[Solved] N-th occurence of a number in a vector

you can do it like template<class InputIterator, class T> size_t find_nth (InputIterator first, InputIterator last, const T& val,size_t count) { size_t ret=0; size_t index=0; while (first!=last) { if (*first==val) { ret++; } if(ret == count) { return index; } index++; ++first; } return -1; } int main() { vector<int> myInt={1,2,3,1,4,1,5,6}; int ret=find_nth(myInt.begin(),myInt.end(),1,3);//ret is -1 if … Read more

[Solved] android – Place imageview next to two textviews under each other

First add dependencies in your gradle file for circular image view compile ‘de.hdodenhof:circleimageview:2.1.0’ now you can use below code as per your requirement <?xml version=”1.0″ encoding=”utf-8″?> <LinearLayout xmlns:android=”http://schemas.android.com/apk/res/android” xmlns:app=”http://schemas.android.com/apk/res-auto” android:layout_width=”match_parent” android:layout_height=”match_parent” android:orientation=”vertical”> <LinearLayout android:layout_width=”match_parent” android:layout_height=”wrap_content” android:orientation=”horizontal” android:weightSum=”3″> <LinearLayout android:layout_width=”0dp” android:layout_height=”match_parent” android:layout_weight=”1″ android:gravity=”center”> <de.hdodenhof.circleimageview.CircleImageView android:id=”@+id/meal_image_order” android:layout_width=”96dp” android:layout_height=”96dp” android:src=”https://stackoverflow.com/questions/44897138/@color/colorAccent” app:civ_border_color=”@color/colorPrimaryDark” app:civ_border_width=”2dp” /> </LinearLayout> <LinearLayout android:layout_width=”0dp” android:layout_height=”match_parent” android:layout_weight=”2″ … Read more

[Solved] Variable Buffer?

You’re hitting undefined behavior for the below line result = result*num; as you’ve not initialized result. The initial value for an uninitialized automatic local variable is indeterminate. Using that invokes UB. Always initialize your local variables, like int count = 0 , result = 0 ; //0 is for illustration, use any value, but do … Read more

[Solved] How does this foo function works?

You are calling the function foo on a. That is the order since you are printing AFTER you are processing the rest of the number. Try moving the call to printf before the call to foo in foo and see if you get anything different. sum is changing because you are doing sum = sum … Read more

[Solved] Executing several actions within Before_Close

Private Sub Workbook_BeforeClose(Cancel As Boolean) Dim sh As Worksheet, lastRow As Long, lastCol As Long, emptyCells As Range Set sh = ActiveSheet lastRow = sh.Range(“A” & Rows.Count).End(xlUp).Row lastCol = sh.Cells(4, Columns.Count).End(xlToLeft).Column On Error GoTo NoBlanks Set emptyCells = sh.Range(sh.Cells(4, 1), sh.Cells(lastRow, lastCol)). _ SpecialCells(xlCellTypeBlanks) If Not emptyCells Is Nothing Then MsgBox “There are empty cells, … Read more

[Solved] How to add a subdomain pointing to IP of EC2 instance in AWS where the domain is pointing to the IP of the machine of some other hosting provider?

After trying and as commented by Dusan above, creating ‘A’ record for “sub.xyz.com” in WIX resolved the issue. solved How to add a subdomain pointing to IP of EC2 instance in AWS where the domain is pointing to the IP of the machine of some other hosting provider?

[Solved] auto redirect after no user action [duplicate]

You need javascript: <script type=”text/javascript”> setTimeout(onUserInactivity, 1000 * 120) function onUserInactivity() { window.location.href = “https://stackoverflow.com/questions/15966686/onUserInactivity.php” } </script> This will redirect the user after 2 Minutes of inactivity. If you want to make it dependend of the mouse-moving, try: <script type=”text/javascript”> inactivityTimeout = False resetTimeout() function onUserInactivity() { window.location.href = “https://stackoverflow.com/questions/15966686/onUserInactivity.php” } function resetTimeout() { clearTimeout(inactivityTimeout) … Read more

[Solved] Written Equation To Python Code [closed]

You need to group the both the expression under the division bar in parentheses: >>> ( … (.310 * .290) / .260 … / … ( … (.310 * .290) / .260 … + … ((1 – .310) * (1 – .290) / (1 – .260)) … ) … ) 0.3430943785456421 This ensures that the … Read more