[Solved] C++ templates to Java Generics [closed]
[ad_1] Not at all. Java generics are less powerful compared to C++ templates. There is simply no way to express such a template in Java. 15 [ad_2] solved C++ templates to Java Generics [closed]
[ad_1] Not at all. Java generics are less powerful compared to C++ templates. There is simply no way to express such a template in Java. 15 [ad_2] solved C++ templates to Java Generics [closed]
[ad_1] The problem is in foreach templated function: first parameter can be a pointer to the array or it can just be static array array with undefined size second parameter can be a function pointer or a reference to the function (which should accept constant element of same type as array elements by reference, as … Read more
[ad_1] You could implement the first one with a default parameter: int A(int a, int b, int c, int d = 0) { // stuff } 3 [ad_2] solved C++ avoid writing two similar functions
[ad_1] It seems you want to pass a non-type template parameter, and more specifically, a pointer-to-member. For what you want, you have to user: template<ObjectType gameclass::* ptr> struct foo // … Note that will allow you to access the member of an object only if you have a pointer to that object. You can have … Read more
[ad_1] The original poster failed to actually post the code that was causing the problem. He has since edited my post with the correct code that demonstrates the problem. The code that demonstrates the problem follows: template <class R, typename B=int> class AVectorContainer { public: AVectorContainer() {} typedef R* ptr_Type; typedef const B & const_ref_Type; … Read more
[ad_1] The problem is int8_t is implemented as char. The implementation of the input stream is working like this: char x; std::string inputString = “abc”; std::istringstream is(inputString); is >> x; std::cout << x; The result is ‘a’, because for char the input stream is read char for char. To solve the problem, provide a specialised … Read more
[ad_1] In your code, you declare to return type T, but the variable you return has type list<T>. I’d suggest to develop your code with concrete types (and without templates) first; you can exchange the concrete type with placeholders afterwards, but concrete types give a better idea what actually happens. Try the following code and … Read more
[ad_1] This looks like a problem where code is not necessarily the solution, maybe you should use photoshop to glue 2 images together in this way. It would be a lot easier, and obviously much less buggy. If you really want to do this in-app, you are going to have to at least get some … Read more
[ad_1] Is there any way to compile this code such as inheritance, overload…? No. Not as you are trying to at least. mylist *y = new mylist(); //….how? isn’t valid since you have to provide a template parameter for mylist like mylist<MyType>. You’re probably looking for template specializations. 6 [ad_2] solved c++ use template class … Read more
[ad_1] The template arguments are placeholders, their scope is limited to that one declaration alone. Therefore, the T in template<class T> struct Alloc { }; is not connected to the T in template<class T> using Vec = vector<T, Alloc<T>>; similarly as you could use the same parameter name in different function declarations. 3 [ad_2] solved … Read more
[ad_1] Templates cannot be compiled like any other source file. Both interface and implementation should live in the header file (although some split them in .hpp files for interface and .ipp files for implementation, and then include the .ipp file at the end of the .hpp file). How would the compiler know what classes to … Read more
[ad_1] I have looked up and down, tried all the different and various ways of being able to solve this problem,Then I find the Solution. You can use the text-overflow Property in CSS to not write long titles in multiple lines. Use this Style : th.fit { white-space: nowrap; overflow: hidden; text-overflow: ellipsis; } Check … Read more
[ad_1] It’s quite common, actually almost all templates have certain requirements towards their arguments. Those are usually implicitly clear from how the template parameter is used, but you can improve the error messages by using type traits. In C++11, they are available from the standard library via #include <type_traits>, otherwise look into Boost.TypeTraits. With C++11, … Read more
[ad_1] “undefined reference to” NOT the template constructor,but the constructor of the class I’m trying to use the template with [ad_2] solved “undefined reference to” NOT the template constructor,but the constructor of the class I’m trying to use the template with
[ad_1] Option #1 #include <cstddef> #include <type_traits> #include <utility> #include <tuple> template <typename A, typename B> struct merge_tuples { static_assert(std::tuple_size<A>::value == std::tuple_size<B>::value, “!”); template <std::size_t… Is> static auto merge(std::index_sequence<Is…>) noexcept -> std::tuple<typename std::decay<decltype(std::declval<typename std::tuple_element<Is, A>::type>() + std::declval<typename std::tuple_element<Is, B>::type>()) >::type…>; using type = decltype(merge(std::make_index_sequence<std::tuple_size<A>::value>{})); }; DEMO Option #2 #include <type_traits> #include <utility> template <typename A, … Read more