[ad_1] Use a wordwrap function: <? $text = “kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk”; $newtext = wordwrap($text, 20, “<br />\n”); ?> 1 [ad_2] solved String to get string to second line? [duplicate]
[ad_1] Why do you include so many unneeded header files? These should be sufficient: #include <iostream> #include <string> #include <stdio.h> #include <stdlib.h> #include <time.h> You should avoid using namespace std;. If you don’t want to type std::string every time especially you can use using std::string; using std::string; using std::cout; using std::endl; Now to your function. … Read more
[ad_1] For the second one, you could look for a line that starts with “10”, then “something” and then 9 consecutive spaces. After the spaces is what you need to capture. The regex is ^10.+\s{9}(.*) 1 [ad_2] solved PHP – Find number in a string
[ad_1] if you alltime wants to show 1st and last 3 letters and in between some * than you can do it by sub-string and string concat method $str = “hello this is my password”; echo substr($str,0,3).”******”.substr($str,(strlen($str))-3,3); 1 [ad_2] solved How can I hide/replace a part of a string in PHP? [duplicate]
[ad_1] You have mistake in both sumOfEvenPlaces() and sumOfOddPlaces() methods. In sumOfEvenPlaces(long number) you have to change number %= 10; to number /= 10; You can only skip a digit using number / 10 not by number % 10 And in both functions change while (number % 10 != 0 || number / 10 != … Read more
[ad_1] try this def reverse_besides_number(l): # convert number in list to a dict # record the index d = {k: v for k, v in enumerate(l) if v.isdigit()} # record the character in list c = [i for i in l if not i.isdigit()] c.reverse() # insert for key, value in d.items(): c.insert(key, value) return … Read more
[ad_1] You are passing two arguments as String type, “20”, “10”: int myBmi = myBmiCal(“20”, “10”); But it should be int type: int myBmi = myBmiCal(20, 10); “” – it means just empty String in Java. “20” – it means String with value 20. “20” and 20 are different types in Java. Here is documentation … Read more
[ad_1] string.Format(“[{0}]”, string.Join(“,”, array.Select(i => “{” + i.ToString() + “}”))); [ad_2] solved How to build an array of objects and then convert the whole array to an string [closed]
[ad_1] This routine returns -1, 0, or 1 as values, so you can do something like this: String first; String second; … assign first and second if( first.compareToIgnoreCase(second) < 0) { // second is less than first… } else if first.compareToIgnoreCase(second) == 0) { // second is same as first… } else if first.compareToIgnoreCase(second) > … Read more
[ad_1] This is a very weird way to handle data. I would use a nested dicts: exampleDictionary = {‘thing on ground’: {‘backpack’: {‘tea’: ‘Earl Grey’}}} print exampleDictionary[‘thing on ground’] print exampleDictionary[‘thing on ground’][‘backpack’] print exampleDictionary[‘thing on ground’][‘backpack’][‘tea’] Outputs: {‘backpack’: {‘tea’: ‘Earl Grey’}} {‘tea’: ‘Earl Grey’} Earl Grey 2 [ad_2] solved Python. Converting string into directory … Read more
[ad_1] Assuming that the request for a “random” allocation of letters to arrays is for a pseudo-random (or, perhaps, a superficially arbitrary) allocation that is therefore reversible, one technique to do this would be to essentially use a transposition cipher. The algorithm would then be something like: Run the transposition cipher on the input text. … Read more
[ad_1] Always use equals since == doesn’t always work. Even though objects are the same in memory it may be stored in different places, and == checks for objects identity and not equality. [ad_2] solved Checking if strings are equal in java using == [duplicate]
[ad_1] You can say: tax2 = int( input(“How Much Will You Tax Per Person In Dollars? “) ) If you’re sure the input won’t contain decimals. If you’re not sure, and want to keep the decimal value, you could use: tax2 = float( input(“How Much Will You Tax Per Person In Dollars? “) ) Or … Read more
[ad_1] You just need to group your array elements and use map to join your keys using joined(separator: “, “): extension Array { func group(of n: IndexDistance) -> Array<Array> { return stride(from: 0, to: count, by: n) .map { Array(self[$0..<Swift.min($0+n, count)]) } } } Testing: let dic = [“f”:1,”a”:1,”b”:1,”c”:1,”d”:1,”e”:1, “g”: 1] let arr = Array(dic.keys).group(of: … Read more
[ad_1] Errors were not detected because either the warnings of your compiler are not enabled, being ignored or need for a better compiler. This code does not allocate space for data being read. Simplest solution: used fixed size arrays and limit user input. #include <stdio.h> int main(void) { char colorOne[80+1]; printf(“How many bands??\n”); … printf(“\n\nEnter … Read more