Not only the commented line, but another will also fail if there is space in the begin of string. First line fail (to compile) because string::find_first_not_of return size_t. And construct string from two size just make no sense. Second line may fail because string::substr accept length (not end) as it’s second parameter. 1 solved c++ … Read more
Suppose you have a very large number of strings. Your algorithm will compare all the strings between them, and thats a terrible number of iterations. Radical improvement: New approach Build a map that associates a string of ordered unique vowels (e.g. “ae”) to a list of all the string found that contains exactly these unique … Read more
You may find a database command to get this kind of search. In swift, it’s easy to construct such a predicate like the following if I understand your requirement right. let multipleSearchString = “my stg l la ma” let texts = [“mystringlladm1a”, “mystr2ingllama”, “mystri2ngllama”, “mys3ringllama”] let key = multipleSearchString.compactMap{ $0 == ” ” ? nil … Read more
Make sure that Cards::init() is called and returns true before calling Cards::load. The array accessed by Cards::load will consist of three empty strings in case Cards::init() is not called, or if it returns false. 1 solved How to print std::string array with printf in c++? [closed]
Try this.. list1.append((i for i in list2 if not i in list1).next()) 0 solved compare two lists of strings and remove duplicates python
To work with elements in a cell array, use curly braces {} to retrieve the data stored at each cell index, as in the following loop: for i = 1:74 str = m{i}; % do something with string end 0 solved How to work with strings in a loop – MatLab [closed]
A couple of comments regarding your code. You should mark your fields as private and then access to them trough getter/setter. class RF { private final String nom; private final String ref; private final String num; I don’t know why they are final (I don’t hink they should) anyway. Then RF n = (RF) jComboBox1.getSelectedItem(); … Read more
class GFG { static String censor(String text, String word) { String stars = “”; for (int i = 0; i < word.length(); i++) if (word.charAt(i) != ‘ ‘){ stars += ‘#’; }else { stars += ‘ ‘; } text = text.replaceAll(word,stars); return text; } public static void main(String[] args) { String extract = “Lorem ipsum … Read more
May be you want this: import re def rna_strand_count(test_string,sub_string): test_string = test_string.replace(‘ ‘,”).upper() sub_string = sub_string.replace(‘ ‘,”).upper() first = sub_string[0] second = sub_string[1:] return {sub_string:len(re.findall(r'{0}(?={1})’.format(first,second),test_string))} print rna_strand_count(‘AAAA’,’AA’) 1 solved How to create a strand count? [closed]
This can be done with Linq and the GroupBy function pretty easily: var input = new string[] { “welcome guys”, “guys and”, “and ladies”, “ladies repeat”, “repeat welcome”, “welcome guys” }; var groups = input .GroupBy(x => x); foreach (var g in groups) { Console.WriteLine(“{0}, {1}”, g.Key, g.Count().ToString()); } welcome guys, 2 guys and, 1 … Read more
Say you have a string. string = ‘Test’ string[::-1] would reverse this into ‘tseT’ 2 solved How tomreverse a string in python? [duplicate]
Use ‘a’ and not “a”, the difference between char and string is subtle here but substantial. solved Error Operator ‘==’ cannot be applied to operands of type ‘char’ and ‘string’ [closed]
final is a reserved keyword in Java and cannot be used for variable names. Rename the final variable. 1 solved (Java) Program gives me an illegal type of expression and “;” expected even when I actually typed in a semi colon
Regex is your friend : public static void main(String[] args) throws Exception { String s1 = “jdK1TESTds3TEST”; System.out.println(s1.replaceAll(“(?i)(.*)TEST$”, “$1”)); } O/P : jdK1TESTds3 The code above replaces the last TEST (if it exists). Add (?i) modifier to make it case-insenstive. 4 solved Checking of String if it has this specific value [closed]
This is what you want: var subdividedStringArray = str.componentsSeparatedByString(“|#|”) now you have an array with 2 strings, you can access the first one with: str = subdividedStringArray[0] or: str = subdividedStringArray.first 0 solved How to delete part of string indicated after a character? [duplicate]