com/questions/48771175/lightbulb.jpg” alt=””></body> </html> So even if … Read more
You got a bad example. Short answer: never(!) return a pointer from a binary function (operator). Return by value or a std::unique_ptr or std::shared_ptr. Note: The accepted answer in the link of the question changed afterward. 2 solved When should I return pointer to object (not an object) from the operator function?
Though your question is not very clear, it seems you just want o print the array index with contents, in that case you can follow the below code: for(int i=0;i<fruit.length;i++){ System.out.println((i+1)+”.”+fruit[i]); } Or if you want the number to store the index in the array contents, then you can go with: for(int i=0;i<fruit.length;i++) { System.out.print(“Fruit … Read more
This is basic of swift, I hope you designed it on LaunchScreen.storyboard which acts as the Splash screen of the application. Your problem is you designed your view in LaunchScreen.storyboard so it stayed only for 5 seconds, now the solution is design your view in Main.storyboard so that you will see your UIControls or UIElements. … Read more
If you are using typed datasets then you have to manually update them if you update your schema. 2 solved Visual Studio ignoring SQL changes in Visual Studio (C#) [closed]
First, you need to read the text file into a string; find the pattern “{([a-z|]+)}” using regex, split them by “|” to make a list as random words. It could be achieved as the following: import re, random seed = [] matches = re.findall(‘{([a-z|]+)}’, open(‘bio.txt’, ‘r’).read()) [seed.extend(i.split(‘|’)) for i in matches] input = random.choice(seed) solved … Read more
It sounds like you want to group the items by league. Let’s use our array_reduce friend for that. This is the basic syntax: $arr = [ [ “leauge” => “sweeden”, “fixture” => “12” ], [ “leauge” => “sweeden”, “fixture” => “13” ], [ “leauge” => “germany”, “fixture” => “14” ], [ “leauge” => “france”, “fixture” … Read more
I fixed some of your syntax. I don’t see anything completely wrong with your solution. Maybe the fixed syntax is all you need. private void button1_Click(object sender, EventArgs e) { double hour = (double)numHour.Value; double minute = (double)numMinute.Value; if (hour < 12 & rbPM.Checked) { hour = hour + 12; } else if(hour > 12 … Read more
Try to add a for loop to calcolate the sum of ages like this: for(i=0;i<age.length;i++){ sum+=age[i]; } And take out this below block out of for loop: avg= sum/age.length; System.out.println(“the avarage of all Students are :”+avg); System.out.println(“the minimum age of all Students : “+min); Like this: public static void main(String[] args) { // TODO code … Read more
SELECT c.ClientID, c.LastName, c.FirstName, c.MiddleName, CASE WHEN cudf.UserDefinedFieldFormatULink = ’93fb3820-38aa-4655-8aad-a8dce8aede’ THEN cudf.UDF_ReportValue AS ‘DA Status’ WHEN cudf.UserDefinedFieldFormatULink = ‘2144a742-08c5-4c96-b9e4-d6f1f56c76’ THEN cudf.UDF_ReportValue AS ‘FHAP Status’ WHEN cudf.UserDefinedFieldFormatULink = ‘c3d29be9-af58-4241-a02d-9ae9b43ffa’ THEN cudf.UDF_ReportValue AS ‘HCRA Status’ END INTO #Temp FROM Client_Program cp INNER JOIN client c ON c.ulink = cp.clientulink INNER JOIN code_program p ON p.ulink = cp.programulink … Read more