[ad_1] You never define item_type_qty. All you ever do with it in your class is this: self.item_type_qty[[“Pants”,20],[“Dress”,20]] Which has no effect, since it looks like you’re trying to get a value out using weird indexes. If you meant to assign it, do it like this: self.item_type_qty = [[“Pants”,20],[“Dress”,20]] However, you’ll run into another problem with … Read more
[ad_1] In field where you have runserver write: http://127.0.0.1:8000/. Don’ forget to enable Django support in Settings/Language&Frameworks/Django and set settings file, manage script and project root. Also make shure that you choose right Python interpreter(in Django server configuration) – the one which has installed Django. The easiest way to check if you have right interpreter … Read more
[ad_1] Here’s a solution using regex if that’s what you really need. I search to see if any of your 3 substrings are present inside any given string from the list. Using https://docs.python.org/3/library/re.html as the Python regex library. import re for word in wordList: m = re.search(‘.*(ra|dec|lat).*’, word) if m: <youve matched here> [ad_2] solved … Read more
[ad_1] Use something like: new_list = [list(x) for x in FINAL_ZIPPED_LIST] [ad_2] solved Converting a list of tuples to list of list in python [duplicate]
[ad_1] You can use JMetalPy, a Python implementation for the JMetal Meta-heuristic search library. You need to define and implement how to encode your solutions and implement a fitness function. 5 [ad_2] solved How can I use Genetic Algorithms to solve non-linear optimization problems in Python? [closed]
[ad_1] In the second snippet, you pass list of countries to country_to_continent function, which according to the first example, receives a single country as a parameter. If you want to convert the whole column in your Dataframe, try instead: print(df[“country”].apply(lambda x: country_to_continent(x))) [ad_2] solved country convert to continent
[ad_1] The way you wrote it, the script will end after the first error. If you’d like to check for a string, display a message and still ask for input, you could try something like this: i = 0 total = 0 while i < 10: try: a = int(input(f’Enter a number (position {i}): ‘)) … Read more
[ad_1] def f(input1,input2): return input2[:2]+input1[2:]+’ ‘+input1[:2]+input2[2:] 2 [ad_2] solved python- swap letters between 2 strings
[ad_1] If you want to create an instance, you can just do this c=Chemise() Then call whatever method you want c.Affiche_info() What you’re currently doing is creating another class that inherits from the first [ad_2] solved Object-Oriented Programming / python3 Classes
[ad_1] Here, I tried solving it. Here is my code : bracket_string = ‘[apple]and[orange]and[apple]again!’ def find_tags(string1): start = False data=”” data_list = [] for i in string1: if i == ‘[‘: start = True if i != ‘]’ and start == True: if i != ‘[‘: data += i else: if data != ”: data_list.append(data) … Read more
[ad_1] You are increasing your total line count incrementally with each processed line. Read in the full file into a list, then process the list. While processing the list, increase a counter thats “the current lines nr” and pass it to the output function as well. The len() of your list is the total line … Read more
[ad_1] That depends on your input. If, in one call to order, x[0] is the biggest item by ranks, you get all the items in the list copied to r, and you’re calling order with exactly the same arguments again. This causes an infinite recursion and at some point (level 1000) it triggers Python’s max … Read more
[ad_1] You can use list comprehensions to do this. In this case, you can check the len of each sublist, and use that to filter out which sublists you want to keep/discard. >>> df = [[2,4,6,7],[3,4,],[2,4,6,8,12,24],[3,5,7,333,450],[4,20]] >>> [i for i in df if len(i) > 3] [[2, 4, 6, 7], [2, 4, 6, 8, 12, … Read more
[ad_1] basically a try and except is like an if and else…kinda except that when you try if it doesn’t raise an exception it excecutes the try code block but when it fails it’ll execute the except block for example a = [1,2,3,4,”hello”] for i in a: try: print(i) i + 1 except: print(“nope ” … Read more
[ad_1] This is not the most straight forward post request, if you look in developer tools or firebug you can see the formdata from a successful browser post: All that is pretty straight forward bar the fact you see some : embedded in the keys which may be a bit confusing, simpleSearchSearchForm:commandSimpleFPSearch is the key … Read more