In expressions an array designator is implicitly converted to the pointer to its first element. Adding an integer to a pointer you will get again a pointer. It is so called the pointer arithmetic. Thus for example if you have an array int a[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, … Read more
there could be a better way to do this.. But this is one way of doing it. import pandas as pd def checkDates(d): if d.time().hour < 6: return d – pd.Timedelta(days=1) else: return d ls = [“12/31/2019 3:45:00 AM”, “6/30/2019 9:45:00 PM”, “6/30/2019 10:45:00 PM”, “1/1/2019 4:45:00 AM”] df = pd.DataFrame(ls, columns=[“dates”]) df[“dates”] = df[“dates”].apply(lambda … Read more
You must protect against dividing by zero. Specifically, any time the value of q may be zero. At a minimum you need to test q each time you enter your function. With the additional code you posted, if you insure q isn’t 0 before calling geoprogress, that is sufficient as well. Regardless, a test in … Read more
The problem with using a seperate row was that on a mobile device all the three buttons (in the seperate row) sat away from their relevant content. This meant it was very confusing on a mobile device to understand what the buttons took the user to, this looked like: By adding a simple <br /> … Read more
Your question is really vague. Rather than coming here asking a vague question you should provide some code snippets, explain what your have tried and what is going wrong. This will help people answer your question, and not down-vote your question to hell (like what is happening now). With that being said i’ll take a … Read more
If anyone will search answer, I did it! import math x = int(input(“How many cities? “)) a = math.factorial(x) print(“For”, x, “cities, there are”, a, “possible routes”) solved Traveling Salesman assignment
What have you tried? Here’s one possible solution: class ForDemo { public static void main(String[] args){ for(int i=1; i<11; i++){ if(i != 5){ System.out.println(“Count is: ” + i); } } } } I added a check in there: if(i != 5) which executes the code inside only if the condition is true (ie: i is … Read more
The MakeSentence(): finishes once it hits the return statement, so you have several print statements that execute after that seemingly repeated again? You could have this return a list or tuple: def MakeSentence(): #makes sentence by combining name, verb, and noun “”” (None)->List Returns a list with a random name, verb and noun “”” x … Read more
The best way is to define a variable, like this: a = “Printed text” print(a) And if you want to verify wih another string, use b = input() and verify with tis variable. if a == b: print(“Yes”) else: print(“No”) solved How do i define a printed text in python?
In Java there are lots of ways you can code to get the contents between brackets (or any two specific characters for that matter) but you sort of want to dabble with a regular expression which can be rather slow for this sort of thing especially when dealing with multiple instances of bracket pairs within … Read more
If the search on http://musicbrainz.org/ws/2/artist/? returns more than one artist, the object returns an array in results.query.results.metadata[“artist-list”].artist So, to access the data, it would be quizCountry = results.query.results.metadata[“artist-list”].artist[0].area.name; quizYear = results.query.results.metadata[“artist-list”].artist[0][“life-span”].begin.match(/\d{4}/); quizBand = results.query.results.metadata[“artist-list”].artist[0].name; So, you’ll need to check if results.query.results.metadata[“artist-list”].count > 1 and change your code appropriately e.g. if(results.query.results.metadata[“artist-list”].count > 1) { quizCountry = … Read more
Yes, you can use server-side Java code as a mediator. Use JavaScript to POST data to an HttpServlet, via JavaScript’s XMLHttpRequest object. Then handle the data in your servlet. Once you’ve done your DB business, you can send a “All done!” response back, to be handled by your JS. I suggest reading up on the … Read more
try this, import sys for j in range (0,n): for i in range (n-j+1): sys.stdout.write(‘ ‘); for k in range (j+1): sys.stdout.write(‘#’); print() 1 solved python 3.6.1 ‘FOR LOOP’
You need CookieCollection to get cookies and set UseCookie to true in HtmlWeb. CookieCollection cookieCollection = null; var web = new HtmlWeb { //AutoDetectEncoding = true, UseCookies = true, CacheOnly = false, PreRequest = request => { if (cookieCollection != null && cookieCollection.Count > 0) request.CookieContainer.Add(cookieCollection); return true; }, PostResponse = (request, response) => { … Read more
You could try converting double nN to a string and see if your String line contains it with if statement: if (line.contains(Double.toString(nN))) { code… } solved Check if certain numbers are in a string