[ad_1] You could try something like this, test = (condition)?”somevalue”:”somevalue” Basically, I am using ternary operators. If the condition is true, then the value after ‘?‘ gets assigned to test. Otherwise, test will equal to the value after ‘:‘. 🙂 4 [ad_2] solved string assignment with or operator [closed]
[ad_1] There is no built-in functionality to do that, since you throw away information (the length of each string). So that information have to be stored somewhere. You could use a TStringList descendant : Interface TMyStrings = class(TStringList) protected function GetTextStr: string; override; end; Implementation { TMyStrings } function TMyStrings.GetTextStr: string; var Element: String; begin … Read more
[ad_1] You can achieve this by extracting each bits one by one, like this str[i] = (char)( (num % 10) – 48 ) 48 has to be subtracted because an integer value changing to character goes through an ASCII conversion. Keeping the above line in a loop, that would run for each digit in the … Read more
[ad_1] You can try this: str = str.replace(/\w*\(\d*\)/g, function () {return ‘(‘ + arguments[0] + ‘)’;}); A live demo at jsFiddle EDIT Since you’ve changed the conditions, the task can’t be done by Regular Expressions. I’ve put an example, how you can do this, at jsFiddle. As a side effect, this snippet also detects possible … Read more
[ad_1] I tried to run that and my outputs for r1 and r2 are qwdaweqwe asdas–sd (two spaces) and basically it is what the code should be doing. But if I get your intention right, you want to work with those empty strings. Then you should be feeding your function with different numbers, because array … Read more
[ad_1] There are cases when both isalpha and isdigit returns False, but isalnum returns True. So isalnum is not just a combination of the other two. >>> ‘a1’.isalpha(), ‘a1’.isdigit(), ‘a1’.isalnum() (False, False, True) [ad_2] solved Python: is isalnum() the same as isalpha with isdigit?
[ad_1] You could use a simple list comprehension here : S = [x[0] for x in content_E.most_common(3)] or, if you need to generate from E, then: S = [x[0] for x in E] 0 [ad_2] solved get most common keys from list
[ad_1] This is how you do it. Next code was made with Visual Studio 2010 C++ console project. First, the assembly part, pay attention to the comments, how to get the string’s address from stack, how the characters are visited, and the most important part, how the undesired chars are deleted: .386 .model flat, C … Read more
[ad_1] Your response looks like JSON, so for json response in result; JSONObject lsubObject= new JSONObject(result); String MaCID =lsubObject.getString(“MaCID”); [ad_2] solved Extracting strings out of a String response [duplicate]
[ad_1] The function for onClick attribute in XML has to be something like, public void yourFunction (View view) { //Your code } Since you didn’t add View as the argument of your function, your layout is never going to get to it, hence when you click on your button, the app crashes. You also need … Read more
[ad_1] You can simply work with regular expressions. Something like: if(vehicleId.matches(“^[A-Z]{3}\d{4}$”)) (Assuming the id contains three capital letters followed by four digits.) This will return a boolean if vehicleId, supposedly a variable holding the user’s input, is matched. 2 [ad_2] solved How can I check if a String contains X letters and Y numbers? [closed]
[ad_1] You have a question in the format “No A is within a class B”. The algorithm for such problem is bool wrong = false; while ( /* there is another A */ ) { if ( /* check if it is NOT within a class */ ) { wrong=true; break; } } if (wrong) … Read more
[ad_1] Because all your data is in the same file, your going to need to take a slightly different approach. Instead of passing in the item to fill out, I would have the function return the list of read questions: public IEnumerable<QuestionUnit> ReadQuestionFile() Then, read in a loop until you reach the end of the … Read more
[ad_1] It looks like you’re asking for interpolation. In which case sure! First you’ll want to construct a map<string, string> of the keys and values, for example: map<string, string> interpolate = { { “F”s, “a && b && c”s }, { “H”s, “p ^ 2 + w”s }, { “K”s, “H > 10 || e … Read more
[ad_1] Just use a if condition. if (i == 1) { animal = “dog”; } else if (i == 2) { animal = “cat”; } Some additional comments: I would recommend using Enum instead of String. This: for(int puzzleNum = 1; puzzleNum <= NUMANIMALS; mazeNum++) looks like an infinite loop to me, as your puzzleNum … Read more