Well try to debug your code by yourself first. Anyhow for your question Why is this happening? : It gives you error in postCode = split_address[4] because your list has 4 elements 0,1,2,3 and you are accessing the 4th element which is not present.. you don’t have the index[4] thats why it gives you error … Read more
You may find this approach verbose and overengineered. Yes, it’s. Though, I like the way the grading system is defined. class Test { public static void main(String[] args) { Map<String, Predicate<Integer>> gradingSystem = new HashMap<>(); gradingSystem.put(“A”, mark -> mark >= 90 && mark <= 100); gradingSystem.put(“B”, mark -> mark >= 80 && mark < 90); … Read more
You could try using the GenomicRanges package. library(dplyr) library(GenomicRanges) Here we load in the the example input data. (This is an inelegant way to do this — I know… but I was lazy and the sublime multiline edit made it easy.) Note: I don’t know where the “1” column means, but I kept it in … Read more
You already mentioned the solution in your question. You can use: range(0, 10) To repeat the sequence 3 times you could do: str_repeat(implode(‘ ‘,range(0, 10)).’ ‘, 3); 1 solved How to range and sequence in PHP
items = [1, 2, 3, 4, 5, 6, 7, 8, 9] for item in items: if 5 <= item <= 10: print(item) You might find Python for Beginners useful. 0 solved Search list for number in range
Swift ranges are written as 0…10, not [0…10]. [0…10] creates a single-item array. The first item in the array is a 0…10 range. Using for i in [0…10] thus iterates over that single-item array, not the range itself. The iterated value i will be of type Range or ClosedRange. To iterate over each Int in … Read more
I believe you have string array like: string[] x = { “120”, “123”, “125”, “128”, “130”, “140”, “157”, “189”, “220”, “230”, “243”, “250” }; You have to parse each item to int and then sort them, later you can get the count like: int start = 123; int end = 150; var result = x.Select(int.Parse) … Read more
a = int(input()) b = int(input()) if a > b: for number in range(a,b+1): print(number) else: for c in range(b,a+1): print(c) solved a = int(input()) b = int(input()) if a > b: for number in range(a,b+1): print(number) else: for c in range(b,a+1): print(c)
do list(range(4)). The range() function returns a generator (only produces one value at a time). You have to convert that generator to a list. 1 solved How to get a list using the range function? [closed]
First iteration, j is 0, i is 1. j is set to 0+1 == 1. Second interation, j is 1, i is 3. j is set to 1+3 == 4. Third iteration, j is 4, i is 5. j is set to 4+5 == 9. Fourth iteration, j is 9, i is 7. j is … Read more
17:30 comes after 4:00, so anything with start <= x <= end will evaluate to false, because it implies that end (4:00) is larger than start (17:30), which is never true. What you must do instead is check whether it’s past 17:30 or it’s before 4:00: import datetime now_time = datetime.datetime.now().time() start = datetime.time(17, 30) … Read more
>>> X = range(4, 7) # List of number from 4 to 6 >>> Y = range(2) # List of number from 0 to 1 >>> X [4, 5, 6] >>> Y [0, 1] >>> X[2] = Y # Stored ‘Y’ at X[2] in place of ‘6’ # X[2] is referencing Y >>> X [4, … Read more
This is a foolproof way of doing it although it is not the most efficient: from re import findall as f r=”5″ level=3 a = f(r'(\d+)?-?(\d+)’, r)[0] try: print int(a[0]) <= level <= int(a[1]) except (IndexError, ValueError): print 0 <= level <= int(a[1]) 3 solved check if value inside the range [closed]
You had some error about your indentation and element word, it was element def copy_sort(array): copy=array[:] sorted_copy=[] while len(copy)>0: minimum=0 for element in range(0,len(copy)): if copy[element] < copy[minimum]: minimum=element print(‘\nRemoving value’,copy[minimum], ‘from’,copy) sorted_copy.append(copy.pop(minimum)) return sorted_copy array=[5,3,1,2,6,4] print(‘Copy sort…\nArray:’,array) print(‘copy :’, copy_sort(array)) print(‘array’,array)` 1 solved Python sorting algorithm [closed]
This can be a start. This checks whether the number N is divisible by all numbers from 2 to int(sqrt(N)) + 1, where the int function truncates the square root of N. The all() function in python returns True if all members of a list satisfy some condition (here not zero). You should set an … Read more