This is one way to achieve what you are looking to do: number = “12345678910” print( ‘number id {0}.{1}.{2}-{3}’.format( *[number[i:i+3] for i in range(0,len(number), 3)] ) ) #number id 123.456.789-10. There are a few problems with your code. First the first number in the “{0…}” refers to the positional argument in the format() function. In … Read more
Well, you forgot to convert to radians : public double distance(double x, double y, double x2, double y2) { // r is earth’s radius (mean radius = 6,371km) double r = 6371e3; double toMile = 0.000621371; double latDiff = (x2 – x)*(Math.PI)/180; double lonDiff = (y2 – y)*(Math.PI)/180;; // a is the square of half … Read more
Apparently type char is converted to ascii code. You have to use string to get the real number. Try this if (Char.IsDigit(c)) intChar.Push( Convert.ToInt32(c.ToString()) ); another way is to use GetNumericValue function. Since it returns double, it needs to be cast to int. if (Char.IsDigit(c)) intChar.Push( (int)Char.GetNumericValue(c) ); solved Could not push integer value in … Read more
Your content contains no ” quotes, and no text gm, so why would you expect that regex to match? FYI: Syntaxes like “foo”gm or /foo/gm are something other languages do for regex literals. Java doesn’t do that. The g flag is implied by the fact that you’re using a find() loop, and m is the … Read more
First, use split() to split the input into a list. Then, you need to test isnumeric() on every element of the list, not the whole string. Call int() to convert the list elements to integers. Finally, add the sum to counter, not counter_item. my_list = input(“Input your list.(Numbers)\n”).split() while not all(item.isnumeric() for item in my_list): … Read more
Actually, the function returns a value. Maybe you want to see it, so just print the result: #include <stdio.h> #include <cs50.h> int calcrectarea(int len,int wid){ return len*wid; } int main(){ printf(“enter length here:\n”); int x; scanf(“%d”,&x); printf(“enter width here:\n”); int y; scanf(“%d”, &y); printf(“area is: %d”, calcrectarea(x,y)); } solved The function is not returning in … Read more
What you have in your json is a List<Cast>, and the Cast class is a simple String so what you could do is get the list of Cast and then get the list[index].name to get the String In case you’d like a List<String> you should have this as json [ “Jhon”, “Anne”, “Carl” ] Then … Read more
A = [s for s in A if s.strip() != ”] or A = [s for s in A if len(s.strip()) > 0] 1 solved How to remove str. Of spaces from list [closed]
Short answer, Yes Running this type of data will out-perform CPU. Long answer, if its is ( stream-able), what I mean is that if you can have your data structured in such a way that its iterable and can be emitted one by one to some consuming end, then yes. But about the programing language … Read more
If you need such sequencing, you might reevaluate your need to use goroutines. However, the way you described the solution is correct: go first() { for { <-ch1 // do stuff ch2<-struct{}{} } }() go second() { for { <-ch2 // do stuff ch3<-struct{}{} } }() go third() { for { <-ch3 // do stuff … Read more
According to: https://en.wikipedia.org/wiki/Wikipedia:Special:Random The endpoint for a categorized random subject is: https://en.wikipedia.org/wiki/Special:RandomInCategory/ And not: https://en.wikipedia.org/wiki/Special:Random/ So you should change your url to: url = requests.get(f”https://en.wikipedia.org/wiki/Special:RandomInCategory/{topic}”) 1 solved A Random Wikipedia Article Generator
That is because the ternary operator always evaluates to a single type. You can’t “return” different types with this operator. When the compiler encounters such an expression he tries to figure out whether he can reduce the whole thing to one type. If that’s not possible you get a compile error. In your case there … Read more
If you want to check if a string i contains string j, you can do it using i in j. Then comes the part how do you want the output actually. What my approach was to go through the list1 and for each of them go though the list2 and check if element of list2 … Read more
@lily … saw your message before I left. This code will create a file. Hope this sorts you out đŸ™‚ <form action=”#” method=”post”> Number start:<br> <input type=”text” name=”num_start” value=”1″> <br> Number end:<br> <input type=”text” name=”num_end” value=”5″> <br><br> <input type=”submit” value=”Submit”> </form> <?php try{ if (isset($_POST[‘num_start’]) && isset($_POST[‘num_end’])){ $i = $_POST[‘num_start’]; $e = $_POST[‘num_end’]; while ($i … Read more
Considering what you are doing, won’t using memcached be a better option? You just store your ips as key=value pairs in memcached, with an expiry of 5 minutes. Thus your data always expires every 5 minutes. Also interaction with memcached is much easier than file-handling. 2 solved How to delete a .txt file after a … Read more