For your case, you have one line of leading and one line of trailing context you care about, so grep -C1 Toronto input should do it. 0 solved Linux grep command with relevant values as output
One approach could be like below: num = 1729 sum_of_digits <- sum(as.numeric(unlist(strsplit(as.character(num), split = “”)))) rev_of_sum_of_digits <- as.numeric(paste(rev(strsplit(as.character(sum_of_digits),””)[[1]]),collapse=””)) ifelse(rev_of_sum_of_digits * sum_of_digits == num, “Magic Number!”, “Not a Magic Number!”) Hope this helps! 5 solved Magic number in R [closed]
You should be using == for comparison instead of = (which is assignment): @IBAction func buttonTouched(sender : UIButton) { var buttonTag : Int = sender.tag if let colorTouched = ButtonColor(rawValue: buttonTag) { if currentPlayer == .Computer { return } // note double equals if colorTouched == inputs[indexOfNextButtonToTouch] { … 1 solved cannot assign to value … Read more
For each element in your header or footer, whether it be an image or a text box or anything else, right click on each item and select the ‘properties’ option at the bottom of the menu. Then select the ‘visibility’ tab and change from ‘show’ to ‘show or hide based on an expression’. Click the … Read more
DEMO $(document).ready(function () { $(“.quantity-adder .add-action”).click(function () { if ($(this).hasClass(‘add-up’)) { var text = $(this).parent().parent().parent().find(“[name=quantity]”, ‘.quantity-adder’) text.val(parseInt(text.val()) + 1); } else { var text = $(this).parent().parent().parent().find(“[name=quantity]”, ‘.quantity-adder’) if (parseInt(text.val()) > 1) { text.val(parseInt(text.val()) – 1); } } }); }); I added the .parent() so that then find the proper text to increase 7 solved How … Read more
module TB; reg ***[2:0]*** a, b, c; initial begin a = 3; b = 4; $display (“a = %d, b = %d, c=%d\n”, a, b, c); c <= a + b; $display (“a = %d, b = %d, c=%d\n”, a, b, c); a <= 10; b <= 2; c = a + b; $display (“a … Read more
mutate is used to operate on data column-wise. If you want to do this rowwise one way in base R would be to use apply with margin as 1. gapFill_data <- data gapFill_data[] <- t(apply(data, 1, function(x) replace(x, x == 0, min(x[x > 0], na.rm = TRUE)))) gapFill_data # a b c d #1 1 … Read more
This should work. function createSentence(array) { if (array.length == 1) { return array[0]; } else if (array.length == 0) { return “”; } var leftSide = array.slice(0, array.length – 1).join(“, “); return leftSide + ” and ” + array[array.length – 1]; } console.log(createSentence([“dogs”, “cats”, “fish”])); console.log(createSentence([“dogs”, “cats”])); console.log(createSentence([“dogs”])); console.log(createSentence([])); 6 solved Javascript comma list but … Read more
You should be using SimpleDateFormat(“dd-MM-yyyy”). DD is for day in year, like there are 365 days in a year. 3 solved SimpleDateFormat returning incorrect day on given date [closed]
Return a promise from your config.js file. mongodb client supports promises directly, just do not pass the callback parameter and use then. config.js module.exports = (app) => { const mongo_client = require(‘mongodb’).MongoClient; const assert = require(‘assert’); const url=”mongodb://localhost:27017″; const db_name=”portfolio”; return mongo_client.connect(url).then(client => { assert.equal(null, err); console.log(‘Connection Successfully to Mongo’); return client.db(db_name); }); }; And … Read more
Unless there’s more to the picture, why not just query everything, ordered by section, to have the A-Z: SELECT * FROM Main_Section ORDER BY section … and then process the results with one loop, which could look something like this: $sections = $connect->query(“SELECT * FROM Main_Section ORDER BY section”); while ($row = $sections->fetch_array()) { echo … Read more
Consider saving all the details in a dictionary with the primary key as the name and pin & balance as secondary keys. Then, you can save it to a json file. import json accdict ={} accdict[‘Obi’] = {‘Name’:’Obi Ezeakachi’,’Pin’:1111,’Balance’: 5000} Continue for all the accounts. with open(‘accounts.json’,’w’) as f: f.write(json.dumps(accdict)) You can now manipulate this … Read more
You want to initiate the download if at least two checkboxes are checked? In that case, try using this: $(document).ready(function() { $(“#download”).click(function() { var count = 0; if ($(‘#temperature’).prop(‘checked’)) count++; if ($(‘#illuminance’).prop(‘checked’)) count++; if ($(‘#button-state’).prop(‘checked’)) count++; if (count > 1) { window.location.href=”https://api.thingspeak.com/channels/899906/feeds.csv?start=2019-11-12%2019:11:12&end=2019-11-13%2019:11:13″; } }); }); 2 solved How to make your checkbox work with your … Read more
def look_up(to_search,target): for (index , item) in enumerate(to_search): if item == target: break # break statement here will break flow of for loop else: return(-1) # when you write return statement in function function will not execute any line after it return(index) print(“This line never be printed”) # this line is below return statement which … Read more
textfile=open(‘somefile.txt’,’r’) text_list=[line.split(‘ ‘) for line in textfile] unique_words=[word for word in text_list if word not in unique_words] print(len(unique_words)) That’s the general gist of it solved how do I count unique words of text files in specific directory with Python? [closed]