[ad_1] Assuming you’re posting to /compress.py, replace def z(self): with def post(self): That’ll get you to your next problem. As an aside, you’ll probably find it easier to take smaller steps. A small step in this case would be “can I hit a handler via URL and at least get a ‘hello world’ result?”. Maybe … Read more
[ad_1] Getters and setters are used in order to prevent code outwith the class from accessing implementation details. Maybe today some piece of data is just a string, but tomorrow it has be created by joining two other strings together and also keeping a count of the number of times the string is retrieved (OK, … Read more
[ad_1] With this code you are doing linear probing index = hash(entry.key); while (!is_vacant(index)) index = next_index(index); template <class RecordType> inline std::size_t table<RecordType>::next_index(std::size_t index) const // Library facilities used: cstdlib { return ((index+1) % CAPACITY); } Say your map is nearly full and hash returns 23, then the next slots you are going to test … Read more
[ad_1] You are returning an array. The salary is in the the first position of you array. If you want to see the salary you would need to use return salary[0]; in your method. or System.out.println(calculateSalary(salary,riseRate)[0]); in the main. What you’re trying to print right now is the actual array, not a value. I am … Read more
[ad_1] I assume that the isHttps variable check is there for a reason(?) and therefore the second cast should actually be HttpURLConnection, meaning there is a typo in the question? If so the most methods used in the question are available in the parent class URLConnection without a cast, but not all. Fortunately HttpsURLConnection is … Read more
[ad_1] You could get the length of the list of items after splitting: len(my_long_string.split(‘;’)) Alternatively, count the number of semicolons and add one: my_long_string.count(‘;’) + 1 The latter is probably faster if you don’t need to know what the items are, but only how many items there are. len is a function that returns the … Read more
[ad_1] document.getElementById(“test”).innerHTML = “Who”; NOT document.getElementIdBy(“test”).innerHTML = “Who”; 0 [ad_2] solved Javascript code will not run at all
[ad_1] Here you go: jsFiddle You just needed to place the content in a <div> and add the following CSS to it. .container { width:40%; text-align:right; } 0 [ad_2] solved Setting text at right side of screen
[ad_1] Since your tuples are just repeating the same number, just use a range loop and create the tuple from scratch: for i in range(256): rgb = (i, i, i) There is no need to add up here. Alternatively, calculate i from the frame. 30 frames in a second? Divide 256 by 30 to get … Read more
[ad_1] Here is a version of your code which doesn’t break aliasing rules: class Foo { public: Foo() : userData(0L) { } long userData; }; void Destroy(Foo* pFoo) { if (–pFoo->userData <= 0) { delete pFoo; } } int main() { int i = 0; while (i < 10) { Foo* pFoo = new Foo(); … Read more
[ad_1] This can be modelled as a graph problem. Create a graph node for each row and column where there’s a monster. Connect the nodes if a monster is on that row and that column. This is a bipartite graph, and you want to do minimum vertex cover. König’s theorem shows that for bipartite graphs … Read more
[ad_1] If you’re simply looking for its index in the loop: <textarea name=”description{{ loop.index }}”> Here’s the docs. 1 [ad_2] solved How to attach counter variable on field in twig file?
[ad_1] What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ? [ad_2] solved What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ?
[ad_1] This issue was only present in the PyPI distribution of PyPDF2==2.3.0 for a couple of hours. It was fixed with release 2.3.1. See #1011 for more details I’m the maintainer of PyPDF2. I’m sorry I caused some headaches. You can update PyPDF2 via: pip install PyPDF2 –upgrade [ad_2] solved No module named ‘PyPDF2._codecs’, even … Read more
[ad_1] Remove the last word from success and assign to failure: import re success = “Today’s day is Wednesday”; failure = re.sub(r’\w+$’, ”, success) [ad_2] solved How to make sure the beginning of two strings match until the last word(s)? [closed]