Those two lines in your main function shadow your global variable declaration: optQuit := getopt.BoolLong(“quit”, 0, “Help”) optRun := getopt.BoolLong(“run”, ‘r’, “Help”) If you only use them, to get a nice usage, why not create a usage function yourself? If you insist on using getopt just to create a usage, do _ = getopt.BoolLong(“quit”, 0, … Read more
From the NSUserDefaults Class Reference: A default object must be a property list, that is, an instance of (or for collections a combination of instances of): NSData, NSString, NSNumber, NSDate, NSArray, or NSDictionary. If you want to store any other type of object, you should typically archive it to create an instance of NSData. The … Read more
It makes elmtadress an alias for struct elmt *. If you use this, you can type: elmtadress myStruct; instead of struct slmt *myStruct; Read more here: http://www.tutorialspoint.com/cprogramming/c_typedef.htm 1 solved What is the meaning of this typedef struct in C language? [closed]
I feel like we’ve given the search for pre-existing solutions its due diligence. Given that “<=” is assignment in some languages (e.g., Verilog) we can quite intuitively introduce: value_struct_instance<<=’field’, value as the Pythonic form of value_struct_instance.field = value Here is an updated example for instructive purposes: # Python doesn’t support copy-on-assignment, so we must use … Read more
you shall not free() instances that have not been allocated through malloc(), though it’s unclear how the instance has been allocated before being given to that function, though it’s unlikely it’s been malloc()ed as this is C++, which leads me to 2. ; you should not free() C++ objects, but instead call delete that will … Read more
In this statement struct sockaddr *ai_addr; there is used so-called elaborated type specifier. This statement does two things. First of all it declares type name sockaddr and declares a pointer of this type. To declare a pointer to a structure there is no need that the structure would be defined that is that it would … Read more
A matrix is an array of arrays, so you could use a pointer to a pointer to mystruct, as well and the number of rows and columns so the function knows how to handle it: void myfunction(mystruct** matrix, int rows, int columns) { // Your logic goes here… } 3 solved Passing a matrix of … Read more
The problem is that you define a type (account) in the class. account is a type so you should not declare it in the class : struct account { std::string name; float money; short pin; }; and then, the class becomes : class CBank { public: CBank(); account acc; std::vector<account> add; }; and the main … Read more
Well the second one is nonsense in many way. You don’t want to do that. The second if used only – then think how would you pass it to the function. There are innumerous problem that you would face – one of them shown below :- void fun( myStructure z){ printf(“%d\n”, z.id); } myStructure zz; … Read more
The reason this outputs 4 has to do with the size of each type and struct padding and alignment. On my system, sizeof(unsigned int) is 4, sizeof(long int) is 8, and sizeof(struct test) is 24. So to ensure that the 64-bit field lies on a 64-bit boundary, the structure is physically laid out like this: … Read more
I found the solution. You have to add a closure and then use it when calling the function. func getData(symbol: String, completion: @escaping (Stock) -> Void) { let apiURL = “https://cloud.iexapis.com/stable/stock/\(symbol)/quote?token=\(secretToken)” let url = URL(string: apiURL)! URLSession.shared.dataTask(with: url) { (data, response, err) in guard let data = data else { return } do { let … Read more
Here are some issues I found. 1. Don’t use struct when referring to variable types. Incorrect: void getTime(struct Time *time) Correct: void getTime(Time * time) Pass by reference, not pointer:void getTime(Time& time) You need to use either . syntax to refer to members or ->:cin >> time->hours; // if passed by pointer.cin >> time.hours; // … Read more
If you have control of your input format, i.e. you can guarantee it will always be something like 0xabc, then you can try: const char input[] = “0xabc”; uint32_t tmp; sscanf(input, “0x%x”, &tmp); struct cmd cmdid; cmdid.a = (tmp & 0xFF0000U) >> 16; cmdid.b = (tmp & 0xFF00U) >> 8; cmdid.c = (tmp & 0xFFU); … Read more
It’s C++: don’t use malloc, use new don’t use plain arrays, use std::vector or std::array don’t use raw pointers, use std::unique_ptr 1 solved Failed to allocate an array of pointers to a struct
If you want to keep it packed in some type you better use enum instead: enum RandomMessage: String, CaseIterable { case message1 = “Message1” case message2 = “Message2” case message3 = “Message3” case message4 = “Message4” case message5 = “Message5” static var get: String { return allCases.randomElement()!.rawValue } } This way you will guarantee that … Read more