Connection reset.*?\\b([^ .]+\\.xls)\\b You can use this regex.Grab the group 1 or capture 1.See demo. https://regex101.com/r/bN8dL3/3 1 solved How to search a particular string in a file using pattern matcher in java
What’s the point of “s”? It’s a variable of the type that you’ve just checked for, which you often want to use. Your example is an unfortunate one as Console.WriteLine accepts object as well… but suppose you wanted to print out the length of the string. Here’s a complete example without pattern matching: public void … Read more
Either isn’t simply a union of types; it’s a tagged union, which means every value has to explicitly specify which “side” of the type the wrapped value occurs on. Here’s an example, (with a Show instance derived for your Card type): *Main> Card Hearts Jack <interactive>:3:13: error: • Couldn’t match type ‘Court’ with ‘Either Pip … Read more
If you want to avoid regular expressions altogether and need to support only that single case illustrated in your post, then this should work: def match(string, pattern): if len(string) != len(pattern): return False for s, p in zip(string, pattern): if s != p and p != ‘?’: return False return True Execution example: >>> match(‘ABC’, … Read more
(?:~~)?1(?:~~)?2(?:~~)? matches all your example strings. Is that what you meant? Explanation: (?:~~) combines two tildes into a single (non-capturing) group. ? makes that group optional. 10 solved I need a pattern in regex engine to ignore a specific set of characters(eg: “~~”) [closed]
According to your new rules, may be this helps: data1 <- data #changing some elements to test the code data1[2,8] <-2 data1[4,1] <- 1 ##The code is for the row indx <- which(t(sapply(split(data1 == pattern, row(data1)), { function(x) colSums(sapply(1:(length(x) – 3), function(i) x[seq(i, i + 3)]), na.rm = TRUE) == 4 })), arr.ind = TRUE) … Read more
This one should be the way: #(\w+)(?:[, .]|$) # matches # literally \w is a word with at least one letter (?:) is non-capturing group [, .]|$ is set of ending characters including the end of line $ For more information check out Regex101. In Java don’t forget to escape with double \\: String str … Read more
I got the solution… private void method(String txt) { Pattern pattern = Pattern.compile((“md5_id=[a-zA-Z_0-9]{5,}”)); Matcher m = pattern.matcher(txt); while (m.find()) { Log.d(“log”, m.group()); } } 1 solved get matches words by regex java
You can use \[.*?\]\{.*?\} on your example which I tested out here. This breaks into two smaller regex: \[.*?\], which is the square brackets with any chars inside. \{.*?\}, which is the curly brackets with any chars inside. Both of these are using a non-greedy .* inside the brackets. This way if there is more … Read more
In Java there are lots of ways you can code to get the contents between brackets (or any two specific characters for that matter) but you sort of want to dabble with a regular expression which can be rather slow for this sort of thing especially when dealing with multiple instances of bracket pairs within … Read more