for number in range(x, y) every number in that range represents a single int you cannot take the min of a single int. However you could append all those values to your empty list number and then take the min of that list, but even so we could just print the min of the entire … Read more
You could try solving the problem by patter matching the input string by using regular expression. Basic example for your case: import re input_str = input().lower() pattern = re.compile(r’^h+e+l{2,}o+$’) if pattern.match(input_str): print(‘YES’) else: print(‘NO’) solved find certain string in string
your code seems to lack the actual regular expression that will find the result you are looking for. If I understand correctly, your aim is to find lines starting with F, followed by ANY two characters. If this is the case, you wish to print the line to the terminal. Let me guide you: import … Read more
You should cast your variable to type int : @api.onchange(‘length’,’width’) def _compute_size_id(self): for s in self: if (s.length and s.width): s.size_wise = int(s.length )* int(s.width) 1 solved TypeError: can’t multiply sequence by non-int of type ‘unicode’
I was able to figure out something a little bit less messy by using an array, probably still not the best way of doing it but it’s the best that I could come up with. length_of_charts = int(input(“Enter how many songs you have in each of your weekly charts: “)) lengths = [3, 5, 10, … Read more
Supposing movies is a normal Python List and that you would like to get the average cost in Dollars: movies = [ (“Titanic”, 20000000), (“Dracula”, 9000000), (“James Bond”, 4500000), (“Pirates of the Caribbean: On Stranger Tides”, 379000000), (“Avengers: Age of Ultron”, 365000000), (“Avengers: Endgame”, 356000000), (“Incredibles 2”, 200000000) ] totalCost = 0 totalMovies = 0 … Read more
Your return statements and indentation are messed up: def tag_count(string_list): count=0 for string in string_list: if string.endswith(‘>’) and string.startswith(‘<‘): count += 1 return count print (tag_count([“test”,”<item>”,”test”])) 1 solved Code returns invalid syntax [closed]
No need for regex here, you can just split the text on \n and : , i.e..: text = “””It sent a notice of delivery of goods: UserName1 Sent a notice of delivery of the goods: User is not found, UserName2 It sent a notice of receipt of the goods: UserName1 It sent a notice … Read more
You can use: maketrans–which allows creation of a translation table translate–applies translation table from maketrans to a string Code def encrypt(infile, outfile, translation): ”’ Encrypts by applying translation map to characters in file infile. ”’ # Create translation table table=””.maketrans(translation) # Apply table to all characters in input file # and write to new output … Read more
You need to sort first, then call dict to convert sorted tuple: dict( sorted(ROOM_CATEGORIES, reverse=True) ) solved Dictionaries in specific format
You can use params in requests to use arguments in url import requests data = [“AAPL”, “SQ”, “PLTR”] data_str = “,”.join(data) url = “https://stocknewsapi.com/api/v1” payload = { “tickers”: data_str, “items”: 50, “date”: “last7days”, “token”: “myapikey”, } response = requests.get(url, params=payload) Eventually you can use string formatting with {} and .format(data_str) data_str = “,”.join(data) url = … Read more
This will give you filtered dataframe with all the columns where Region is Europe and Purchased Bike is Yes agestock = pd.DataFrame({ ‘Region’: {0: ‘Europe’, 1: ‘Europe’, 2: ‘Europe’, 3: ‘APAC’, 4: ‘US’}, ‘Age’: {0: 36, 1: 43, 2: 48, 3: 33, 4: 43}, ‘Purchased Bike’: {0: ‘Yes’, 1: ‘Yes’, 2: ‘Yes’, 3: ‘No’, 4: … Read more
It is because you set y_2 to be the same list as y. That list is an object, and you created two references to that object. If you want to create an independent copy of the list you could use y_2 = list(y), or use the copy module in more complicated cases. Btw please just … Read more
You can almost triple the speed by using pygame.surfarray. But I don’t thing you actually want to have a list of the pixels. Please post a new question with you underling problem, as @hop suggested. def load(screen): return pygame.surfarray.pixels2d(screen).tolist() solved Efficient loading of Pygamescreens to 2D-lists
You could sort the list of dictionaries by the price reversed and then use slicing notation to return the top results. from operator import itemgetter top = 3 data = [{“name”: “bread”, “price”: 100}, {“name”: “wine”, “price”: 138}, {“name”: “meat”, “price”: 15}, {“name”: “water”, “price”: 1}, {“name”: “fish”, “price”: 10}] print(sorted(data, key=itemgetter(‘price’), reverse=True)[:top]) Output: [{‘name’: … Read more