First, if you were looking for a null character you would probably want to do (char)0 because “” is an empty string (no character). Second, if Java uses a null character (they don’t have to IIRC) then they hide it. EDIT: Struck my third point because I’m not sure about it anymore. SECOND EDIT: I … Read more
You can try this: var str=”RANDOM1″; if(/^RANDOM\d+$/gi.test(str)) console.log(‘true’); else console.log(‘false’); solved What will be the Regular expression for matching a constant word ending with number
You must have used the variable – sum (int datatype) earlier which is different from the inbuilt function sum() you are trying to call. Hence, it is usually not advisable to use pre-defined in-built function names for variables. 1 solved Getting the TypeError – ‘int’ object is not callable [closed]
Some questions like that should really be accompanied by the real intention behind the code. The reason is that some problems should be solved completely differently. In the body of the script, the return can be used to quit the script. From another point of view, you can just remember the situation in a variable … Read more
Found the solution by using HttpClient instead of RestSharp library for downloading the content directly to browser The code snippet is as below HttpClient client = new HttpClient(); var fileName = Path.GetFileName(filePath); var fileDowloadURL = $”API URL”; var stream = await client.GetStreamAsync(fileDowloadURL).ConfigureAwait(false); // note that at this point stream only contains the header the body … Read more
— is a “decrement” operator in Java and many other languages. The reason the compiler doesn’t treat it as two – operators is that there’s a basic rule that the compiler will look for the longest sequence of consecutive characters that forms one of its “separators” or “operators”, as defined here. (> characters are handled … Read more
Your first if is the problem if((a>b)&&(a>c)) { if(a>d) return a; // what about else? } If your outer condition is true, but the inner condition is false, it will not have any return case. By the way, your method is a very convoluted way to solve this, or at least difficult to read. I … Read more
I wouldn’t rely too much on the approach you posted in your answer. Use the following function instead: function index_of_one($dec) { // maximum precision is 15 $str = str_replace(‘.’,”,sprintf(‘%.15f’, $dec)); $pos = strpos($str, ‘1’); if ($pos === false) { return -1; } return ($pos + 1); } Example: $dec1 = 1.00000000; $dec2 = 0.10000000; $dec3 … Read more
The problem wasn’t that you were giving a wrong answer, it’s that you weren’t giving the coding solution they were expecting. On this particular problem, there’s a “hint” section in the upper right hand corner. If you click on the What’s this? link. This hint shows the code you’ll need to successfully complete this step, … Read more
ContextImpl is the canonical Context implementation class. It has many ways for initializing its mResources member variable which can be then accessed with getResources(). Contexts following the usual Activity – ContextThemeWrapper – ContextWrapper inheritance path delegate getResources() to the base context. The base context is set up as ContextImpl instance when the activity is created. … Read more
It wasn’t fun to read your query, but I think the problem is here: LEFT JOIN ( SELECT max(notification_date) notification_date, client_id FROM og_ratings WHERE notification_date NOT IN ( SELECT max(notification_date) FROM og_ratings ) if you want the maximum date for every client you need to GROUP BY client_id: SELECT client_id, max(notification_date) notification_date FROM og_ratings GROUP … Read more
Promoting my comment to an answer as the OP appears to agree (and removing a spurious ) in the process): computeY <- function(x) { sqrt(1-(x-1)^2) } which at the prompt works as well: R> computeY <- function(x) { sqrt(1-(x-1)^2) } R> sapply((1:5)/10, computeY) [1] 0.435890 0.600000 0.714143 0.800000 0.866025 R> Disclaimer: No pipes were hurt … Read more
Here’s a complete and working example of your goal. main.c #include “somefile.h” int main() { somefunc(); return 0; } somefile.h #ifndef RHURAC_SOMEFILE_H #define RHURAC_SOMEFILE_H void somefunc(); #endif somefile.c #include <stdio.h> #include “somefile.h” void somefunc() { printf(“hello\n”); } example build ( gcc ) gcc main.c somefile.c -o main output $ ./main hello 3 solved Proper use … Read more
Macros are just replaced by their definition. When you #define k 1024; and write if(k==1024)… what the compiler actually sees is: if(1024; == 1024) … which doesn’t compile. The compiler doesn’t complain because sometimes you may actually want to add a semicolon (; is called semicolon, not colon, which is 🙂 to your macro. solved … Read more
You can use /^[A-Za-z0-9]{6}-\d{2}-[A-Za-z0-9]-\d{4}$/ Or shorter with the case insensitive flag: /^[A-Z0-9]{6}-\d{2}-[A-Z0-9]-\d{4}$/i solved Need JS Pattern Validation