it’s reason is pointers. Variable a and b is points same positions because a = b; After this code a points same memory adress with b. And all the changes and result will be same. solved equality between two arrays
Exception in thread “main” org.hibernate.InvalidMappingException: Could not parse mapping document from resource employee.hbm.xml solved Exception in thread “main” org.hibernate.InvalidMappingException: Could not parse mapping document from resource employee.hbm.xml
You need to have a backend server to do to this, it will test if the key is valid, if not it won’t download. If it is valid it will download. Here is the most basic authentication that you can do. I would recommend using a better secret key to test for validation, such as … Read more
For saving in files use \r\n. \n as new lines is viable on printstreams but not writing to files. 3 solved Java NewLine “\n” not working in save to text file [closed]
Using plain javascript, you can use the “substring” method of a string object to retrieve specific characters. Please see MDN String::substring var main = document.getElementById(“ccMain”); var text = main.innerText; console.log(“First Letter: ” + text.substring(0,1)); console.log(“Second Letter: ” + text.substring(1,2)); <div id=”ccMain”>Simple Text</div> solved Store First & Second Character value in two different veritable [closed]
You are comparing the NAMES of the two players instead of the values and the comparison for the second player should be an else if for the first if ‘ calculate and display total number of dots intTotal = intNum1 + intNum2 lblTotal.Text = intTotal.ToString() intTotal2 = intNum3 + intNum4 lblTotal2.Text = intTotal2.ToString() If intTotal … Read more
This should help you: lst = [‘apple’,’banana’,’cherry’] strings = input().split(‘,’) for x in strings: lst.remove(x) print(lst) Output: >>> apple,banana [‘cherry’] solved How to remove multiple input items from a list [closed]
So move semantics is basically doing a shallow copy from an element that is about to die (go out of scope). Say that we have object, dying_obj, that we know is about to go out of scope (and hence have its destructor called), we can change its type to an rvalue with std::move like so: … Read more
Consider the following. $(function() { $(“.slider”).change(function() { var v = $(this).val(); $(this).next(“.value”).html(v + “000000”); if ($(this).is(“#priceFrom”)) { $(“#priceTo”).attr(“min”, v).val(v).trigger(“change”); } }); }); .form-group label { width: 60px; } <link rel=”stylesheet” href=”https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css” integrity=”sha384-Vkoo8x4CGsO3+Hhxv8T/Q5PaXtkKtu6ug5TOeNV6gBiFeWPGFN9MuhOf23Q9Ifjh” crossorigin=”anonymous”> <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <div class=”form-group”> <label>FROM</label> <input type=”range” min=”2″ max=”9″ value=”2″ class=”slider” id=”priceFrom” /> <span class=”value”>2000000<span> </div> <div class=”form-group”> <label>TO</label> <input type=”range” min=”2″ … Read more
If I understand the logic correctly . . . # imports import pandas as pd from io import StringIO # sample data s1 = “””id Name score 111 Jack 2.17 112 Nick 1.11 113 Zoe 4.12″”” s2 = “””id Name score 111 Jack 2.17 112 Sick 1.10 113 Zoe 4.12 114 Jay 12.3″”” df1 = … Read more
“1 2” is not a string representing an int and therefore, it can not be parsed into an int. You need to split the such an input and then you can parse the individual elements into int values and perform the required arithmetic operation on them e.g. public class Main { public static void main(String[] … Read more
You could use enumerate to iterate over the indices and values. Then use next to stop upon finding the first non-zero value. If StopIteration was thrown, the list contained no non-zero values, so do whatever error handling you’d like there. def first_non_zero(values): try: return next(idx for idx, value in enumerate(values) if value != 0) except … Read more
The code is very inefficient because you find the thing, and then you turn around and find the thing again. So you end up looping multiple times. To make it more readable, I broke it up into parts. It also loops one time over the object to locate the items with children and the items … Read more
I wrote this before the edit, so refer to your original code to see the differences. I added comments to explain what I did. One of the problems is the lack of {} around the code after the if statements. Without them only the first statement after the if is conditional. if(newLocation == 0) cout … Read more
What does this function do? It concatenates two strings, i.e. it’s doing the same as the standard strcat function. See https://man7.org/linux/man-pages/man3/strcat.3.html Assume the input is “Hello World”. Just when the function is called, some where in memory it looks like: String1: Hello\0 ^ | s1 String2: World\0 ^ | s2 Now this part while (*s1 … Read more