You can build a backtracking based solution to formulate all the possible sub-sequence for the given array. Sharing an ideone link for the same: https://ideone.com/V0gCDX all = [] def gen(A, idx = 0, cur = []): if idx >= len(A): if len(cur): all.append(cur) return gen(A, idx + 1, list(cur)) incl = list(cur) incl.append(A[idx]) gen(A, idx … Read more
assuming your input file is data.txt (Linux), you can use the system command sort: sort data.txt > output.txt 6 solved Is there a function that will quickly sort a file in C? [closed]
So from the sound of your question you are attempting to get a binary search working for your example. First, it is useful to know that a binary search only works reliably on sorted data. This is quite different than a standard linear search that will always find the value, regardless of order. As you … Read more
If I was coding this myself (rather than trying to explain a method for someone else to code this) I would do the following: Type ValueAndLevel dataValue As String dataLevel As Long End Type Dim myData() As ValueAndLevel Sub Export1() ReDim myData(1 To 1) ‘Start the process in column 1, with level being 0 Process … Read more
To read a file of “lines” in Java you can use the Files class like this: final List<String> l = Files.readAllLines(Paths.get(“/some/path/input.txt”)); This reads a file and stores each line in a List. When you have the List of String objects you can use a simple Comparator and the Collections.sortmethod. Check this code out: final List<String> … Read more
Solution without linq: int[] array1 = new int[] { 3, 5, 6, 9, 12, 14, 18, 20, 25, 28 }; int[] array2 = new int[] { 30, 32, 34, 36, 38, 40, 42, 44, 46, 48 }; int count1 = array1.Length; int count2 = array2.Length; int[] arrayResult = new int[count1 + count2]; int a = … Read more
Your code is not right: it does not do a stable partition of the array. Imagine your array is 100, 33, 333, 22, 222, 11 After the stable partitioning around the first element, it should become 33, 22, 11, 100, 333, 222 // 33, 22, and 11 in the same order as in the original … Read more
One example of such method could be: static bool IsSorted<T>(IEnumerable<T> enumerable) where T : IComparable<T> { T prev = default(T); bool prevSet = false; foreach (var item in enumerable) { if (prevSet && (prev == null || prev.CompareTo(item) > 0)) return false; prev = item; prevSet = true; } return true; } Works with most … Read more
You could reduce the array and check if the previous value is equal to the actual value. function sumSame(arrayA, arrayB) { var i, l = arrayA.length, resultA = [], resultB = []; for (i = 0; i < l; i++) { if (arrayA[i] === arrayA[i – 1]) { resultB[resultB.length – 1] += arrayB[i]; } else … Read more
I don’t know where you got data from, but you need to change it to array<int, 3> or make compareByValue a template: bool compareByValue(const array<int, 3> &a, const array<int, 3>&b) { return a[0] < b[0]; } 2 solved Sorting vector of arrays by array’s element
You can do it just by extracting the domain and using it as index for an array with the encrypted values, like so: $url=$_POST[‘url’]; $url=nl2br($url); $url=explode(“<br />”,$url); $urls = array(); foreach ($url as $value ){ $arr = explode(‘www.’,$value); $encrypt = md5($value); $urls[$arr[1]][]= $encrypt; //this line now fixed, had an error } foreach($urls as $key => … Read more
Try this: void bubble_sort(int m, int a[100000]) { int i, ok = 0, v, n = m; while ( !ok ) { ok = 1; for ( i=0; i < m-1; ++i ) { if ( *(a+i) > *(a+i+1) ) { v = *(a+i); *(a+i) = *(a+i+1); *(a+i+1) = v; ok = 0; } } … Read more
#include <stdio.h> #include <stdlib.h> struct node { int data; struct node *nextPtr; }; struct node *firstPtr = NULL; void insertioon (int d){ struct node *np, *temp, *prev = NULL; int found; np=malloc(sizeof(struct node)); np->data = d; np->nextPtr = NULL; temp=firstPtr; found=0; while ((temp != NULL) && !found) { if (temp->data <d) { prev = temp; … Read more
Create a post value and sort by it: postValue = likes + (isVetted ? 10 : 0) This makes “vetting” worth 10 likes. In other words, if 10 people like something not vetted, it will be ranked equivalently to something vetted with 0 likes. If you want to sort by date instead, then just sort … Read more
Try below code, I hope it is helpful. PHP Script. <?php // Static array. $array=array(); $array[0]=array( ‘_id’=>’5911af8209ed4456d069b1d3’, ‘title’=>’Zen M4S(Silver) 1’, ‘srp’=>1900 ); $array[1]=array( ‘_id’=>’5911af8209ed4456d069b1d2’, ‘title’=>’Zen M4S(Silver) 2’, ‘srp’=>1000 ); $array[2]=array( ‘_id’=>’5911af8209ed4456d069b1d4’, ‘title’=>’Zen M4S(Silver) 1’, ‘srp’=>1250 ); // For acending sorting. function asc_sort_json($array1,$array2){ $on = ‘srp’; if ($array1[$on] == $array2[$on]) { return 0; } return ($array1[$on] … Read more