[ad_1] You were almost there. you just had to specify n and return the right object at the end. matrix_a = function(n) { A = matrix(data = 0, nrow = n, ncol = n) for (i in 1:n) { for (j in 1:n) { if (i>=j) {A[i,j] = (i^2)} if (i<j) {A[i,j] = (j^2)} } … Read more
[ad_1] You don’t need inline event handlers You can use event delegation Use index to get the clicked element index in ul HTML <div class=”grid_12″> <ul id=”categories”> <li class=”filter”>Categories:</li> <li id=”ny”><a href=”#newYork”> New York</a> </li> <li id=”sc”><a href=”#spanishCities”>Spanish Cities</a> </li> <li id=”gv”><a href=”#aGlasgowViewpoint”>A Glasgow Viewpoint</a> </li> <li id=”sch”><a href=”#someChurches”>Some Churches</a> </li> <li id=”bh”><a href=”#barcelonaHighlights”>Barcelona Highlights</a> … Read more
[ad_1] Check the reference source from Microsoft here Following is the SelectMany overload being utilized public static IEnumerable<TResult> SelectMany<TSource, TCollection, TResult>(this IEnumerable<TSource> source, Func<TSource, IEnumerable<TCollection>> collectionSelector, Func<TSource, TCollection, TResult> resultSelector) { if (source == null) throw Error.ArgumentNull(“source”); if (collectionSelector == null) throw Error.ArgumentNull(“collectionSelector”); if (resultSelector == null) throw Error.ArgumentNull(“resultSelector”); return SelectManyIterator<TSource, TCollection, TResult>(source, collectionSelector, resultSelector); … Read more
[ad_1] Well the loop seems to be this one (at the end of the code): for i,j in itertools.combinations([a,b,c],2): all_diffs=alldiffs(i,j) total=count_total(i,j) zero=count_zero(all_diffs) total=np.array(total) union=map(sub,total,zero) zero=np.array(zero).tolist() union=np.array(union).tolist() union=[list(x) for x in union] sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \ for (aa, bb) in itertools.izip(zero, union)] sim_comb=sum(sim,[]) sum_of_sim=sum(sim_comb) number_sum=len(sim_comb) ave=sum_of_sim/number_sum one_ave=1-ave print one_ave One … Read more
[ad_1] Below is the modified code with Prepared Statement. First step is to connect to the database. To do that, we need to define the access details. // Define Database Credentials $servername = “localhost”; //Server Name $username = “KyleHulse”; //Username to the DB $password = “(my password)”; //Password to the DB $dbname = “csdb1082”; //Name … Read more
[ad_1] Use string.split: var combined = “user:pass”; var split = combined.Split(new[]{“:”}); var user = split[0]; var password = split[1]; 2 [ad_2] solved split user:pass to user and pass in c# [closed]
[ad_1] It is very easy… $con = mysql_connect(“servername”,”username”,”password”); mysql_select_db(“databasename”); $command = “UPDATE tuser SET point=”your value” where id=whatever”; //replace ‘your value’ with the new value and “whatever” with the user id mysql_query($command); mysql_close_connection($con); Next time don’t ask so stupid questions here… use Google [ad_2] solved How to Update one column (point) in php sql [duplicate]
[ad_1] You need to load your main.js at the end of the body tag, so the DOM has been loaded by the time your script executes. If you put it in the head (above the body), the DOM has not loaded your elements yet, so anime.js doesn’t find them. This is why the codepen works … Read more
[ad_1] If I am not mistaken, you don’t want your script to start the Animation automatically on pageload. So you simply have to remove the lase line from the code: setTimeout(function() { toggleOptions(‘.selector’); }, 100); This way, the animation is only started when you manually click on .selector button. [ad_2] solved How to stop JavaScript … Read more
[ad_1] There are two ways to look at this: Integer.toBinaryString(n) produces a string of length ceiling(log2(n)). That computation will take time that is roughly proportional to log(n). The maximum value for n is 2^31 – 1, and that computation will always take less than some fixed constant time. In fact, the question of the big … Read more
[ad_1] This answer assumes reading of the earlier question and comments so is not “code only”. qt = expand.grid(Month=c(“G”,”J”,”M”,”Q”,”V”), Year=1975:2016) query_names_vec <- apply(qt, 1, function(x) paste0(“CME/GC”, paste0( x, collapse=””) ) ) > head( query_names_vec ) [1] “CME/GCG1975” “CME/GCJ1975” “CME/GCM1975” “CME/GCQ1975” [5] “CME/GCV1975” “CME/GCG1976” 10 [ad_2] solved Loop R with Quandl as optional
[ad_1] The difference is: The Exception(String, Exception) constructor creates an Exception with an InnerException (Exception) and a message (String) The Exception(String) constructor create an Exception with only a message (String) and the InnerException is NULL You can check this information here.https://msdn.microsoft.com/en-us/library/system.exception.exception(v=vs.110).aspx Hope this helps. [ad_2] solved Difference between Exception(String) and Exception(String,Exception) [closed]
[ad_1] Fresco caches images for you. If you are offline, the images should still be displayed. You should not need to do anything. However, when the cache is cleared (e.g. when the user presses the button or when device space is low), images are obviously deleted from the cache – which is the desired behavior … Read more
[ad_1] The steps you need to do are as follows: Iterate each char of the string use fillText (or strokeText) to draw the char at the position you want Increment height for each char. Example var ctx = document.querySelector(“canvas”).getContext(“2d”), // get context of canvas str = “H E L L O”, char, i = 0, … Read more
[ad_1] Question is: if Test() in my Web App is called 10 times, in parallel, do the POST requests to the remote server are be called in parallel or in serial? They will be called in parallel. Nothing in the code would make it in a blocking way. In fact, when I have huge list … Read more