[ad_1] Use lengths of the lists to terminate the recursion. In this example implementation, if length of either of the lists is 0, we have either mapped it all, or it is an empty list to begin with, thus we terminate the recursion. Also worth noting that l1[1:] is the slice of the list we … Read more
[ad_1] Instead of printing result[0],result[1],result[2],first check the size of vector result and if it is ‘0’ then return 0 or whatever is given and otherwise return result vector. [ad_2] solved Core dumped while using vector
[ad_1] Those 500 classes should have derived from a common abstract base class, where you would add the stub. [ad_2] solved Change 500+ Classes that consumes an interface that I just modified
[ad_1] Finally I realized what was the problem it was in displaying the encrypted and decrypted strings when I tried result=QString::fromLocal8Bit((char*)ciphertext); it worked fine and showed the original text. [ad_2] solved Wrong Encryption (QT c++ OpenSSL AES 256 CBC)
[ad_1] What you will need to use to do this is the System.Dynamic.ExpandoObject class. using System; using System.Dynamic; using System.Collections.Generic; public class Program { public static void Main() { var args = “–Bar –Foo MyStuff”.Split(); var parsedArgs = ParseArgs(args); Console.WriteLine(parsedArgs.Foo); //Writes “MyStuff” Console.WriteLine(parsedArgs.Bar); //Writes true; Console.WriteLine(parsedArgs.NotDefined); //Throws run time exception. } public static dynamic ParseArgs(string[] … Read more
[ad_1] You can use the partition method for this. It’s part of the built-in str type. >>> help(str.partition) partition(self, sep, /) Partition the string into three parts using the given separator. This will search for the separator in the string. If the separator is found, returns a 3-tuple containing the part before the separator, the … Read more
[ad_1] Assuming a MySQL database, why not simply have a TIMESTAMP column on your database: http://dev.mysql.com/doc/refman/5.6/en/timestamp-initialization.html and leave MySQL to populate it for you 2 [ad_2] solved Store bids in microtime [closed]
[ad_1] import pandas as pd, numpy as np # filter results by showing records that meet condition # sample df d = {‘SBP’: [111, 100], ‘DBP’: [81, 40], ‘HEARTRATE’:[1,50]} df = pd.DataFrame(data=d) df # if an alert is found, prints alert, else normal if len(df[(df[ ‘SBP’ ] > 110) & (df[ ‘DBP’ ] > 80) … Read more
[ad_1] There is actually a reasonably easy way of doing this. You can fetch all the channels from a guild and then loop through them. You then pick out all the channels which are of type category and get the size of their children property. Below is some code which will help you go in … Read more
[ad_1] It gives ~10^-16 something very close to zero you can console.log(Math.sin(Math.PI).toFixed(2)) [ad_2] solved Math.sin() behaving strangely in javascript [closed]
[ad_1] After you click the first button a new DOM is loaded, so click on the second (and third …) will end with StaleElementReferenceException. You need to get all the href values first and then try them one by one. Just tried on web bbc.com with this code: package navi; import java.util.ArrayList; import java.util.List; import … Read more
[ad_1] I would recommend using SharedPreferences to achieve this. They are meant to be to retain app state when run at a later time. In your case, you need to use putBoolean() method from SharedPreferences.Editor something like this: “Start” button onClickListener: SharedPreferences sharedPref = context.getSharedPreferences(context, MODE_PRIVATE); SharedPreferences.Editor editor = sharedPref.editor(); editor.putBoolean(“isJobRunning”,”true”); editor.commit(); In the same … Read more
[ad_1] Use the index of the character you want, so: a[0] For a complete answer: char getFirstChar(string inString, char defaultChar) { if (string.IsNullOrEmpty(inString)) return defaultChar; return inString[0]; } 1 [ad_2] solved How can I get the first character of a string? [duplicate]
[ad_1] As @aspend mentioned above you will get result just by using .flatten property of array class: <% str = “Hello my name is __john__ and i am __30__ years old”%> <%=str.scan(/__(.*?)__/).flatten %> Preview: 2 [ad_2] solved How to matche all the words from a string that starts and ends with double underscore in rails … Read more
[ad_1] If you’re trying to use findViewById in Fragment, first of all make sure you’re using onCreateView() and you’re returning the view at the end. See the differences in here: Difference and uses of onCreate(), onCreateView() and onActivityCreated() in fragments Here is an example for that: @Override public View onCreateView(LayoutInflater inflater, ViewGroup parent, Bundle savedInstanceState) … Read more