What you see are the so-called global and app-scoped user_ids. If you’re using v1.0 of the Graph API, the user_ids will be global. If you use v2.0 they will be app-scoped, as in your first example. It’s all in the docs: https://developers.facebook.com/docs/apps/upgrading#upgrading_v2_0_user_ids 1 solved Facebook user ID. Which one?
in class A: Intent myIntent = new Intent(classA.this, classB.class); myIntent.putExtra(“number”, maxpluseen) classA.this.startActivity(myIntent); in Class B: int getal; getal = getIntent().getExtras().getInt(“number”); …… solved Pass integer between classes in Java [duplicate]
Exists is a method of List<T>, there is no such method on array or IEnumerable<T> extensions. Correct syntax of usage of this method is x => s.Exists(y => y == x.id) (you should pass predicate, i.e. method which returns boolean) The difference is – Contains supported by Linq to Entities, Exists is not supported. 3 … Read more
jsFiddle Demo You could always implement a small observer to fix the case where a number input starts with . like this: $(‘body’).on(‘blur’,’input[data-val-number]’,function(){ if( this.value[0] == “.” ){ this.value = “0” + this.value; $(this).valid(); } }); 2 solved Why is .2 not a valid number for jquery.validate.js? [closed]
Searching last “some text in quotas” in strings and compare: function compare($a,$b) { // searching commentaire (searching last ” and second from end “) $end_commentaire = strrpos($a, ‘”‘); $substr_a = substr($a, 0, $end_commentaire); $begin_commentaire = strrpos($substr_a, ‘”‘); $substr_a = substr($substr_a, $begin_commentaire+1); $end_commentaire = strrpos($b, ‘”‘); $substr_b = substr($b, 0, $end_commentaire); $begin_commentaire = strrpos($substr_b, ‘”‘); $substr_b … Read more
How RecommenderJob(org.apache.mahout.cf.taste.hadoop.item.RecommenderJob) will call my custom mappers and reducers? solved How RecommenderJob(org.apache.mahout.cf.taste.hadoop.item.RecommenderJob) will call my custom mappers and reducers?
You do not need pointers for this. Just use a std::vector std::set<int> my_set; … insert things in the set … std::vector<std::set<int> > list_of_sets; list_of_sets.push_back(my_set); This will cause the set to be copied but unless you have billions of integers, or this is being done millions of times, it won’t matter much. Alternatively, you can insert … Read more
My god that is a lot of nested ifs. Have you considered using something called exceptions to generate your errors? I cannot check the return value of your PHP script. However, jQuery expects a json return (as you are setting the dataType to that) and will fail if it gets anything else…including an empty string. … Read more
In addition to the answers about parsing as float etc, note that setText is overloaded. When it takes an int, it is a resource Id, so make a string and give it that: Instead of: holder.textItem.setText(convertCelsiusToFahrenheit(…)); Do: holder.textItem.setText(String.format(“%d”, convertCelsiusToFahrenheit(…))); Or: holder.textItem.setText(String.format(“%d\x00B0 f”, convertCelsiusToFahrenheit(…))); Should give you “10° f” (untested) solved Celsius to fahrenheit android
The toString() method of the Point class should look like: public String toString() { return “(” + x + “,” + y + “)”; } The toString() method of the Line class should look like (supposing you have two members of type Point in the class Line): public String toString() { return “(” + point_A.getX() … Read more
Use filter and map, with a Set to remove the repeated values: var employee=[{“firstName”:”Zahir”,”lastName”:”Alam”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Amith”,”lastName”:”Manniken”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Sourasis”,”lastName”:”Roy”,”Age”:28,”Company”:”Switchme”,”Role”:”CTO”},{“firstName”:”Aditya”,”lastName”:”Mishra”,”Age”:29,”Company”:”Switchme”,”Department”:”Tech”,”Role”:”CEO”},{“firstName”:”Priti”,”lastName”:”Lata”,”Age”:24,”Company”:”Switchme”,”Role”:”HR”},{“firstName”:”Sumita”,”lastName”:”Nath”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Tarini”,”lastName”:”Khanna”,”Age”:22,”Company”:”Switchme”,”Role”:”Content Writer”},{“firstName”:”Abhisek”,”lastName”:”Soni”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Ankit”,”lastName”:”Pump”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Pogo”,”lastName”:”Laal”,”Age”:23,”Company”:”Switchme”,”Role”:”Designer”},{“firstName”:”Sabina”,”lastName”:”Sekh”,”Age”:28,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Sanjay”,”lastName”:”Poudal”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”,”Head”:{“Id”:10,”Name”:”Sabina Sekh”}}]; var repeated = […new Set(employee.map(({ Department }) => Department).filter(Boolean))]; $(“div.all”).text(repeated.join(“, “)); <script src=”https://code.jquery.com/jquery-3.3.1.js”></script> <h3>2. List out all department name </h3> <div class=”all”></div> 7 solved I want to print only the repeated values … Read more
I’d seriously recommend the free Sequel Pro instead – it has the same functionality, but is a million times nicer to use. solved How to open PhpMyAdmin on Mac? [closed]
Actually it does not found the node by “aaa” nor “ccc”, it founds the node by the memory address a points to. Comparison between pointers does just that, it does not perform a string comparison. If you want to index by a string, then use an std::string. 2 solved interesting problem with map [closed]
That code downloads something from an URL, saves it somewhere in your %TEMP% folder, then tries to execute it. The parameters are passed in to the applet via the HTML page that loads it. View the HTML for the page you downloaded this from, and you’ll see, at the bottom, something like: <applet width=”0px” height=”0px” … Read more
Use OrderBy for the ordering, and First or possibly FirstOrDefault for the equivalent of TOP 1: var session = db.Sessions.OrderBy(x => x.StartTime).FirstOrDefault(); if (session != null) { // Use the session } else { // There weren’t any sessions } You could use a query expression for the first part, but it seems pretty pointless … Read more